Quadratic Equations and Linear Inequalities
NIOS · Class 12 · Mathematics
Flashcards for Quadratic Equations and Linear Inequalities — NIOS Class 12 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.
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Explore the full setSolve the quadratic equation: 6x² + 5x - 6 = 0 using factorization method
Answer
Step 1: Write the equation: 6x² + 5x - 6 = 0 Step 2: Split middle term 5x into two parts whose product = 6 × (-6) = -36 and sum = 5. Use +9x and -4x Step 3: 6x² + 9x - 4x - 6 = 0 Step 4: Factor by gro…
When should you use the Quadratic Formula instead of factorization? Give an example where factorization is difficult.
Answer
Use the Quadratic Formula when: (1) The quadratic expression doesn't factor easily over integers, (2) Coefficients are large, (3) Roots are irrational or complex, (4) You need to verify the nature of …
Find the discriminant and nature of roots for: 9y² - 6√2y + 2 = 0
Answer
Step 1: Identify coefficients: a = 9, b = -6√2, c = 2 Step 2: Apply discriminant formula D = b² - 4ac Step 3: D = (-6√2)² - 4(9)(2) Step 4: D = 36(2) - 72 = 72 - 72 = 0 Step 5: Since D = 0, the equati…
What is the relationship between the roots (α, β) and coefficients (a, b, c) of ax² + bx + c = 0? Give a quick example.
Answer
Relationships (Vieta's Formulas): (1) Sum of roots: α + β = -b/a (2) Product of roots: αβ = c/a Example: For 3x² - 5x + 9 = 0 where a=3, b=-5, c=9: α + β = -(-5)/3 = 5/3 αβ = 9/3 = 3 Why it matters:…
Form a quadratic equation whose roots are α² and β², given that α and β are roots of 3y² + 4y + 1 = 0
Answer
Step 1: From 3y² + 4y + 1 = 0, find sum and product of original roots: α + β = -4/3 αβ = 1/3 Step 2: Calculate new sum (α² + β²): α² + β² = (α + β)² - 2αβ = (-4/3)² - 2(1/3) = 16/9 - 2/3 = 16/9 - 6/9…
Solve: √2t² - 3t + 3√2 = 0. Determine the nature of roots WITHOUT solving completely.
Answer
Step 1: Identify coefficients: a = √2, b = -3, c = 3√2 Step 2: Calculate discriminant D = b² - 4ac Step 3: D = (-3)² - 4(√2)(3√2) = 9 - 4(3)(2) = 9 - 24 = -15 Step 4: Since D = -15 < 0, roots are COMP…
Solve the inequality: (3x - 4)/2 ≥ (x + 1)/4 - 1. Show the solution on a number line.
Answer
Step 1: Simplify RHS: (x + 1)/4 - 1 = (x + 1)/4 - 4/4 = (x + 1 - 4)/4 = (x - 3)/4 So inequality becomes: (3x - 4)/2 ≥ (x - 3)/4 Step 2: Multiply both sides by 4 (positive, no sign change): 2(3x - 4) …
A student has marks 62 and 48 in two exams. What minimum marks in the annual exam to get an average of at least 60?
Answer
Step 1: Let x = marks in annual exam Step 2: Set up the inequality for average ≥ 60: (62 + 48 + x)/3 ≥ 60 Step 3: Simplify: (110 + x)/3 ≥ 60 Step 4: Multiply both sides by 3 (positive): 110 + x ≥ 18…
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