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Chapter 8 of 12
Important Questions

Heron's Formula

Karnataka Board · Class 9 · Mathematics

Most important questions from Heron's Formula for Karnataka Board Class 9 Mathematics board exam 2026. MCQs, short answer, and long answer questions with marks.

45 questions20 flashcards4 concepts

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45 Questions·
multiple choice

Sample Questions

1multiple choice
1 marks

Find the area of an isosceles triangle with equal sides 10 cm each and base 12 cm.

Show answer

48 cm²

Step 1: Sides are a = 10 cm, b = 10 cm, c = 12 cm. Step 2: Calculate semi-perimeter s = (10+10+12)/2 = 16 cm. Step 3: Find differences: (s-a) = 6, (s-b) = 6, (s-c) = 4. Step 4: Apply Heron's formula: Area = √[16×6×6×4] = √[2304] = 48 cm². We can verify using height: height = √(10²-6²) = 8 cm, so Area = (1/2)×12×8 = 48 cm².

2multiple choice
1 marks

A triangle has sides 7 cm, 24 cm, and 25 cm. What type of triangle is this and what is its area?

Show answer

Right triangle, 84 cm²

Step 1: Check if it's a right triangle: 7² + 24² = 49 + 576 = 625 = 25². Yes, it's a right triangle. Step 2: For right triangle, area = (1/2) × 7 × 24 = 84 cm². Step 3: Verify using Heron's formula: s = (7+24+25)/2 = 28. Step 4: Area = √[28×21×4×3] = √[7056] = 84 cm². Both methods give the same answer, confirming our calculation.

3multiple choice
1 marks

The area of a triangle with sides 8 cm, 15 cm, and 17 cm is:

Show answer

60 cm²

Step 1: Check if it's a right triangle: 8² + 15² = 64 + 225 = 289 = 17². Yes, it's a right triangle. Step 2: For a right triangle, area = (1/2) × base × height = (1/2) × 8 × 15 = 60 cm². Step 3: Verify using Heron's formula: s = (8+15+17)/2 = 20. Step 4: Area = √[20×12×5×3] = √[3600] = 60 cm². This demonstrates how Heron's formula works even when we can use simpler methods.

4multiple choice
1 marks

A triangular field has a perimeter of 72 m and sides in the ratio 5:12:13. Find its area.

Show answer

216 m²

Step 1: Let sides be 5x, 12x, 13x. Since perimeter = 72, we have 30x = 72, so x = 2.4. Step 2: The sides are 12 m, 28.8 m, 31.2 m. Wait, let me recalculate: 5×2.4=12, 12×2.4=28.8, 13×2.4=31.2. Actually, 5+12+13=30, so 30x=72 gives x=2.4. Sides are 12m, 28.8m, 31.2m. Step 3: This is a 5:12:13 right triangle (5²+12²=13²). Step 4: Area = (1/2)×12×28.8 = 172.8 m². Let me recalculate: if ratio is 5:12:13 and perimeter is 72, then each unit = 72/30 = 2.4, giving sides 12, 28.8, 31.2. But 5:12:13 with scale factor 1.8 gives 9, 21.6, 23.4. Let me try again: 72/(5+12+13) = 72/30 = 2.4, so sides are 12,

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Frequently Asked Questions

What are the important topics in Heron's Formula for Karnataka Board Class 9 Mathematics?
Heron's Formula covers several key topics that are frequently asked in Karnataka Board Class 9 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Heron's Formula — Karnataka Board Class 9 Mathematics?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many important questions are there in Heron's Formula?
There are 45 practice questions available for Heron's Formula. These cover multiple question types including MCQs, short answer, and long answer questions.

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