Jammu & Kashmir Board Class 10 Mathematics — Flashcards for Quick Revision

A: Step 1: Break 32760 into prime factors. Step 2: 32760 = 2 × 2 × 2 × 3 × 3 × 5 × 7 × 13. Step 3: Write repeated primes using powers. Answer: 32760 = 2^3 × 3^2 × 5 × 7 × 13. Check: 2^3 = 8 and 3^2 = 9,

A: चरण 1: 32760 को अभाज्य गुणनखंडों में तोड़िए। चरण 2: 32760 = 2 × 2 × 2 × 3 × 3 × 5 × 7 × 13. चरण 3: दोहराए गए अभाज्य संख्याओं को घातों के रूप में लिखिए। उत्तर: 32760 = 2^3 × 3^2 × 5 × 7 × 13. जाँच: 2^3

A: A composite number can be written as a product of primes in only one way, except that the order of the primes may change. Example: 2 × 3 × 5 × 7 and 3 × 5 × 7 × 2 give the same factorisation. So, chan

A: Step 1: Substitute x = 2 into p(x). Step 2: p(2) = 2^2 - 3(2) - 4 Step 3: p(2) = 4 - 6 - 4 = -6 Answer: p(2) = -6

A: चरण 1: x = 2 को p(x) में रखें। चरण 2: p(2) = 2^2 - 3(2) - 4 चरण 3: p(2) = 4 - 6 - 4 = -6 उत्तर: p(2) = -6

A: Step 1: Substitute x = -1. p(-1) = (-1)^2 - 3(-1) - 4 = 1 + 3 - 4 = 0 Step 2: Substitute x = 4. p(4) = 4^2 - 3(4) - 4 = 16 - 12 - 4 = 0 Answer: p(-1) = 0 and p(4) = 0

A: Step 1: Add the equations to eliminate y. (x + 3y) + (2x - 3y) = 6 + 12 3x = 18 Step 2: Solve for x. x = 6 Step 3: Substitute x = 6 in x + 3y = 6. 6 + 3y = 6 3y = 0 y = 0 Answer: x = 6, y = 0

A: चरण 1: y को हटाने के लिए समीकरणों को जोड़ें। (x + 3y) + (2x - 3y) = 6 + 12 3x = 18 चरण 2: x के लिए हल करें। x = 6 चरण 3: x = 6 in x + 3y = 6. को प्रतिस्थापित करें 6 + 3y = 6 3y = 0 y = 0 उत्तर: x = 6,

A: Step 1: Rewrite the equations. x = 2y 3x + 4y = 20 Step 2: The lines intersect because the coefficients are not proportional in the same ratio. Step 3: Check a common solution. From x = 2y, substitute