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Chapter 6 of 14
Practice Quiz

Triangles

Gujarat Board · Class 10 · Mathematics

Practice quiz for Triangles — Gujarat Board Class 10 Mathematics. MCQs and questions with answers to test your preparation.

45 questions24 flashcards5 concepts

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Quick Quiz: Triangles

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1

In triangle ABC, if DE is parallel to BC and AD = 6 cm, DB = 9 cm, AE = 4 cm, then find EC.

2

If triangles ABC and DEF are similar with ratio of similarity 3:4, and the area of triangle ABC is 27 cm², find the area of triangle DEF.

3

In triangle PQR, if angle P = 60°, angle Q = 80°, and in triangle XYZ, angle X = 60°, angle Y = 80°, then which similarity criterion proves that triangle PQR ~ triangle XYZ?

4

In triangle ABC, DE || BC, AD = x, DB = x + 3, AE = 2x, and EC = x + 6. Find the value of x.

45 Questions·
multiple choicemultiple correct

Sample Questions

1multiple correct

Which of the following sets of measurements can form similar triangles? (Multiple correct answers possible)

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Triangle 1: sides 3, 4, 5 and Triangle 2: sides 6, 8, 10, Triangle 1: sides 5, 12, 13 and Triangle 2: sides 10, 24, 26, Triangle 1: sides 2, 3, 4 and Triangle 2: sides 4, 6, 8

For similar triangles, the ratios of corresponding sides must be equal. Option 1: 3/6 = 4/8 = 5/10 = 1/2 ✓. Option 2: 5/10 = 12/24 = 13/26 = 1/2 ✓. Option 3: 3/6 ≠ 4/7 ≠ 5/8 ✗. Option 4: 2/4 = 3/6 = 4/8 = 1/2 ✓. Option 5: 1/2 ≠ 2/4 ≠ 3/5 ✗.

2multiple correct

If in triangles ABC and PQR, AB/PQ = BC/QR = CA/RP = 2/3, then which of the following statements are true? (Multiple correct answers possible)

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Triangle ABC ~ Triangle PQR, Corresponding angles are equal, The ratio of their areas is 4:9, The ratio of their perimeters is 2:3

Since all corresponding sides are in the ratio 2:3, by SSS similarity criterion, triangle ABC ~ triangle PQR. This means corresponding angles are equal. The triangles are not congruent as they have different sizes. The ratio of areas = (2/3)² = 4/9. The ratio of perimeters = 2/3 (same as the ratio of corresponding sides).

3multiple choice

In triangle ABC, D and E are points on sides AB and AC respectively such that DE || BC. If AD = 4 cm, AB = 12 cm, and AC = 9 cm, find AE.

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3 cm

By Basic Proportionality Theorem, when DE || BC, we have AD/AB = AE/AC. Given: AD = 4 cm, AB = 12 cm, AC = 9 cm. Substituting: 4/12 = AE/9. Simplifying: 1/3 = AE/9. Therefore, AE = 9 × (1/3) = 3 cm.

4multiple choice

Two triangles have sides in the ratio 5:7. If the area of the smaller triangle is 75 cm², what is the area of the larger triangle?

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147 cm²

For similar triangles with sides in ratio 5:7, their areas are in the ratio (5:7)² = 25:49. If area of smaller triangle = 75 cm², then 75/Area of larger triangle = 25/49. Therefore, Area of larger triangle = (75 × 49)/25 = 3675/25 = 147 cm².

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Frequently Asked Questions

What are the important topics in Triangles for Gujarat Board Class 10 Mathematics?
Triangles covers several key topics that are frequently asked in Gujarat Board Class 10 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Triangles — Gujarat Board Class 10 Mathematics?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.

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