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Weigh it, Pour it — NCERT Solutions

CBSE · Class 4 · Mathematics

NCERT Solutions for Weigh it, Pour it, CBSE Class 4 Mathematics: 34 textbook questions solved step by step. Covers Chapter 8: Weigh It, Pour It.

44 questions52 flashcards4 formulas & key relations5 concepts

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34 Questions Solved · 1 Section

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Chapter 8: Weigh It, Pour It

1Look at the pictures given and write the names of the animals from heaviest to lightest.Show solution

Note: The actual pictures of animals are not visible in the OCR. However, the approach is as follows:

Given: Pictures of different animals.

Concept: We compare animals by their known weights. Generally, larger animals are heavier.

Example order (if the animals shown are elephant, tiger, dog, cat, sparrow):

Heaviest to Lightest:

  1. Elephant
  2. Tiger
  3. Dog
  4. Cat
  5. Sparrow

(Write the names based on the actual animals shown in your textbook picture, arranging from the heaviest to the lightest.)

2Write the name of the heaviest object in your home. How did you know?Show solution

Answer (sample): The heaviest object in my home is the refrigerator.

How I knew: I tried to lift or move it and it was very difficult to move even a little. Also, my parents told me it weighs about 50–70 kg. We can also check by looking at the product label or manual which mentions the weight.

3Do you carry your school bag with ease or with some effort?Show solution

Answer (sample): I carry my school bag with some effort because it has many books, notebooks, a water bottle, and a lunch box. It feels heavy on my shoulders.

(Students should answer based on their own experience.)

4Write the name of the heaviest book in your bag. How did you know?Show solution

Answer (sample): The heaviest book in my bag is my Mathematics textbook.

How I knew: I picked up each book one by one and compared their weight by holding them in my hands. The Mathematics book felt the heaviest. I could also compare by placing them on a weighing balance.

5What is your weight? How did you know?Show solution

Answer (sample): My weight is 28 kg.

How I knew: I stood on a weighing machine (bathroom scale) at home and read the number shown on the dial/display. The doctor also measures my weight during health check-ups.

6What do you think will be the weight of the half pumpkin?Show solution

Given: A full pumpkin is shown being weighed.

Concept: If a whole pumpkin weighs, say, 1 kg1\ \text{kg}, then half the pumpkin will weigh half of that.

Weight of half pumpkin=Weight of full pumpkin2\text{Weight of half pumpkin} = \frac{\text{Weight of full pumpkin}}{2}

Answer: The weight of the half pumpkin will be half the weight of the full pumpkin.

(Write the actual number based on what the full pumpkin weighs in your textbook picture. For example, if the full pumpkin weighs 2 kg, then the half pumpkin weighs 1 kg.)

7Let Us Do — Estimate the weight of the following and put a tick mark (✓) in the appropriate cell: 6 Bananas, 5 Potatoes, 10 Tomatoes, 15 Onions (Less than 1 kg or More than 1 kg).Show solution

Concept: We estimate weight based on our experience and then verify using a weighing balance.

Sample Estimation Table:

Fruits and VegetablesEstimation
Less than 1 kgMore than 1 kg
6 Bananas✓
5 Potatoes✓
10 Tomatoes✓
15 Onions✓

Reasoning:

  • 6 Bananas: Each banana weighs about 100–120 g, so 6 bananas ≈ 600–720 g → Less than 1 kg
  • 5 Potatoes: Each potato weighs about 100–150 g, so 5 potatoes ≈ 500–750 g → Less than 1 kg
  • 10 Tomatoes: Each tomato weighs about 80–100 g, so 10 tomatoes ≈ 800 g–1 kg → Less than 1 kg (approximately)
  • 15 Onions: Each onion weighs about 80–100 g, so 15 onions ≈ 1200–1500 g → More than 1 kg

(Students should verify by actually weighing these items on a balance.)

8Let Us Explore — (a) 2 packets of 500 grams = 1000 g = 1 kg. So, 1 packet of 500 g = ? kg. Or 500 g = ? kg.Show solution

Given: 2 packets of 500 g = 1000 g = 1 kg

Step 1: 2×500 g=1000 g=1 kg2 \times 500\ \text{g} = 1000\ \text{g} = 1\ \text{kg}

Step 2: Therefore, 1 packet of 500 g =12 kg= \dfrac{1}{2}\ \text{kg}

500 g=12 kg\boxed{500\ \text{g} = \frac{1}{2}\ \text{kg}}

9Let Us Find — (1) How many 250 g daal packets will balance one 500 g daal packet? Also complete: 250 g = ___ of 500 g (½, 2).Show solution

Given: One pan has a 500 g daal packet. We need to find how many 250 g packets balance it.

