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Chapter 9 of 12
Practice Quiz

Motion

Karnataka Board · Class 9 · Science

Practice quiz for Motion — Karnataka Board Class 9 Science. MCQs and questions with answers to test your preparation.

44 questions20 flashcards5 concepts

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Quick Quiz: Motion

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Tap an answer to check it instantly. No sign-up needed for these 4.

1

What is the SI unit of speed?

2

A car travels 100 km in 2 hours. What is its average speed?

3

Which of the following represents uniform motion?

4

What is the difference between distance and displacement?

44 Questions·
multiple choice

Sample Questions

1multiple choice
1 marks

The slope of a distance-time graph represents:

Show answer

Speed

Step 1: The slope of any graph is calculated as rise/run or change in y-axis/change in x-axis. Step 2: In a distance-time graph, y-axis represents distance and x-axis represents time. Step 3: Therefore, slope = change in distance/change in time = speed. Step 4: A steeper slope means higher speed, while a gentler slope means lower speed. Step 5: This graphical method helps us visualize and calculate speed easily from motion data.

2multiple choice
1 marks

Which equation represents the relationship between velocity, acceleration, and time?

Show answer

v = u + at

Step 1: The first equation of motion relates final velocity (v), initial velocity (u), acceleration (a), and time (t). Step 2: It states that final velocity equals initial velocity plus the change in velocity due to acceleration. Step 3: The term 'at' represents the change in velocity over time t with constant acceleration a. Step 4: Other equations relate position and velocity but not specifically velocity-acceleration-time relationship. Step 5: This equation is fundamental for solving problems involving uniformly accelerated motion.

3multiple choice
1 marks

A body starting from rest has an acceleration of 2 m/s². What will be its velocity after 5 seconds?

Show answer

10 m/s

Step 1: Use the first equation of motion: v = u + at. Step 2: Given values: u = 0 (starts from rest), a = 2 m/s², t = 5 s. Step 3: Substitute the values: v = 0 + (2 × 5) = 0 + 10 = 10 m/s. Step 4: The body accelerates uniformly, gaining 2 m/s of velocity every second. Step 5: After 5 seconds, total velocity gained = 2 × 5 = 10 m/s, which matches our calculation.

4multiple choice
1 marks

What type of motion does a freely falling object exhibit?

Show answer

Uniformly accelerated motion

Step 1: A freely falling object experiences constant gravitational acceleration (g ≈ 9.8 m/s²). Step 2: Since the acceleration is constant, the object's velocity increases by equal amounts in equal time intervals. Step 3: This constant acceleration defines uniformly accelerated motion. Step 4: The object starts from rest (or initial velocity) and continuously gains speed as it falls. Step 5: This is a perfect example of motion with constant acceleration, making calculations predictable using equations of motion.

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Frequently Asked Questions

What are the important topics in Motion for Karnataka Board Class 9 Science?
Motion covers several key topics that are frequently asked in Karnataka Board Class 9 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Motion — Karnataka Board Class 9 Science?
Understand the core concepts first, then work through the 44 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.

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