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Chapter 6 of 14
Important Questions

Triangles — Important Questions

Gujarat Board · Class 10 · Mathematics

45 important questions from Triangles for Gujarat Board Class 10 Mathematics, with answers. Includes multiple choice and multiple correct questions.

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45 Questions·
multiple choicemultiple correct

Important Questions from Triangles

1multiple correct

Which of the following sets of measurements can form similar triangles? (Multiple correct answers possible)

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Triangle 1: sides 3, 4, 5 and Triangle 2: sides 6, 8, 10, Triangle 1: sides 5, 12, 13 and Triangle 2: sides 10, 24, 26, Triangle 1: sides 2, 3, 4 and Triangle 2: sides 4, 6, 8

For similar triangles, the ratios of corresponding sides must be equal. Option 1: 3/6 = 4/8 = 5/10 = 1/2 ✓. Option 2: 5/10 = 12/24 = 13/26 = 1/2 ✓. Option 3: 3/6 ≠ 4/7 ≠ 5/8 ✗. Option 4: 2/4 = 3/6 = 4/8 = 1/2 ✓. Option 5: 1/2 ≠ 2/4 ≠ 3/5 ✗.

2multiple correct

If in triangles ABC and PQR, AB/PQ = BC/QR = CA/RP = 2/3, then which of the following statements are true? (Multiple correct answers possible)

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Triangle ABC ~ Triangle PQR, Corresponding angles are equal, The ratio of their areas is 4:9, The ratio of their perimeters is 2:3

Since all corresponding sides are in the ratio 2:3, by SSS similarity criterion, triangle ABC ~ triangle PQR. This means corresponding angles are equal. The triangles are not congruent as they have different sizes. The ratio of areas = (2/3)² = 4/9. The ratio of perimeters = 2/3 (same as the ratio of corresponding sides).

3multiple choice

In triangle ABC, D and E are points on sides AB and AC respectively such that DE || BC. If AD = 4 cm, AB = 12 cm, and AC = 9 cm, find AE.

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3 cm

By Basic Proportionality Theorem, when DE || BC, we have AD/AB = AE/AC. Given: AD = 4 cm, AB = 12 cm, AC = 9 cm. Substituting: 4/12 = AE/9. Simplifying: 1/3 = AE/9. Therefore, AE = 9 × (1/3) = 3 cm.

4multiple choice

Two triangles have sides in the ratio 5:7. If the area of the smaller triangle is 75 cm², what is the area of the larger triangle?

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147 cm²

For similar triangles with sides in ratio 5:7, their areas are in the ratio (5:7)² = 25:49. If area of smaller triangle = 75 cm², then 75/Area of larger triangle = 25/49. Therefore, Area of larger triangle = (75 × 49)/25 = 3675/25 = 147 cm².

+41 more questions on Triangles (Gujarat Board Class 10 Mathematics)

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Frequently Asked Questions

What are the important topics in Triangles for Gujarat Board Class 10 Mathematics?
Key topics in Triangles include Similar Figures, Basic Proportionality Theorem (Thales Theorem), Criteria for Similarity of Triangles, Applications and Problem Solving. Study these first, then practise questions on each for the Gujarat Board Class 10 board exam.
How many important questions are there in Triangles?
Super Tutor has 45 practice questions for Triangles, including multiple choice, multiple correct questions. A sample with answers is on this page.

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Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.

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