Relations — Practice Quiz
CBSE · Class 11 · Applied Mathematics
Try a 4-question quiz on Relations for CBSE Class 11 Applied Mathematics: tap an answer to check it and see why. 45 questions in the full chapter test.
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Quick Quiz: Relations
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If A = {1, 2} and B = {3, 4}, find the number of elements in A × B.
Find the values of x and y if the ordered pairs (2x + 1, y - 2) and (5, 3) are equal.
Calculate the number of subsets of A × B where A = {a, b} and B = {1, 2, 3}.
For sets P = {1, 2} and Q = {3, 4, 5}, find P × Q.
Sample Questions
If A = {1, 2, 3} and relation R = {(1,1), (2,2), (3,3)}, which properties does R satisfy?
Show answer
Reflexive, Symmetric, Transitive
Step 1: Check reflexive: (1,1), (2,2), (3,3) ∈ R, so reflexive. Step 2: Check symmetric: For each (a,b) ∈ R, (b,a) ∈ R (trivially true as all pairs are of form (a,a)). Step 3: Check transitive: For (a,b) and (b,c) in R, (a,c) ∈ R (trivially satisfied). This is the identity relation on A.
If R is a relation on set {1, 2, 3} defined by R = {(1,2), (2,3), (1,3)}, is R transitive?
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Yes
Step 1: Check transitive property: if (a,b) ∈ R and (b,c) ∈ R, then (a,c) ∈ R. Step 2: We have (1,2) ∈ R and (2,3) ∈ R. Step 3: Check if (1,3) ∈ R. Yes, (1,3) ∈ R. Step 4: No other pairs in R form a chain, so R is transitive.
Find the domain and range of relation R = {(2,4), (3,6), (4,8), (5,10)}.
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Domain = {2, 3, 4, 5}, Range = {4, 6, 8, 10}
Step 1: Domain = set of all first elements of ordered pairs. Step 2: Domain = {2, 3, 4, 5}. Step 3: Range = set of all second elements of ordered pairs. Step 4: Range = {4, 6, 8, 10}.
How many relations are possible from set A to set B if n(A) = 2 and n(B) = 3?
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64
Step 1: Number of relations from A to B = 2^(n(A) × n(B)). Step 2: n(A × B) = 2 × 3 = 6. Step 3: Number of relations = 2^6 = 64. Step 4: Each relation is a subset of A × B, and a set with 6 elements has 2^6 subsets.
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Sources & Official References
- NCERT Official — ncert.nic.in
- CBSE Academic — cbseacademic.nic.in
- CBSE Official — cbse.gov.in
- National Education Policy 2020 — education.gov.in
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