Triangles — Practice Quiz
Gujarat Board · Class 10 · Mathematics
Try a 4-question quiz on Triangles for Gujarat Board Class 10 Mathematics: tap an answer to check it and see why. 45 questions in the full chapter test.
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Quick Quiz: Triangles
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In triangle ABC, if DE is parallel to BC and AD = 6 cm, DB = 9 cm, AE = 4 cm, then find EC.
If triangles ABC and DEF are similar with ratio of similarity 3:4, and the area of triangle ABC is 27 cm², find the area of triangle DEF.
In triangle PQR, if angle P = 60°, angle Q = 80°, and in triangle XYZ, angle X = 60°, angle Y = 80°, then which similarity criterion proves that triangle PQR ~ triangle XYZ?
In triangle ABC, DE || BC, AD = x, DB = x + 3, AE = 2x, and EC = x + 6. Find the value of x.
Sample Questions
Which of the following sets of measurements can form similar triangles? (Multiple correct answers possible)
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Triangle 1: sides 3, 4, 5 and Triangle 2: sides 6, 8, 10, Triangle 1: sides 5, 12, 13 and Triangle 2: sides 10, 24, 26, Triangle 1: sides 2, 3, 4 and Triangle 2: sides 4, 6, 8
For similar triangles, the ratios of corresponding sides must be equal. Option 1: 3/6 = 4/8 = 5/10 = 1/2 ✓. Option 2: 5/10 = 12/24 = 13/26 = 1/2 ✓. Option 3: 3/6 ≠ 4/7 ≠ 5/8 ✗. Option 4: 2/4 = 3/6 = 4/8 = 1/2 ✓. Option 5: 1/2 ≠ 2/4 ≠ 3/5 ✗.
If in triangles ABC and PQR, AB/PQ = BC/QR = CA/RP = 2/3, then which of the following statements are true? (Multiple correct answers possible)
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Triangle ABC ~ Triangle PQR, Corresponding angles are equal, The ratio of their areas is 4:9, The ratio of their perimeters is 2:3
Since all corresponding sides are in the ratio 2:3, by SSS similarity criterion, triangle ABC ~ triangle PQR. This means corresponding angles are equal. The triangles are not congruent as they have different sizes. The ratio of areas = (2/3)² = 4/9. The ratio of perimeters = 2/3 (same as the ratio of corresponding sides).
In triangle ABC, D and E are points on sides AB and AC respectively such that DE || BC. If AD = 4 cm, AB = 12 cm, and AC = 9 cm, find AE.
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3 cm
By Basic Proportionality Theorem, when DE || BC, we have AD/AB = AE/AC. Given: AD = 4 cm, AB = 12 cm, AC = 9 cm. Substituting: 4/12 = AE/9. Simplifying: 1/3 = AE/9. Therefore, AE = 9 × (1/3) = 3 cm.
Two triangles have sides in the ratio 5:7. If the area of the smaller triangle is 75 cm², what is the area of the larger triangle?
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147 cm²
For similar triangles with sides in ratio 5:7, their areas are in the ratio (5:7)² = 25:49. If area of smaller triangle = 75 cm², then 75/Area of larger triangle = 25/49. Therefore, Area of larger triangle = (75 × 49)/25 = 3675/25 = 147 cm².
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