Statistics
Karnataka Board · Class 9 · Mathematics
Practice quiz for Statistics — Karnataka Board Class 9 Mathematics. MCQs and questions with answers to test your preparation.
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Quick Quiz: Statistics
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A bar graph shows the number of books read by students in different months. If January shows 15 books, February shows 20 books, March shows 12 books, and April shows 18 books, what is the total number of books read in these four months?
In a frequency distribution table, a class interval is 20-30. What is the class mark (mid-point) of this interval?
A histogram shows the heights of students. If the class interval 150-160 cm has a frequency of 12 students and the width is 10 cm, what would be the height of the rectangle in the histogram if 1 cm on the y-axis represents 2 students?
A frequency polygon is drawn for the marks obtained by students. The points plotted are (15, 3), (25, 7), (35, 12), (45, 8), (55, 4). What is the total frequency represented by this polygon?
Sample Questions
In a bar graph showing favorite sports of 100 students, Cricket shows 35 students, Football shows 25 students, Basketball shows 20 students, and Tennis shows the remaining students. How many students chose Tennis?
Show answer
20
Step 1: Identify total students = 100, Cricket = 35, Football = 25, Basketball = 20. Step 2: Find students who chose Cricket, Football, and Basketball: 35 + 25 + 20 = 80 students. Step 3: Calculate remaining students for Tennis: Total - (Cricket + Football + Basketball) = 100 - 80. Step 4: Final calculation: 100 - 80 = 20 students chose Tennis. Verify: 35 + 25 + 20 + 20 = 100 ✓.
A histogram has class intervals of equal width 5. If the first interval is 10-15 with frequency 8, and the second interval 15-20 has frequency 12, what is the difference in the heights of these two rectangles?
Show answer
4
Step 1: In histograms with equal class widths, the height of rectangles is proportional to frequency. Step 2: Frequency of first interval (10-15) = 8, Frequency of second interval (15-20) = 12. Step 3: Since widths are equal, height difference = frequency difference = 12 - 8. Step 4: Calculate: 12 - 8 = 4. The difference in heights of the rectangles is 4 units.
The class intervals in a frequency distribution are 0-5, 5-10, 10-15, 15-20. What is the class size of each interval?
Show answer
5
Step 1: Class size is calculated as Upper limit - Lower limit for any interval. Step 2: Take the first interval 0-5: Upper limit = 5, Lower limit = 0. Step 3: Calculate class size: 5 - 0 = 5. Step 4: Verify with another interval 5-10: 10 - 5 = 5. All intervals have the same class size of 5.
A frequency polygon has vertices at points (5,2), (15,6), (25,10), (35,8), (45,4). What is the mode class interval if each class has a width of 10?
Show answer
20-30
Step 1: The mode class is the class with the highest frequency. Find the highest frequency from y-coordinates: 2, 6, 10, 8, 4. Step 2: The maximum frequency is 10, corresponding to x-coordinate 25. Step 3: Since 25 is the class mark and class width is 10, find the interval: Class mark = (Lower + Upper)/2, so 25 = (Lower + Upper)/2. Step 4: For width 10: Lower = 25 - 5 = 20, Upper = 25 + 5 = 30. The mode class interval is 20-30.
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Sources & Official References
- Karnataka SSLC — kseeb.kar.nic.in
- Dept of Pre-University Education, Karnataka
- National Education Policy 2020 — education.gov.in
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