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Pair of Linear Equations in Two Variables

Punjab Board · Class 10 · Mathematics

Flashcards for Pair of Linear Equations in Two Variables — Punjab Board Class 10 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions30 flashcards5 concepts

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A comparison of the three possible graphical representations of a pair of linear equations in two variables: intersecting lines (unique solution), parallel lines (no solution), and coincident lines (i
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30 Flashcards
Card 1Substitution Method

Solve by substitution method: x + y = 10 and x - y = 2

Answer

Step 1: From first equation, express x in terms of y: x = 10 - y Step 2: Substitute in second equation: (10 - y) - y = 2 Step 3: Simplify: 10 - 2y = 2 Step 4: Solve for y: 2y = 8, so y = 4 Step 5: Sub

Card 2Elimination Method

Solve by elimination method: 2x + 3y = 13 and 3x - 2y = 4

Answer

Step 1: Multiply first equation by 2: 4x + 6y = 26 Step 2: Multiply second equation by 3: 9x - 6y = 12 Step 3: Add equations to eliminate y: (4x + 9x) + (6y - 6y) = 26 + 12 Step 4: Simplify: 13x = 38,

Card 3Method Selection

When should you use the substitution method instead of elimination method?

Answer

Use substitution method when: 1. One equation is already solved for one variable (like y = 2x + 5) 2. One variable has coefficient 1 or -1 (easy to isolate) 3. Coefficients are small and don't need mu

Card 4Graphical Analysis of Lines

Determine the nature of lines: Compare ratios a₁/a₂, b₁/b₂, c₁/c₂ for equations: 2x + 3y = 7 and 4x + 6y = 15

Answer

For equations a₁x + b₁y + c₁ = 0 and a₂x + b₂y + c₂ = 0 Given: 2x + 3y - 7 = 0 and 4x + 6y - 15 = 0 Step 1: Calculate ratios: a₁/a₂ = 2/4 = 1/2 b₁/b₂ = 3/6 = 1/2 c₁/c₂ = -7/-15 = 7/15 Step 2: Compare

Card 5Substitution Method

Solve the system: 7x - 15y = 2 and x + 2y = 3

Answer

Using Substitution Method: Step 1: From second equation, isolate x: x = 3 - 2y Step 2: Substitute in first equation: 7(3 - 2y) - 15y = 2 Step 3: Expand: 21 - 14y - 15y = 2 Step 4: Combine like terms:

Card 6Word Problems

Akhila spent ₹20 total. Rides on Giant Wheel cost ₹3 each, Hoopla costs ₹4 per game. She played Hoopla half as many times as rides. Find number of rides and games.

Answer

Step 1: Define variables. Let x = number of rides, y = number of Hoopla games Step 2: Form equations: Condition 1: y = x/2 (Hoopla times = half the rides) Condition 2: 3x + 4y = 20 (total cost) Step 3

Card 7Graphical Analysis of Lines

Check if this pair has infinitely many solutions: 5x - 8y + 1 = 0 and 10x - 16y + 2 = 0

Answer

Step 1: Compare coefficients. Rewrite second equation by dividing by 2: 5x - 8y + 1 = 0 Step 2: Notice that both equations become identical when second is divided by 2. Step 3: Check ratios: a₁/a₂ = 5

Card 8Elimination Method

Solve by elimination: 3x + 4y = 10 and 2x - 2y = 2

Answer

Step 1: Make coefficients of y equal. Multiply first equation by 1 and second by 2: 3x + 4y = 10 4x - 4y = 4 Step 2: Add equations to eliminate y: (3x + 4x) + (4y - 4y) = 10 + 4 7x = 14 x = 2 Step 3:

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What are the important topics in Pair of Linear Equations in Two Variables for Punjab Board Class 10 Mathematics?
Key topics in Pair of Linear Equations in Two Variables include Complete Chapter Overview — Pair of Linear Equations in Two Variables, Pair of Linear Equations - Concept Overview, Process flowchart showing steps to convert a real-world problem into a pair of linear equations. These are the concepts Punjab Board Class 10 examiners draw on most — study them first, then practise related questions.
How to score full marks in Pair of Linear Equations in Two Variables — Punjab Board Class 10 Mathematics?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
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There are 30 flashcards for Pair of Linear Equations in Two Variables covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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