Vacation with My Nani Maa

Given: Total Seeds = 15, Seeds on the Table = 12.

Concept: Hidden Seeds = Total Seeds − Seeds on the Table

$$15 - 12 = 3$$

Hidden Seeds = 3

Given: Total Seeds = 17, Seeds on the Table = 10.

Concept: Hidden Seeds = Total Seeds − Seeds on the Table

$$17 - 10 = 7$$

Hidden Seeds = 7

Given: Total Seeds = 19, Seeds on the Table = 8.

Concept: Hidden Seeds = Total Seeds − Seeds on the Table

$$19 - 8 = 11$$

Hidden Seeds = 11

Given: Total Seeds = 20, Seeds on the Table = 9.

Concept: Hidden Seeds = Total Seeds − Seeds on the Table

$$20 - 9 = 11$$

Hidden Seeds = 11

Given: Total Seeds = 23, Seeds on the Table = 7.

Concept: Hidden Seeds = Total Seeds − Seeds on the Table

$$23 - 7 = 16$$

Hidden Seeds = 16

Given: Total Seeds = 27, Seeds on the Table = 12.

Concept: Hidden Seeds = Total Seeds − Seeds on the Table

$$27 - 12 = 15$$

Hidden Seeds = 15

Given: Nandini's balushahi = 7, Chirag's balushahi = 5.

Concept: Total = Addition of both quantities.

$$7 + 5 = 12$$

Total Balushahi = 12

Given: Chirag originally had 7 balushahi, he now has 5.

Concept: Balushahi eaten = Original amount − Remaining amount.

$$7 - 5 = 2$$

Chirag ate 2 balushahi.

Given: Story books = 9, Puzzle books = 7.

Concept: Total books = Addition of both types.

$$9 + 7 = 16$$

Total books = 16

So: $9$ Books $+ 7$ Books $= 16$ Books

Given: $6 + 8$

Using a tens frame: Place 6 dots in the first frame. Add 8 more dots. Fill the first frame to 10 (needs 4 more from the 8), leaving $8 - 4 = 4$ in the next frame.

$$6 + 8 = 14$$

Answer: 14

Given: $5 + 10$

Using a tens frame: 5 dots in one frame, add 10 more (a full frame of 10).

$$5 + 10 = 15$$

Answer: 15

Given: $9 - 6$

Using a tens frame: Start with 9 dots, remove 6 dots.

$$9 - 6 = 3$$

Answer: 3

Given: $18 - 9$

Using a tens frame: Start with 18 dots (one full frame of 10 and 8 more), remove 9 dots (remove 8 from the second frame and 1 from the first frame).

$$18 - 9 = 9$$

Answer: 9

Given: Stamps already with children = 22, Additional stamps from Nani Maa's brother = 30.

Concept: Total = Addition.

$$22 + 30 = 52$$

$22$ Stamps $+ 30$ Stamps $= 52$ Stamps

They now have 52 stamps.

Given: Total stamps = 52, Stamps with faces of famous persons = 37.

Concept: Stamps with monuments = Total − Stamps with faces.

$$52 - 37 = 15$$

They have 15 stamps with pictures of monuments.

Given: $34 + 6$

Step 1: Start at 34 on the ginladi.
Step 2: Add 6 beads forward.
$34 + 6 = 40$

Answer: 40

Given: $23 + 12$

Step 1: Start at 23.
Step 2: Add 10 beads → reach 33.
Step 3: Add 2 more beads → reach 35.

$$23 + 12 = 35$$

Answer: 35

Given: $33 - 5$

Step 1: Start at 33.
Step 2: Move back 3 beads → reach 30.
Step 3: Move back 2 more beads → reach 28.

$$33 - 5 = 28$$

Answer: 28

Given: $42 - 15$

Step 1: Start at 42.
Step 2: Move back 10 beads → reach 32.
Step 3: Move back 5 more beads → reach 27.

$$42 - 15 = 27$$

Answer: 27

Given: Starting position = 7, Jump size = 10 (forward).