Step 1: 250 g+250 g=500 g250\ \text{g} + 250\ \text{g} = 500\ \text{g}

Step 2: So 2 packets of 250 g will balance one 500 g packet.

Step 3: 250 g=12 of 500 g250\ \text{g} = \dfrac{1}{2}\ \text{of}\ 500\ \text{g}

250 g=12 of 500 g\boxed{250\ \text{g} = \frac{1}{2}\ \text{of}\ 500\ \text{g}}

(Draw 2 packets of 250 g on the empty pan of the balance.)

10Let Us Find — (2) Draw arrows to indicate which side the pan balance will tilt? (a), (b), (c), (d)Show solution

Concept: The pan with the greater weight will tilt downward. If both sides are equal, the balance stays level.

Note: The actual weights on each pan are shown in pictures not visible in the OCR. The general rule to apply is:

  • Compare the total weight on the left pan and the right pan.
  • The arrow points downward toward the heavier side.
  • If both sides are equal, the balance is level (horizontal).

General Method:

(a) Add up all weights on the left pan. Add up all weights on the right pan. Arrow points to the heavier side.

(b) Same method as (a).

(c) Same method as (a).

(d) Same method as (a).

(Students should look at the weights shown in the pictures in their textbook and draw the arrow toward the heavier pan.)

11Let Us Find — (3) Match the unit convenient for measuring each of the following objects.Show solution

Concept: We use grams (g) for lighter objects and kilograms (kg) for heavier objects.

Note: The actual images are not visible. General matching guide:

ObjectAppropriate Unit
A feather / leaf / coinGrams (g)
A pencil / eraser / biscuitGrams (g)
A bag of rice / a person / a watermelonKilograms (kg)
A truck / a car / an elephantKilograms (kg)

(Match based on the actual objects shown in your textbook picture using the above logic.)

12Let Us Do — (1) How many erasers will weigh the same as a 50 g Haldi packet?Show solution

Given: From the picture, 1 eraser weighs approximately 10 g.

Step 1: Weight of Haldi packet =50 g= 50\ \text{g}

Step 2: Number of erasers =5010=5= \dfrac{50}{10} = 5

5 erasers will weigh the same as a 50 g Haldi packet.\boxed{5\ \text{erasers will weigh the same as a 50 g Haldi packet.}}

13Let Us Do — (2) A 100 g soap bar will weigh the same as ______ erasers.Show solution

Given: 1 eraser weighs approximately 10 g; soap bar weighs 100 g.

Step: Number of erasers =10010=10= \dfrac{100}{10} = 10

A 100 g soap bar will weigh the same as 10 erasers.\boxed{A\ 100\ \text{g soap bar will weigh the same as}\ \mathbf{10}\ \text{erasers.}}

14Let Us Do — (3) ______ erasers will weigh the same as 250 g sugar.Show solution

Given: 1 eraser weighs approximately 10 g; sugar weighs 250 g.

Step: Number of erasers =25010=25= \dfrac{250}{10} = 25

25 erasers will weigh the same as 250 g sugar.\boxed{25\ \text{erasers will weigh the same as 250 g sugar.}}

15Let Us Think — Boxes of Sweet: Mr Shrinathan has 1 kg Kaju-katli. Write the number of boxes needed to pack 1 kg in: (1) 500 g boxes, (2) 250 g boxes, (3) 100 g boxes, (4) 50 g boxes.Show solution

Given: Total Kaju-katli = 1 kg = 1000 g

Concept: Number of boxes =Total weightWeight of each box= \dfrac{\text{Total weight}}{\text{Weight of each box}}

(1) 500 g boxes:
Number of boxes=1000 g500 g=2 boxes\text{Number of boxes} = \frac{1000\ \text{g}}{500\ \text{g}} = \mathbf{2}\ \text{boxes}

(2) 250 g boxes:
Number of boxes=1000 g250 g=4 boxes\text{Number of boxes} = \frac{1000\ \text{g}}{250\ \text{g}} = \mathbf{4}\ \text{boxes}

(3) 100 g boxes:
Number of boxes=1000 g100 g=10 boxes\text{Number of boxes} = \frac{1000\ \text{g}}{100\ \text{g}} = \mathbf{10}\ \text{boxes}

(4) 50 g boxes:
Number of boxes=1000 g50 g=20 boxes\text{Number of boxes} = \frac{1000\ \text{g}}{50\ \text{g}} = \mathbf{20}\ \text{boxes}

16Let Us Do — Ask your parents and find the amount of consumption of the following items at your home in a month: Atta, Rice, Pulses, Sugar.Show solution

Answer (sample — students should fill in their own data):

ItemsWeight (per month)
Atta10 kg
Rice5 kg
Pulses2 kg
Sugar2 kg

(Ask your parents at home and fill in the actual quantities used in your family each month.)

