Lines and Angles
Karnataka Board · Class 9 · Mathematics
Most important questions from Lines and Angles for Karnataka Board Class 9 Mathematics board exam 2026. MCQs, short answer, and long answer questions with marks.
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Sample Questions
In triangle ABC, if ∠A = 60° and ∠B = 80°, what is ∠C?
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40°
Step 1: The sum of all angles in a triangle is always 180°. Step 2: ∠A + ∠B + ∠C = 180°. Step 3: Substitute the given values: 60° + 80° + ∠C = 180°. Step 4: 140° + ∠C = 180°. Step 5: ∠C = 180° - 140° = 40°.
If two angles are complementary and one angle is 35°, find the other angle.
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55°
Step 1: Complementary angles are two angles whose sum is 90°. Step 2: Let the unknown angle be x°. Step 3: Given angle + x° = 90°. Step 4: 35° + x° = 90°. Step 5: x° = 90° - 35° = 55°.
Lines PQ and RS intersect at O. If ∠POR : ∠ROQ = 3:2, find ∠POR.
Show answer
108°
Step 1: ∠POR and ∠ROQ form a linear pair, so they are supplementary. Step 2: ∠POR + ∠ROQ = 180°. Step 3: Given ratio ∠POR : ∠ROQ = 3:2, so let ∠POR = 3x and ∠ROQ = 2x. Step 4: 3x + 2x = 180°, so 5x = 180°. Step 5: x = 36°, therefore ∠POR = 3 × 36° = 108°.
If AB || CD and EF is a transversal, and ∠AEF = 130°, find ∠EFC (alternate interior angle).
Show answer
130°
Step 1: When parallel lines are cut by a transversal, alternate interior angles are equal. Step 2: ∠AEF and ∠EFC are alternate interior angles. Step 3: By the Alternate Interior Angles theorem, these angles are equal when lines are parallel. Step 4: Therefore, ∠EFC = ∠AEF = 130°.
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Sources & Official References
- Karnataka SSLC — kseeb.kar.nic.in
- Dept of Pre-University Education, Karnataka
- National Education Policy 2020 — education.gov.in
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