Surface Areas and Volumes
Jharkhand Board · Class 9 · Mathematics
Most important questions from Surface Areas and Volumes for Jharkhand Board Class 9 Mathematics board exam 2026. MCQs, short answer, and long answer questions with marks.
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Which of the following are correct formulas? (Select all correct answers)
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Volume of sphere = 4/3 πr³, Curved surface area of hemisphere = 2πr², Volume of hemisphere = 2/3 πr³, Total surface area of cone = πr(l+r)
The correct formulas are: Volume of sphere = 4/3 πr³, Curved surface area of hemisphere = 2πr², Volume of hemisphere = 2/3 πr³, and Total surface area of cone = πr(l+r). The total surface area of hemisphere is 3πr², not 2πr².
A sphere has radius 7 cm. What is its surface area?
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196π cm²
Using the formula 4πr², where r = 7 cm, we get 4π × 7² = 4π × 49 = 196π cm².
What is the relationship between the slant height (l), height (h), and radius (r) of a cone?
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l² = r² + h²
By Pythagoras theorem, in a right circular cone, the slant height, height, and radius form a right triangle where l² = r² + h².
Which of the following statements about hemispheres are correct? (Select all correct answers)
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A hemisphere has two faces, A hemisphere is half of a sphere, A hemisphere has one curved face and one flat face, The volume of a hemisphere is half the volume of a sphere
A hemisphere is half of a sphere with two faces (one curved, one flat). Its volume is half that of a sphere, but its curved surface area is half the surface area of a sphere (2πr²), not equal to it.
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