17Let Us Do — (1) Write the names of three objects that you can lift easily. Estimate and write their weights.Show solution

Answer (sample):

  1. A book — approximately 500 g
  2. A water bottle (empty) — approximately 100 g
  3. A pencil box — approximately 300 g

(Students should write objects they can actually lift easily and estimate their weights.)

18Let Us Do — (2) Write the names of things that you can lift with a lot of effort. Estimate and write their weights.

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19Let Us Do — (3) How many 1 kg packets are in: (a) 10 kg, (b) 20 kg, (c) 50 kg, (d) 25 kg?

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20Let Us Do — (4) Match the objects in the left column with their estimated weights in the right column: A cat, An elephant, A 1 litre filled bottle, A tiger, An empty gas cylinder, A pen, A leaf, A wooden chair.

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21Measuring Capacity — Find bottles and containers that can hold the following quantities of water: Less than 1 litre, 1 litre, More than 1 litre.

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22Let Us Find — (a) How many 500 ml bottles will fill a 1 l bottle?

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23Let Us Find — (b) How many 250 ml bottles will fill a 1 l bottle?

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24Let Us Find — (c) How many 100 ml bottles will fill a 1 l bottle?

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25Let Us Find — (d) Find: 250 ml in ½ l = ___; 250 ml in 750 ml = ___; 100 ml in ½ l = ___; 100 ml in 800 ml = ___.

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26Let Us Do — (1) Find how many 10 ml will fill a 100 ml bottle. Also find: (a) 10 ml dosing cups to fill a 250 ml glass, (b) 10 ml dosing cups to fill a 500 ml vessel, (c) 10 ml dosing cups to fill a 1 l bottle.

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27Let Us Do — (2) Take a 1 ml dropper and find out: (a) How many 1 ml droppers will fill a 10 ml dosing cup? (b) How many droppers will fill a teaspoon?

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28Let Us Do — (3) Find out how much of these liquids are used at a time: (a) Eye drops, (b) Honey, (c) Cough Syrup, (d) Cooking Oil.

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29Let Us Do — (4) Mr Krishna packages perfumed oils. Customers want 1 l perfumed oil in different sized bottles. Write the number of bottles each will get: (a) Ms Shetty — 500 ml bottles, (b) Mr Muthukumar — 200 ml bottles, (c) Ms Naini — 100 ml bottles, (d) Ms Kannan — 50 ml bottles.

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30Let Us Do — (5) Estimate and verify by measuring the capacity of: Water bottle, Glass, Mug, Jug, Bucket, Teaspoon, Bowl.

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31Let Us Explore — Visit nearby shops and make a list of different items that are sold in the following quantities: 50 ml, 100 ml, 200 ml, 250 ml, 500 ml, 900 ml.

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32Let Us Find — (a) How many litres of water do you drink in a day? How did you find out? (b) How much water can a crow drink at a time? (c) How much milk do you drink in one day? (d) How much water does an elephant drink in a day?

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33How much water may be used in the following activities? (a) Water for taking a shower, (b) Watering crops in a field, (c) Watering flowering plants, (d) Washing clothes.

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34Water Conservation — Have you ever noticed a small drip of water flowing from your tap or water purifier? Take a container and put it under the leaking tap for an hour. How much water is lost in an hour? How much in a day? How much in a week?

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Frequently Asked Questions

What are the important topics in Weigh it, Pour it for CBSE Class 4 Mathematics?
Key topics in Weigh it, Pour it include Measuring Weight, Estimating Weight in Daily Life, Balance and Number of Packets, Boxes of Sweet. Study these first, then practise questions on each for Class 4 exams.
Are these NCERT Solutions for Weigh it, Pour it free?
The first 17 of the 34 solutions on this page are open to read. The other 17 are free with a Super Tutor account — signing up is free and needs no card.
How should I revise Weigh it, Pour it for Class 4 exams?
Learn the core ideas first, then work through the 44 practice questions on Weigh it, Pour it. Revise definitions regularly and use flashcards for quick recall before the exam.

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