Weigh it, Pour it

Note: The actual pictures of animals are not visible in the OCR. However, the approach is as follows:

Given: Pictures of different animals.

Concept: We compare animals by their known weights. Generally, larger animals are heavier.

Example order (if the animals shown are elephant, tiger, dog, cat, sparrow):

Heaviest to Lightest:
1. Elephant
2. Tiger
3. Dog
4. Cat
5. Sparrow

*(Write the names based on the actual animals shown in your textbook picture, arranging from the heaviest to the lightest.)*

Answer (sample): The heaviest object in my home is the refrigerator.

How I knew: I tried to lift or move it and it was very difficult to move even a little. Also, my parents told me it weighs about 50–70 kg. We can also check by looking at the product label or manual which mentions the weight.

Answer (sample): I carry my school bag with some effort because it has many books, notebooks, a water bottle, and a lunch box. It feels heavy on my shoulders.

*(Students should answer based on their own experience.)*

Answer (sample): The heaviest book in my bag is my Mathematics textbook.

How I knew: I picked up each book one by one and compared their weight by holding them in my hands. The Mathematics book felt the heaviest. I could also compare by placing them on a weighing balance.

Answer (sample): My weight is 28 kg.

How I knew: I stood on a weighing machine (bathroom scale) at home and read the number shown on the dial/display. The doctor also measures my weight during health check-ups.

Given: A full pumpkin is shown being weighed.

Concept: If a whole pumpkin weighs, say, $1\ \text{kg}$, then half the pumpkin will weigh half of that.

$$\text{Weight of half pumpkin} = \frac{\text{Weight of full pumpkin}}{2}$$

Answer: The weight of the half pumpkin will be half the weight of the full pumpkin.

*(Write the actual number based on what the full pumpkin weighs in your textbook picture. For example, if the full pumpkin weighs 2 kg, then the half pumpkin weighs 1 kg.)*

Concept: We estimate weight based on our experience and then verify using a weighing balance.

Sample Estimation Table:

| Fruits and Vegetables | Estimation | |
|---|---|---|
| | Less than 1 kg | More than 1 kg |
| 6 Bananas | ✓ | |
| 5 Potatoes | ✓ | |
| 10 Tomatoes | ✓ | |
| 15 Onions | | ✓ |

Reasoning:
- 6 Bananas: Each banana weighs about 100–120 g, so 6 bananas ≈ 600–720 g → Less than 1 kg
- 5 Potatoes: Each potato weighs about 100–150 g, so 5 potatoes ≈ 500–750 g → Less than 1 kg
- 10 Tomatoes: Each tomato weighs about 80–100 g, so 10 tomatoes ≈ 800 g–1 kg → Less than 1 kg (approximately)
- 15 Onions: Each onion weighs about 80–100 g, so 15 onions ≈ 1200–1500 g → More than 1 kg

*(Students should verify by actually weighing these items on a balance.)*

Given: 2 packets of 500 g = 1000 g = 1 kg

Step 1: $2 \times 500\ \text{g} = 1000\ \text{g} = 1\ \text{kg}$

Step 2: Therefore, 1 packet of 500 g $= \dfrac{1}{2}\ \text{kg}$

$$\boxed{500\ \text{g} = \frac{1}{2}\ \text{kg}}$$

Given: One pan has a 500 g daal packet. We need to find how many 250 g packets balance it.

Step 1: $250\ \text{g} + 250\ \text{g} = 500\ \text{g}$

Step 2: So 2 packets of 250 g will balance one 500 g packet.

Step 3: $250\ \text{g} = \dfrac{1}{2}\ \text{of}\ 500\ \text{g}$

$$\boxed{250\ \text{g} = \frac{1}{2}\ \text{of}\ 500\ \text{g}}$$

*(Draw 2 packets of 250 g on the empty pan of the balance.)*

Concept: The pan with the greater weight will tilt downward. If both sides are equal, the balance stays level.

Note: The actual weights on each pan are shown in pictures not visible in the OCR. The general rule to apply is:

- Compare the total weight on the left pan and the right pan.
- The arrow points downward toward the heavier side.
- If both sides are equal, the balance is level (horizontal).

General Method:

(a) Add up all weights on the left pan. Add up all weights on the right pan. Arrow points to the heavier side.

(b) Same method as (a).

(c) Same method as (a).

(d) Same method as (a).

*(Students should look at the weights shown in the pictures in their textbook and draw the arrow toward the heavier pan.)*

Concept: We use grams (g) for lighter objects and kilograms (kg) for heavier objects.

Note: The actual images are not visible. General matching guide:

| Object | Appropriate Unit |
|---|---|
| A feather / leaf / coin | Grams (g) |
| A pencil / eraser / biscuit | Grams (g) |
| A bag of rice / a person / a watermelon | Kilograms (kg) |
| A truck / a car / an elephant | Kilograms (kg) |

*(Match based on the actual objects shown in your textbook picture using the above logic.)*

Given: From the picture, 1 eraser weighs approximately 10 g.

Step 1: Weight of Haldi packet $= 50\ \text{g}$

Step 2: Number of erasers $= \dfrac{50}{10} = 5$

$$\boxed{5\ \text{erasers will weigh the same as a 50 g Haldi packet.}}$$

Given: 1 eraser weighs approximately 10 g; soap bar weighs 100 g.

Step: Number of erasers $= \dfrac{100}{10} = 10$

$$\boxed{A\ 100\ \text{g soap bar will weigh the same as}\ \mathbf{10}\ \text{erasers.}}$$

Given: 1 eraser weighs approximately 10 g; sugar weighs 250 g.

Step: Number of erasers $= \dfrac{250}{10} = 25$

$$\boxed{25\ \text{erasers will weigh the same as 250 g sugar.}}$$

Given: Total Kaju-katli = 1 kg = 1000 g

Concept: Number of boxes $= \dfrac{\text{Total weight}}{\text{Weight of each box}}$

(1) 500 g boxes:
$$\text{Number of boxes} = \frac{1000\ \text{g}}{500\ \text{g}} = \mathbf{2}\ \text{boxes}$$

(2) 250 g boxes:
$$\text{Number of boxes} = \frac{1000\ \text{g}}{250\ \text{g}} = \mathbf{4}\ \text{boxes}$$

(3) 100 g boxes:
$$\text{Number of boxes} = \frac{1000\ \text{g}}{100\ \text{g}} = \mathbf{10}\ \text{boxes}$$

(4) 50 g boxes:
$$\text{Number of boxes} = \frac{1000\ \text{g}}{50\ \text{g}} = \mathbf{20}\ \text{boxes}$$

Answer (sample — students should fill in their own data):

| Items | Weight (per month) |
|---|---|
| Atta | 10 kg |
| Rice | 5 kg |
| Pulses | 2 kg |
| Sugar | 2 kg |

*(Ask your parents at home and fill in the actual quantities used in your family each month.)*

Answer (sample):

1. A book — approximately 500 g
2. A water bottle (empty) — approximately 100 g
3. A pencil box — approximately 300 g

*(Students should write objects they can actually lift easily and estimate their weights.)*