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Surface Areas and Volumes

Gujarat Board · Class 9 · Mathematics

Practice quiz for Surface Areas and Volumes — Gujarat Board Class 9 Mathematics. MCQs and questions with answers to test your preparation.

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Quick Quiz: Surface Areas and Volumes

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1

Find the curved surface area of a right circular cone with base radius 7 cm and slant height 15 cm.

2

A sphere has radius 14 cm. What is its surface area?

3

Find the volume of a cone with base radius 6 cm and height 8 cm.

4

A hemisphere has radius 21 cm. Find its total surface area.

45 Questions·
multiple choicemultiple correct

Sample Questions

1multiple correct

Which of the following statements about cones are correct?

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The slant height can be found using l² = r² + h², Total surface area = πr(l + r), Curved surface area = πrl

Correct statements: 1) l² = r² + h² (Pythagoras theorem), 2) Total surface area = πrl + πr² = πr(l + r), 3) Curved surface area = πrl. Incorrect: Volume of cone = (1/3)πr²h (not πr²h), and cone has only one circular base.

2multiple choice

If the volume of a sphere is 4851 cm³, find its radius. (Use π = 22/7)

Show answer

10.5 cm

Volume of sphere = (4/3)πr³ = 4851. So (4/3) × (22/7) × r³ = 4851. Solving: r³ = 4851 × 3 × 7 ÷ (4 × 22) = 4851 × 21 ÷ 88 = 1157.625. Therefore r³ = 1157.625, so r = 10.5 cm. Step 1: Set up equation. Step 2: Solve for r³. Step 3: Find cube root.

3multiple choice

A cone has height 12 cm and slant height 13 cm. What is its base radius?

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5 cm

Using Pythagoras theorem: l² = r² + h². So 13² = r² + 12². Therefore 169 = r² + 144. So r² = 169 - 144 = 25. Therefore r = 5 cm. Step 1: Apply Pythagoras theorem. Step 2: Substitute known values. Step 3: Solve for r.

4multiple correct

Which of the following are correct formulas for surface areas and volumes?

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Surface area of sphere = 4πr², Volume of hemisphere = (2/3)πr³, Curved surface area of hemisphere = 2πr²

Correct formulas: Surface area of sphere = 4πr², Volume of hemisphere = (2/3)πr³, Curved surface area of hemisphere = 2πr². Incorrect: Volume of cone = (1/3)πr²h (not 1/2), Total surface area of hemisphere = 3πr² (not 2πr²).

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What are the important topics in Surface Areas and Volumes for Gujarat Board Class 9 Mathematics?
Surface Areas and Volumes covers several key topics that are frequently asked in Gujarat Board Class 9 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Surface Areas and Volumes — Gujarat Board Class 9 Mathematics?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.

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