Is Matter around us Pure? — Flashcards
Madhya Pradesh Board · Class 9 · Science
24 flashcards for Is Matter around us Pure? (Madhya Pradesh Board Class 9 Science) to test yourself on key terms and facts.
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What is the scientific definition of a pure substance?
Answer
A pure substance consists of a single type of particle. All constituent particles of that substance are the same in their chemical nature. It is a single form of matter with uniform composition throug…
Define a mixture and give two examples.
Answer
A mixture contains more than one pure substance. Components can be separated by physical methods. Examples: sea water (mixture of salt and water), soil (mixture of sand, clay, organic matter).
What is a homogeneous mixture? Give an example.
Answer
A homogeneous mixture has uniform composition throughout. All parts look the same and have the same properties. Example: salt dissolved in water, sugar solution, copper sulphate solution.
What is a heterogeneous mixture? Give two examples.
Answer
A heterogeneous mixture contains physically distinct parts with non-uniform composition. Different parts can be seen separately. Examples: mixture of oil and water, salt and iron filings, sand and wat…
Define solution, solute, and solvent with an example.
Answer
Solution: homogeneous mixture of two or more substances. Solute: component present in smaller amount (gets dissolved). Solvent: component present in larger amount (does the dissolving). Example: In su…
List four properties of a solution.
Answer
1. Homogeneous mixture 2. Particle size smaller than 1 nm 3. Particles cannot be seen with naked eyes 4. Do not scatter light beam (path not visible) 5. Cannot be separated by filtration 6. Stable (pa…
What is a saturated solution?
Answer
A saturated solution has dissolved as much solute as it can at a given temperature. No more solute can be dissolved in it at that temperature. The amount of solute present in saturated solution is cal…
Calculate the mass by mass percentage if 10g of salt is dissolved in 90g of water.
Answer
Mass by mass percentage = (Mass of solute/Mass of solution) × 100 Mass of solution = 10g + 90g = 100g Percentage = (10/100) × 100 = 10%…
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