Surface Areas and Volumes — Practice Quiz
Gujarat Board · Class 10 · Mathematics
Try a 4-question quiz on Surface Areas and Volumes for Gujarat Board Class 10 Mathematics: tap an answer to check it and see why.
Interactive on Super Tutor
Studying Surface Areas and Volumes? Get the full interactive chapter.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for practice quiz and more.
Free trial, no card needed.
Quick Quiz: Surface Areas and Volumes
0/4Tap an answer to check it instantly. No sign-up needed for these 4.
A toy is made by placing a hemisphere on top of a cylinder. The cylinder has radius 7 cm and height 10 cm. Find the total surface area of the toy. (Use π = 22/7)
A solid is formed by joining a cone and a hemisphere at their bases. The radius of both is 6 cm and the height of the cone is 8 cm. What is the volume of the solid? (Use π = 22/7)
A capsule is made by joining two hemispheres to the ends of a cylinder. If the radius is 3.5 cm and cylinder height is 14 cm, find the total volume. (Use π = 22/7)
A wooden toy is made by scooping out a hemisphere from one face of a cube with side 10 cm. The radius of the hemisphere is 3 cm. Find the volume of the remaining solid.
Sample Questions
Which of the following statements are correct about the surface area of combined solids?
Show answer
We must subtract the areas where solids are joined, Only the visible surfaces are counted in total surface area
When combining solids, we only count the visible surfaces. The flat faces where two solids join are not visible from outside, so they are not included in the total surface area calculation.
The curved surface area of a cone with radius 5 cm and slant height 13 cm is:
Show answer
204.2 cm²
Curved surface area of cone = πrl where r is radius and l is slant height. CSA = (22/7) × 5 × 13 = (22/7) × 65 = 204.2 cm².
A tent is in the shape of a cylinder surmounted by a cone. Both have the same radius 7 m. Height of cylinder is 10 m and height of cone is 8 m. Find the curved surface area of the tent. (Use π = 22/7)
Show answer
1166 m²
Total CSA = CSA of cylinder + CSA of cone. CSA of cylinder = 2πrh = 2 × (22/7) × 7 × 10 = 440 m². For cone, slant height l = √(r² + h²) = √(7² + 8²) = √(49 + 64) = √113 ≈ 10.6 m. CSA of cone = πrl = (22/7) × 7 × 10.6 = 231.9 ≈ 232 m². Wait, let me recalculate more carefully: l = √113 ≈ 10.63. CSA of cone = (22/7) × 7 × 10.63 = 234 m². Total = 440 + 234 = 674 m². Let me check again: l = √113 = 10.63, CSA of cone = 22 × 10.63 = 233.86 ≈ 234 m². Hmm, let me recalculate: CSA of cone = (22/7) × 7 × √113 = 22 × √113 = 22 × 10.63 = 234 m². Actually, let me be more precise: √113 ≈ 10.63, so CSA of con
Which of the following formulas are correct for calculating volumes?
Show answer
Volume of sphere = (4/3)πr³, Volume of hemisphere = (2/3)πr³, Volume of cone = (1/3)πr²h, Volume of cuboid = length × breadth × height
The correct volume formulas are: Sphere = (4/3)πr³, Hemisphere = (2/3)πr³, Cone = (1/3)πr²h, Cylinder = πr²h (not 2πr²h), Cuboid = l×b×h.
+40 more questions on Surface Areas and Volumes (Gujarat Board Class 10 Mathematics)
Practise AllFrequently Asked Questions
What are the important topics in Surface Areas and Volumes for Gujarat Board Class 10 Mathematics?
How many practice questions are there for Surface Areas and Volumes?
Sources & Official References
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
More resources for Surface Areas and Volumes
For serious students
Get the full Surface Areas and Volumes chapter — start free.
Quizzes, flashcards, an AI doubt solver and a study plan for Gujarat Board Class 10 Mathematics. Free to start, no card needed.