Skip to main content
Chapter 11 of 12
Practice Quiz

Surface Areas and Volumes — Practice Quiz

Gujarat Board · Class 9 · Mathematics

Try a 4-question quiz on Surface Areas and Volumes for Gujarat Board Class 9 Mathematics: tap an answer to check it and see why.

45 questions24 flashcards5 formulas & key relations5 concepts

Interactive on Super Tutor

Studying Surface Areas and Volumes? Get the full interactive chapter.

Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for practice quiz and more.

Free trial, no card needed.

Quick Quiz: Surface Areas and Volumes

0/4

Tap an answer to check it instantly. No sign-up needed for these 4.

1

Find the curved surface area of a right circular cone with base radius 7 cm and slant height 15 cm.

2

A sphere has radius 14 cm. What is its surface area?

3

Find the volume of a cone with base radius 6 cm and height 8 cm.

4

A hemisphere has radius 21 cm. Find its total surface area.

45 Questions·
multiple choicemultiple correct

Sample Questions

1multiple correct

Which of the following statements about cones are correct?

Show answer

The slant height can be found using l² = r² + h², Total surface area = πr(l + r), Curved surface area = πrl

Correct statements: 1) l² = r² + h² (Pythagoras theorem), 2) Total surface area = πrl + πr² = πr(l + r), 3) Curved surface area = πrl. Incorrect: Volume of cone = (1/3)πr²h (not πr²h), and cone has only one circular base.

2multiple choice

If the volume of a sphere is 4851 cm³, find its radius. (Use π = 22/7)

Show answer

10.5 cm

Volume of sphere = (4/3)πr³ = 4851. So (4/3) × (22/7) × r³ = 4851. Solving: r³ = 4851 × 3 × 7 ÷ (4 × 22) = 4851 × 21 ÷ 88 = 1157.625. Therefore r³ = 1157.625, so r = 10.5 cm. Step 1: Set up equation. Step 2: Solve for r³. Step 3: Find cube root.

3multiple choice

A cone has height 12 cm and slant height 13 cm. What is its base radius?

Show answer

5 cm

Using Pythagoras theorem: l² = r² + h². So 13² = r² + 12². Therefore 169 = r² + 144. So r² = 169 - 144 = 25. Therefore r = 5 cm. Step 1: Apply Pythagoras theorem. Step 2: Substitute known values. Step 3: Solve for r.

4multiple correct

Which of the following are correct formulas for surface areas and volumes?

Show answer

Surface area of sphere = 4πr², Volume of hemisphere = (2/3)πr³, Curved surface area of hemisphere = 2πr²

Correct formulas: Surface area of sphere = 4πr², Volume of hemisphere = (2/3)πr³, Curved surface area of hemisphere = 2πr². Incorrect: Volume of cone = (1/3)πr²h (not 1/2), Total surface area of hemisphere = 3πr² (not 2πr²).

+41 more questions on Surface Areas and Volumes (Gujarat Board Class 9 Mathematics)

Practise All

Frequently Asked Questions

What are the important topics in Surface Areas and Volumes for Gujarat Board Class 9 Mathematics?
Key topics in Surface Areas and Volumes include Surface Area of Right Circular Cone, Surface Area of Sphere and Hemisphere, Volume of Right Circular Cone, Volume of Sphere and Hemisphere. Study these first, then practise questions on each for Class 9 exams.
How many practice questions are there for Surface Areas and Volumes?
There are 45 questions on Surface Areas and Volumes. Try the 4-question sample quiz on this page first; each answer shows an explanation when you tap it.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.

For serious students

Get the full Surface Areas and Volumes chapter — start free.

Quizzes, flashcards, an AI doubt solver and a study plan for Gujarat Board Class 9 Mathematics. Free to start, no card needed.