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Continuity and Differentiability

Punjab Board · Class 12 · Mathematics

Flashcards for Continuity and Differentiability — Punjab Board Class 12 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

44 questions25 flashcards5 concepts

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A graph of a continuous function at a specific point, showing the limit approaching the function value, illustrating that the function is unbroken and defined at that point.
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25 Flashcards
Card 1Continuity at a Point

Check if f(x) = 2x + 3 is continuous at x = 1.

Answer

To check continuity at x = 1, verify that lim(x→1) f(x) = f(1). Step 1: Find f(1) = 2(1) + 3 = 5 Step 2: Find lim(x→1) f(x) = lim(x→1) (2x + 3) = 2(1) + 3 = 5 Step 3: Compare: lim(x→1) f(x) = 5 = f

Card 2Continuity at a Point

Show that f(x) = |x| is continuous at x = 0.

Answer

For f(x) = |x| = {-x if x < 0; x if x ≥ 0}, check continuity at x = 0. Step 1: Find f(0) = |0| = 0 Step 2: Find left-hand limit: lim(x→0⁻) f(x) = lim(x→0⁻) (-x) = 0 Step 3: Find right-hand limit: l

Card 3Continuity - Special Functions

Find all points of discontinuity of f(x) = [x] (greatest integer function) on [0, 3).

Answer

For f(x) = [x], analyze at each integer point in [0, 3). At x = 0: - Left limit: lim(x→0⁻) [x] doesn't exist in domain - Right limit: lim(x→0⁺) [x] = 0 - f(0) = 0 → Continuous At x = 1: - Left limit

Card 4Continuity - Finding Constants

Find the value of k so that f(x) = {kx² if x ≤ 2; 3 if x > 2} is continuous at x = 2.

Answer

For continuity at x = 2, we need lim(x→2⁻) f(x) = lim(x→2⁺) f(x) = f(2). Step 1: Find left-hand limit: lim(x→2⁻) f(x) = lim(x→2⁻) kx² = k(2)² = 4k Step 2: Find right-hand limit: lim(x→2⁺) f(x) = 3 (

Card 5Continuity Concepts

When do you use the definition of continuity? Give the three-part condition.

Answer

Use the continuity definition when asked to verify or prove a function is continuous at a point c. The THREE CONDITIONS that must ALL be satisfied: 1. f(c) must be defined (the function exists at x

Card 6Differentiability

Prove that f(x) = |x| is NOT differentiable at x = 0.

Answer

To show non-differentiability, prove the left and right derivatives are not equal. For f(x) = |x| = {-x if x < 0; x if x ≥ 0} Step 1: Find left-hand derivative at x = 0: f'(0⁻) = lim(h→0⁻) [f(0+h) -

Card 7Continuity and Differentiability

What is the relationship between continuity and differentiability? (Theorem 3)

Answer

THEOREM: If f is differentiable at c, then f is continuous at c. Important understanding: - Differentiability IMPLIES continuity - Continuous ≠ Differentiable (converse is FALSE) In symbols: f'(c) e

Card 8Chain Rule

Apply the Chain Rule to find d/dx[sin(x²)].

Answer

The Chain Rule: If f = v∘u, then df/dx = (dv/dt)(dt/dx) where t = u(x). For f(x) = sin(x²): Step 1: Identify composition - Inner function: u(x) = x² - Outer function: v(t) = sin(t) - Therefore: f(x)

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What are the important topics in Continuity and Differentiability for Punjab Board Class 12 Mathematics?
Key topics in Continuity and Differentiability include Chapter 5: Continuity and Differentiability – Complete Overview, Decision Tree for Choosing Differentiation Method, Continuity and Differentiability – Complete Chapter Overview. These are the concepts Punjab Board Class 12 examiners draw on most — study them first, then practise related questions.
How to score full marks in Continuity and Differentiability — Punjab Board Class 12 Mathematics?
Understand the core concepts first, then work through the 44 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Continuity and Differentiability?
There are 25 flashcards for Continuity and Differentiability covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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