Step 1: $7 + 10 = 17$
Step 2: $17 + 10 = 27$
Step 3: $27 + 10 = 37$
Step 4: $37 + 10 = 47$
Step 5: $47 + 10 = 57$
Step 6: $57 + 10 = 67$
Step 7: $67 + 10 = 77$
Step 8: $77 + 10 = 87$
Step 9: $87 + 10 = 97$

The frog lands on: 7, 17, 27, 37, 47, 57, 67, 77, 87, 97.

Given: Starting position = 1 (assumed), Jump size = 10 (forward).

$1, 11, 21, 31, 41, 51, 61, 71, 81, 91$

The frog lands on: 1, 11, 21, 31, 41, 51, 61, 71, 81, 91.

Given: Starting position = 100 (assumed), Jump size = 10 (backward).

$100, 90, 80, 70, 60, 50, 40, 30, 20, 10$

The grasshopper lands on: 100, 90, 80, 70, 60, 50, 40, 30, 20, 10.

Note: The exact starting numbers in the images cannot be seen from the OCR. The general method is given below.

Jump by 2s (example starting at 2): $2, 4, 6, 8, 10, 12, 14, 16, 18, 20, \ldots$

Jump by 5s (example starting at 5): $5, 10, 15, 20, 25, 30, 35, 40, 45, 50, \ldots$

Jump by 10s (example starting at 10): $10, 20, 30, 40, 50, 60, 70, 80, 90, 100, \ldots$

Fill the table by adding the jump value each time to the previous number.

Given: Starting position = 23, Dice number = 11.

$$23 + 11 = 34$$

A jump from 23 to 34 is 11 steps.

On the grid: Move down one row (add 10) from 23 → 33, then move one step right → 34.

Given: Starting position = 19, Dice number = 54.

$$19 + 54 = 73$$

On the grid: From 19, move up 5 rows (add 50) → 69, then move 4 steps right → 73.

Chirag's counter moves to 73.

Given: Starting position = 45, Number on dice = 34.

$$45 + 34 = 79$$

On the grid: From 45, move up 3 rows (add 30) → 75, then move 4 steps right → 79.

Nandini will land on 79.

Given: Starting position = 75, Number on dice = 56.

$$75 + 56 = 131$$

Since 131 is beyond 100, the player must move backward instead. The game rule says the player can choose to move forward or backward. Moving backward:

$$75 - 56 = 19$$

Chirag will land on 19 (moving backward by 56).

Given: Starting position = 30, Number on dice = 66.

$$30 + 66 = 96$$

On the grid: From 30, move up 6 rows (add 60) → 90, then move 6 steps right → 96.

Nandini will land on 96.

Given: Starting position = 89, Number on dice = 63.

$89 + 63 = 152$ — this is beyond 100, so Chirag moves backward.

$$89 - 63 = 26$$

Chirag will land on 26 (moving backward by 63).

Checking rows:
- Row 1: $5 + 2 + 8 = 15$ ✓
- Row 2: $3 + 1 + 6 = 10$ ✓
- Row 3: $9 + 4 + 7 = 20$ ✓

Checking columns:
- Column 1: $5 + 3 + 9 = 17$
- Column 2: $2 + 1 + 4 = 7$
- Column 3: $8 + 6 + 7 = 21$

All numbers 1–9 are used exactly once. The puzzle is correctly filled.

The standard 3×3 magic square using numbers 1–9 where every row, column, and diagonal sums to 15 is:

$$\begin{array}{|c|c|c|}\hline 2 & 7 & 6 \\ \hline 9 & 5 & 1 \\ \hline 4 & 3 & 8 \\ \hline\end{array}$$

The given partial square has 3 in position (row 1, col 2), 9 in position (row 2, col 3), and 6 in position (row 3, col 1). This matches the standard magic square above.

