Skip to main content
Chapter 10 of 12
Practice Quiz

Surface areas and Volumes — Practice Quiz

Karnataka Board · Class 9 · Mathematics

Try a 4-question quiz on Surface areas and Volumes for Karnataka Board Class 9 Mathematics: tap an answer to check it and see why.

45 questions20 flashcards3 formulas & key relations4 concepts

Interactive on Super Tutor

Studying Surface areas and Volumes? Get the full interactive chapter.

Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for practice quiz and more.

Free trial, no card needed.

Quick Quiz: Surface areas and Volumes

0/4

Tap an answer to check it instantly. No sign-up needed for these 4.

1

Find the curved surface area of a cone with base radius 7 cm and slant height 15 cm.

2

A sphere has radius 10.5 cm. What is its surface area?

3

Find the volume of a cone with base radius 6 cm and height 8 cm.

4

A hemisphere has radius 7 cm. Find its curved surface area.

45 Questions·
multiple choice

Sample Questions

1multiple choice
1 marks

Find the total surface area of a cone with base radius 5 cm and slant height 13 cm.

Show answer

282.9 cm²

Step 1: Given r = 5 cm, l = 13 cm. Step 2: Total surface area = curved surface area + base area = πrl + πr². Step 3: Factor out π and r to get πr(l + r). Step 4: Substitute = (22/7) × 5 × (13 + 5) = (22/7) × 5 × 18 = 1980/7 = 282.9 cm². Total surface area includes both curved surface and circular base.

2multiple choice
1 marks

The volume of a sphere is 4851 cm³. Find its radius. (Use π = 22/7)

Show answer

10.5 cm

Step 1: Given volume = 4851 cm³. Step 2: Apply volume formula (4/3)πr³ = 4851. Step 3: Substitute π = 22/7: (4/3) × (22/7) × r³ = 4851. Step 4: Solve for r³: r³ = (4851 × 3 × 7)/(4 × 22) = 101871/88 = 1157.625. Step 5: Take cube root: r = 10.5 cm. Working backwards from volume to radius requires solving the cubic equation.

3multiple choice
1 marks

A cone has height 12 cm and volume 1232 cm³. Find the radius of its base.

Show answer

7 cm

Step 1: Given h = 12 cm, V = 1232 cm³. Step 2: Apply volume formula (1/3)πr²h = 1232. Step 3: Substitute known values: (1/3) × (22/7) × r² × 12 = 1232. Step 4: Solve for r²: r² = (1232 × 3 × 7)/(22 × 12) = 25872/264 = 49. Step 5: Therefore r = 7 cm. This is a reverse application of the volume formula.

4multiple choice
1 marks

Find the volume of a hemisphere with diameter 21 cm.

Show answer

2425.5 cm³

Step 1: Given diameter = 21 cm, so radius r = 10.5 cm. Step 2: Volume of hemisphere = (2/3)πr³. Step 3: Substitute values = (2/3) × (22/7) × (10.5)³. Step 4: Calculate = (2/3) × (22/7) × 1157.625 = (2 × 22 × 1157.625)/(3 × 7) = 2425.5 cm³. Remember hemisphere volume is half of sphere volume.

+41 more questions on Surface areas and Volumes (Karnataka Board Class 9 Mathematics)

Practise All

Frequently Asked Questions

What are the important topics in Surface areas and Volumes for Karnataka Board Class 9 Mathematics?
Key topics in Surface areas and Volumes include Surface Area of Right Circular Cone, Surface Area of Sphere and Hemisphere, Volume of Right Circular Cone, Volume of Sphere and Hemisphere. Study these first, then practise questions on each for Class 9 exams.
How many practice questions are there for Surface areas and Volumes?
There are 45 questions on Surface areas and Volumes. Try the 4-question sample quiz on this page first; each answer shows an explanation when you tap it.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.

For serious students

Get the full Surface areas and Volumes chapter — start free.

Quizzes, flashcards, an AI doubt solver and a study plan for Karnataka Board Class 9 Mathematics. Free to start, no card needed.