Skip to main content
Super TutorResources
Chapter 6 of 8
QuestionsNotesFlashcardsSummaryFormulasQuizConceptsSyllabusPlan
Important Questions

Measuring Space Perimeter and Area

CBSE · Class 9 · Mathematics

Most important questions from Measuring Space Perimeter and Area for CBSE Class 9 Mathematics board exam 2026. MCQs, short answer, and long answer questions with marks.

76 questions84 flashcards5 concepts

Interactive on Super Tutor

Studying Measuring Space Perimeter and Area? Get the full interactive chapter.

Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for important questions and more.

Try Super Tutor — Free

1,000+ Class 9 students started this chapter today

76 Questions·
multiple choicemultiple correctnumerical

Sample Questions

1multiple choice
3 marks

A cyclic quadrilateral has side lengths 5 cm, 5 cm, 6 cm, and 6 cm. What is its area using Brahmagupta's formula?

Show answer

30 cm²

Step 1: Find the semi-perimeter: s = 1/2(5 + 5 + 6 + 6) = 11 cm. Step 2: Apply Brahmagupta's formula. Step 3: Area = √((11-5)(11-5)(11-6)(11-6)) = √(6 × 6 × 5 × 5) = √900 = 30 cm².

2multiple choice
3 marks

A rectangle has length 9 cm and width 12 cm. What area is obtained by Brahmagupta's formula for this cyclic quadrilateral?

Show answer

108 cm²

Step 1: For a rectangle with sides 9 cm, 9 cm, 12 cm, 12 cm, the semi-perimeter is s = 1/2(9 + 9 + 12 + 12) = 21 cm. Step 2: Apply Brahmagupta's formula. Step 3: Area = √((21-9)(21-9)(21-12)(21-12)) = √(12 × 12 × 9 × 9) = √11664 = 108 cm².

3multiple choice
3 marks

A cyclic quadrilateral has side lengths 7 cm, 8 cm, 9 cm, and 10 cm. What is its area using Brahmagupta's formula?

Show answer

36√5 cm²

Step 1: Find s = 1/2(7 + 8 + 9 + 10) = 17 cm. Step 2: Substitute into Brahmagupta's formula. Step 3: Area = √((17-7)(17-8)(17-9)(17-10)) = √(10 × 9 × 8 × 7) = √5040 = 36√5 cm².

4multiple choice
3 marks

A circle has radius 14 cm. What is the area of a sector subtending 90° at the centre?

Show answer

154 cm²

Step 1: Use area of sector = πr² × θ/360. Step 2: Substitute r = 14 cm and θ = 90°. Step 3: Area = π × 196 × 90/360 = π × 49 = 154 cm² using π = 22/7.

+72 more questions available

Practice All

Frequently Asked Questions

What are the important topics in Measuring Space Perimeter and Area for CBSE Class 9 Mathematics?
Measuring Space Perimeter and Area covers several key topics that are frequently asked in CBSE Class 9 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Measuring Space Perimeter and Area — CBSE Class 9 Mathematics?
Understand the core concepts first, then work through the 76 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many important questions are there in Measuring Space Perimeter and Area?
There are 76 practice questions available for Measuring Space Perimeter and Area. These cover multiple question types including MCQs, short answer, and long answer questions.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.

More resources for Measuring Space Perimeter and Area

All 8 chapters — CBSE Class 9 Mathematics Important Questions

For serious students

Get the full Measuring Space Perimeter and Area chapter — for free.

Quizzes, flashcards, AI doubt-solver and a step-by-step study plan for CBSE Class 9 Mathematics.

Try Super Tutor Free
Try the full chapter — Free