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Commission Brokerage and Discount — Flashcards

Maharashtra Board · Class 12 · Mathematics & Statistics -Commerce

20 flashcards for Commission Brokerage and Discount (Maharashtra Board Class 12 Mathematics & Statistics -Commerce) to test yourself on key terms.

43 questions20 flashcards6 formulas & key relations5 concepts

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20 Flashcards·
Composite FunctionsInverse FunctionsLogarithmic Differentiation
Card 1Composite Functions

What is the Chain Rule for differentiating composite functions? State the formula and explain when to use it.

Answer

Chain Rule Formula: If y = f(u) and u = g(x), then dy/dx = (dy/du) × (du/dx) Alternatively: If y = f[g(x)], then dy/dx = f'[g(x)] × g'(x) Use when: Differentiating functions within functions, like s…

Card 2Composite Functions

Differentiate y = √(x² + 5) using the chain rule. Show all steps.

Answer

Step 1: Identify functions - Outer function: √u where u = x² + 5 - Inner function: u = x² + 5 Step 2: Find derivatives - dy/du = 1/(2√u) = 1/(2√(x² + 5)) - du/dx = 2x Step 3: Apply chain rule dy/dx …

Card 3Inverse Functions

What is the formula for differentiating inverse functions? State the theorem and explain the geometric meaning.

Answer

Inverse Function Theorem: If y = f(x) is differentiable and dy/dx ≠ 0, and x = f⁻¹(y) exists, then: dx/dy = 1/(dy/dx) Geometric Meaning: - The slope of f⁻¹ at point (a,b) is the reciprocal of the sl…

Card 4Inverse Functions

Find the derivative of sin⁻¹(x). Derive it step by step using the inverse function theorem.

Answer

Given: y = sin⁻¹(x), where -1 ≤ x ≤ 1, -π/2 ≤ y ≤ π/2 Step 1: Express inverse relationship If y = sin⁻¹(x), then x = sin y Step 2: Differentiate x = sin y with respect to y dx/dy = cos y Step 3: Ap…

Card 5Inverse Functions

List the derivatives of all six inverse trigonometric functions with their domains.

Answer

1. d/dx[sin⁻¹(x)] = 1/√(1-x²), |x| < 1 2. d/dx[cos⁻¹(x)] = -1/√(1-x²), |x| < 1 3. d/dx[tan⁻¹(x)] = 1/(1+x²), x ∈ ℝ 4. d/dx[cot⁻¹(x)] = -1/(1+x²), x ∈ ℝ 5. d/dx[sec⁻¹(x)] = 1/(x√(x²-1)), |x| > 1 …

Card 6Inverse Functions

Differentiate y = tan⁻¹(2x/(1-x²)) and simplify your answer.

Answer

Method 1: Direct differentiation dy/dx = 1/(1+(2x/(1-x²))²) × d/dx[2x/(1-x²)] Using quotient rule for 2x/(1-x²): d/dx[2x/(1-x²)] = [2(1-x²) - 2x(-2x)]/(1-x²)² = (2+2x²)/(1-x²)² Therefore: dy/dx = 2/…

Card 7Logarithmic Differentiation

When should you use logarithmic differentiation? List the conditions and explain the process.

Answer

Use logarithmic differentiation when: 1. Function has form y = [f(x)]^g(x) (variable base and exponent) 2. Products/quotients with multiple terms and powers 3. Complex expressions with roots, powers, …

Card 8Logarithmic Differentiation

Differentiate y = x^x using logarithmic differentiation. Show complete steps.

Answer

Step 1: Take natural log of both sides ln y = ln(x^x) = x ln x Step 2: Differentiate both sides with respect to x d/dx(ln y) = d/dx(x ln x) Step 3: Left side using chain rule (1/y)(dy/dx) = d/dx(x l…

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Frequently Asked Questions

What are the important topics in Commission Brokerage and Discount for Maharashtra Board Class 12 Mathematics & Statistics -Commerce?
Key topics in Commission Brokerage and Discount include Derivatives of Composite Functions (Chain Rule), Derivatives of Inverse Functions, Logarithmic Differentiation, Derivatives of Implicit Functions. Study these first, then practise questions on each for the Maharashtra Board Class 12 board exam.
How many flashcards are available for Commission Brokerage and Discount?
There are 20 flashcards for Commission Brokerage and Discount covering key definitions, facts and ideas. A few sample cards are shown on this page.
How should I revise Commission Brokerage and Discount for the Maharashtra Board Class 12 board exam?
Learn the core ideas first, then work through the 43 practice questions on Commission Brokerage and Discount. Revise definitions regularly and use flashcards for quick recall before the exam.

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