Commission Brokerage and Discount
Maharashtra Board · Class 12 · Mathematics & Statistics -Commerce
Summary of Commission Brokerage and Discount for Maharashtra Board Class 12 Mathematics & Statistics -Commerce. Key concepts, important points, and chapter overview.
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Overview
Differentiation is one of the fundamental concepts in calculus that deals with finding the rate of change of functions. This chapter extends your knowledge from basic differentiation to advanced techniques including composite functions, inverse functions, implicit functions, parametric functions, an
Key Concepts
For y = f(g(x))
For y = f(g(x)), dy/dx = f'(g(x)) × g'(x). Step-by-step approach: (1) Identify the outer function f and inner function g, (2) Find f'(g(x)), (3) Find
The derivative f'(a) represents the slope
The derivative f'(a) represents the slope of the tangent line to the curve y = f(x) at point (a, f(a)). Step-by-step visualization: (1) Draw the curve
If y = f(x) and x
If y = f(x) and x = f⁻¹(y), then dx/dy = 1/(dy/dx), provided dy/dx ≠ 0. Step-by-step method: (1) Express the inverse relationship, (2) Use the theorem
Used for functions of the form
Used for functions of the form y = [f(x)]^(g(x)) or complex products/quotients. Method: (1) Take natural log of both sides: log y = g(x)log[f(x)], (2)
Used when y is not explicitly
Used when y is not explicitly expressed as a function of x. Method: (1) Differentiate both sides with respect to x, (2) Treat y as a function of x (us
Learning Objectives
- Master the chain rule for differentiating composite functions like sin(x²), e^(tan x), and log(cos x)
- Understand the geometrical meaning of derivatives as slopes of tangent lines
- Apply the relationship dx/dy = 1/(dy/dx) for inverse functions and derive standard inverse trigonometric derivatives
- Use logarithmic differentiation for complex functions involving products, quotients, and exponential forms
- Differentiate implicit functions where y is not explicitly expressed in terms of x
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