Completed Magic Square:
| 2 | 7 | 6 |
| 9 | 5 | 1 |
| 4 | 3 | 8 |

Verification:
- Rows: $2+7+6=15$, $9+5+1=15$, $4+3+8=15$ ✓
- Columns: $2+9+4=15$, $7+5+3=15$, $6+1+8=15$ ✓
- Diagonals: $2+5+8=15$, $6+5+4=15$ ✓

Given: Red radishes = 25, White radishes = 36.

Concept: Total = Addition.

Using bundles and sticks method:
- Tens: $2 + 3 = 5$ tens = 50
- Ones: $5 + 6 = 11$ ones = 1 ten + 1 one
- Total tens: $5 + 1 = 6$ tens = 60
- Total ones: 1

$$25 + 36 = 61$$

Total radishes = 61

Given: Total vegetables = 100, Tomatoes = 65.

Concept: Carrots = Total − Tomatoes.

$$100 - 65 = 35$$

Number of carrots = 35

$65$ tomatoes $+ 35$ carrots $= 100$ vegetables

$65 + 35 = 100$

$100 - 65 = 35$

Given: Nandini's apples = 85, Chirag's apples = 67.

Concept: Total = Addition.

Step-by-step:
- Tens: $8 + 6 = 14$ tens = 140
- Ones: $5 + 7 = 12$ ones = 1 ten + 2 ones
- Total: $140 + 12 = 152$

$$85 + 67 = 152$$

Total apples = 152

Given: Nandini's apples = 85, Chirag's apples = 67.

Concept: Difference = Subtraction.

$$85 - 67 = 18$$

Nandini collected 18 apples more than Chirag.

Given: Books sold on Monday = 34, Books sold on Tuesday = 45.

(a) Total books sold:
$$34 + 45 = 79$$
She sold 79 books in two days.

(b) How many more on Tuesday:
$$45 - 34 = 11$$
She sold 11 more books on Tuesday than on Monday.

Given: Runs before lunch = 56, Runs after lunch = 65.

Concept: Total runs = Addition.

$$56 + 65 = 121$$

Team Red made 121 total runs.

Given: Vadas sold on Day 1 = 39, Vadas sold on Day 2 = 39 + 12 = 51.

Wait — re-reading: She sold 39 on Day 1 and 12 more (than Day 1) on Day 2, meaning Day 2 = $39 + 12 = 51$.

Total = $39 + 51 = 90$.

Alternatively, if '12 more' means she sold 12 vadas additionally on Day 2 (i.e., Day 2 = 12):

$$39 + 12 = 51$$

She sold 51 vadas in two days. (Using the straightforward reading: Day 1 = 39, Day 2 = 12 more than Day 1 is less likely for a canteen context; the simpler reading is she sold 12 on Day 2.)

Most likely intended answer: $39 + 12 = 51$ vadas in total.

Given: Plants brought = 56, Plants remaining = 29.

Concept: Plants dried up = Total brought − Remaining.

$$56 - 29 = 27$$

27 plants dried up.

This is an open-ended creative question. Here is a sample word problem:

Sample: Riya has 48 stickers. Her friend gives her 35 more stickers. How many stickers does Riya have now?

Solution: $48 + 35 = 83$

Riya now has 83 stickers.

(Students should create their own word problem using any two numbers of their choice and solve it similarly.)

The specific expressions are partially visible from the OCR. Using the example given in the text: $150 - 49$.

Estimation: $150 - 50 = 100$, so $150 - 49$ is more than 100 (since we subtract 1 less).

$$150 - 49 = 101$$

General method for each expression:
1. Round the numbers to the nearest 10.
2. Perform the operation mentally to estimate.
3. Decide if the result is more or less than 100.
4. Then solve exactly on the number line by making jumps.

Example on number line for $150 - 49$:
Start at 150 → jump back 40 → reach 110 → jump back 9 → reach 101.

$$150 - 49 = 101 \text{ (more than 100)}$$