Kinetic Theory
Madhya Pradesh Board · Class 11 · Physics
Flashcards for Kinetic Theory — Madhya Pradesh Board Class 11 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.
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State Boyle's law for a fixed mass of gas at constant temperature.
Answer
For a fixed mass of gas at constant temperature, pressure varies inversely with volume. Formula: PV = constant. If volume decreases, pressure increases so that PV stays constant. Units: P in pascal, V…
स्थिर तापमान पर गैस के नियत द्रव्यमान के लिए बॉयल का नियम बताइए।
Answer
स्थिर तापमान पर गैस के नियत द्रव्यमान के लिए, दाब आयतन के व्युत्क्रमानुपाती होता है। सूत्र: PV = constant. यदि आयतन घटता है, तो दाब बढ़ता है ताकि PV स्थिर रहे। इकाइयाँ: P पास्कल में, V घन मीटर में।…
चार्ल्स का नियम बताइए।
Answer
नियत दाब पर, किसी गैस का आयतन उसके परम ताप T के समानुपाती होता है। सूत्र: V ∝ T. यदि T दोगुना हो जाता है, तो V भी दोगुना हो जाता है। तापमान केल्विन में होना चाहिए।…
State Charles' law.
Answer
For a fixed pressure, the volume of a gas is proportional to its absolute temperature T. Formula: V ∝ T. If T doubles, V also doubles. Temperature must be in kelvin.
State Avogadro's law.
Answer
Equal volumes of all gases at equal temperature and pressure have the same number of molecules. This is why one mole of any ideal gas occupies the same volume at STP.
अवोगाद्रो का नियम बताइए।
Answer
समान तापमान और दाब पर सभी गैसों के समान आयतन में अणुओं की संख्या समान होती है। यही कारण है कि किसी भी आदर्श गैस का 1 मोल STP पर समान आयतन घेरता है।…
एक गैस नमूने का दाब 1.0 × 10^5 Pa, आयतन 2.0 × 10^-3 m^3, और तापमान 300 K है। यदि गैस की मात्रा 0.08 mol है, तो आदर्श गैस समीकरण में प्रयुक्त गैस स्थिरांक का मान ज्ञात कीजिए।
Answer
दिया है: P = 1.0 × 10^5 Pa, V = 2.0 × 10^-3 m^3, T = 300 K, μ = 0.08 mol सूत्र: PV = μRT चरण 1: PV = (1.0 × 10^5)(2.0 × 10^-3) = 200 J चरण 2: μT = 0.08 × 300 = 24 mol K चरण 3: R = PV / (μT) = 200 / 24…
A gas sample has pressure 1.0 × 10^5 Pa, volume 2.0 × 10^-3 m^3, and temperature 300 K. If the amount of gas is 0.08 mol, find the gas constant value used by the ideal gas equation.
Answer
Given: P = 1.0 × 10^5 Pa, V = 2.0 × 10^-3 m^3, T = 300 K, μ = 0.08 mol Formula: PV = μRT Step 1: PV = (1.0 × 10^5)(2.0 × 10^-3) = 200 J Step 2: μT = 0.08 × 300 = 24 mol K Step 3: R = PV / (μT) = 200 /…
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