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Chapter 8 of 12
Important Questions

Heron's Formula — Important Questions

Karnataka Board · Class 9 · Mathematics

45 important questions from Heron's Formula for Karnataka Board Class 9 Mathematics, with answers. Includes multiple choice questions.

45 questions20 flashcards4 formulas & key relations4 concepts

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45 Questions·
multiple choice

Important Questions from Heron's Formula

1multiple choice
1 marks

Find the area of an isosceles triangle with equal sides 10 cm each and base 12 cm.

Show answer

48 cm²

Step 1: Sides are a = 10 cm, b = 10 cm, c = 12 cm. Step 2: Calculate semi-perimeter s = (10+10+12)/2 = 16 cm. Step 3: Find differences: (s-a) = 6, (s-b) = 6, (s-c) = 4. Step 4: Apply Heron's formula: Area = √[16×6×6×4] = √[2304] = 48 cm². We can verify using height: height = √(10²-6²) = 8 cm, so Area = (1/2)×12×8 = 48 cm².

2multiple choice
1 marks

A triangle has sides 7 cm, 24 cm, and 25 cm. What type of triangle is this and what is its area?

Show answer

Right triangle, 84 cm²

Step 1: Check if it's a right triangle: 7² + 24² = 49 + 576 = 625 = 25². Yes, it's a right triangle. Step 2: For right triangle, area = (1/2) × 7 × 24 = 84 cm². Step 3: Verify using Heron's formula: s = (7+24+25)/2 = 28. Step 4: Area = √[28×21×4×3] = √[7056] = 84 cm². Both methods give the same answer, confirming our calculation.

3multiple choice
1 marks

The area of a triangle with sides 8 cm, 15 cm, and 17 cm is:

Show answer

60 cm²

Step 1: Check if it's a right triangle: 8² + 15² = 64 + 225 = 289 = 17². Yes, it's a right triangle. Step 2: For a right triangle, area = (1/2) × base × height = (1/2) × 8 × 15 = 60 cm². Step 3: Verify using Heron's formula: s = (8+15+17)/2 = 20. Step 4: Area = √[20×12×5×3] = √[3600] = 60 cm². This demonstrates how Heron's formula works even when we can use simpler methods.

4multiple choice
1 marks

A triangular field has a perimeter of 72 m and sides in the ratio 5:12:13. Find its area.

Show answer

216 m²

Step 1: Let sides be 5x, 12x, 13x. Since perimeter = 72, we have 30x = 72, so x = 2.4. Step 2: The sides are 12 m, 28.8 m, 31.2 m. Wait, let me recalculate: 5×2.4=12, 12×2.4=28.8, 13×2.4=31.2. Actually, 5+12+13=30, so 30x=72 gives x=2.4. Sides are 12m, 28.8m, 31.2m. Step 3: This is a 5:12:13 right triangle (5²+12²=13²). Step 4: Area = (1/2)×12×28.8 = 172.8 m². Let me recalculate: if ratio is 5:12:13 and perimeter is 72, then each unit = 72/30 = 2.4, giving sides 12, 28.8, 31.2. But 5:12:13 with scale factor 1.8 gives 9, 21.6, 23.4. Let me try again: 72/(5+12+13) = 72/30 = 2.4, so sides are 12,

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Frequently Asked Questions

What are the important topics in Heron's Formula for Karnataka Board Class 9 Mathematics?
Key topics in Heron's Formula include Understanding Heron's Formula, Step-by-Step Problem Solving Method, Worked Examples and Applications, Special Cases and Problem Types. Study these first, then practise questions on each for Class 9 exams.
How many important questions are there in Heron's Formula?
Super Tutor has 45 practice questions for Heron's Formula, including multiple choice questions. A sample with answers is on this page.

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