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Applications of Vector Algebra

Tamil Nadu Board · Class 12 · Mathematics

Flashcards for Applications of Vector Algebra — Tamil Nadu Board Class 12 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions24 flashcards5 concepts

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24 Flashcards
Card 1Scalar Triple Product

Calculate the scalar triple product [a, b, c] where a = i + 2j + 3k, b = 2i + j - k, c = 3i + 2j + k

Answer

Step 1: Use the determinant formula: [a, b, c] = |1 2 3| |2 1 -1| |3 2 1| Step 2: Expand along first ro

Card 2Scalar Triple Product - Volume Calculation

Find the volume of a parallelepiped with coterminus edges: a = 2i - 3j + 4k, b = i + 2j - k, c = 3i - j + 2k

Answer

Step 1: Volume = |[a, b, c]| = |a · (b × c)| Step 2: Calculate the determinant: |2 -3 4| |1 2 -1| |3 -1 2| Step 3: Expand along first row: = 2(2·2 - (-1)·(-1)) - (-3)(1·2 - (-1)·3) + 4(1·(-1

Card 3Coplanarity of Vectors

When do you use the scalar triple product formula [a, b, c] = 0 to determine coplanarity?

Answer

Use this condition to check if three vectors are coplanar (lying in the same plane). Context: Three non-zero vectors a, b, c are coplanar if and only if their scalar triple product equals zero. This

Card 4Scalar Triple Product Formula

Formula for: Calculate scalar triple product using the determinant method

Answer

For vectors a = a₁i + a₂j + a₃k, b = b₁i + b₂j + b₃k, c = c₁i + c₂j + c₃k: [a, b, c] = (a × b) · c = |a₁ a₂ a₃| |b₁ b₂ b₃| |c₁ c₂ c₃| Va

Card 5Dot Product and Perpendicularity

Prove: If a = i + 2j - 3k, b = 2i - j + 2k are perpendicular, find their dot product and verify

Answer

Step 1: Use dot product formula: a · b = a₁b₁ + a₂b₂ + a₃b₃ Step 2: Identify components: a = (1, 2, -3), b = (2, -1, 2) Step 3: Calculate: a · b = (1)(2) + (2)(-1) + (-3)(2) = 2 - 2 - 6

Card 6Vector Triple Product

Find the vector triple product: a × (b × c) where a = i - j, b = i - j - 4k, c = 3j - k

Answer

Step 1: Use the formula: a × (b × c) = (a · c)b - (a · b)c Step 2: Calculate a · c: a · c = (1)(0) + (-1)(3) + (0)(-1) = 0 - 3 + 0 = -3 Step 3: Calculate a · b: a · b = (1)(1) + (-1)(-1) + (0)(-4) =

Card 7Direction Cosines of a Line

Find the direction cosines of the line passing through points A(1, 2, 3) and B(4, 6, 9)

Answer

Step 1: Find the direction vector AB: AB = B - A = (4-1, 6-2, 9-3) = (3, 4, 6) Step 2: Calculate magnitude: |AB| = √(3² + 4² + 6²) = √(9 + 16 + 36) = √61 Step 3: Find direction cosines: l = 3/√61, m

Card 8Cartesian Equations of Lines

Write the Cartesian equation of a line passing through (2, 3, -1) and parallel to 2i + 3j - k

Answer

Step 1: Identify the given point: (x₁, y₁, z₁) = (2, 3, -1) Step 2: Identify direction ratios: (b₁, b₂, b₃) = (2, 3, -1) Step 3: Use the standard form: (x - x₁)/b₁ = (y - y₁)/b₂ = (z - z₁)/b₃ Step

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Frequently Asked Questions

What are the important topics in Applications of Vector Algebra for Tamil Nadu Board Class 12 Mathematics?
Key topics in Applications of Vector Algebra include Applications of Vector Algebra — Chapter Overview Mind Map, Mind map showing all major topics covered in the Applications of Vector Algebra chapter, Flowchart showing the two equivalent methods for computing scalar triple product. These are the concepts Tamil Nadu Board Class 12 examiners draw on most — study them first, then practise related questions.
How to score full marks in Applications of Vector Algebra — Tamil Nadu Board Class 12 Mathematics?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Applications of Vector Algebra?
There are 24 flashcards for Applications of Vector Algebra covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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