Punjab Board Class 12 Mathematics — Flashcards
Punjab Board Class 12 Mathematics flashcards, chapter by chapter — 125 flashcards across 5 chapters. Follows the PSEB syllabus.
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- Check the answer — mark the cards you got wrong.
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- Little and often — short daily sessions beat long cramming sessions.
Chapter-Wise Flashcards — 5 Chapters
Q: Determine if relation R = {(a,b) : a - b = 10} in set A = {1,2,3,4} is reflexive, symmetric, or transitive.
A: Step 1: Check reflexivity - Does (a,a) ∈ R for all a? Test (1,1): 1-1=0≠10. So NOT reflexive. Step 2: Check symmetry - If (a,b) ∈ R, is (b,a) ∈ R? Since no pairs exist in R (no two elements differ by
Q: Show that R = {(a,b) : 2 divides (a-b)} in set Z is an equivalence relation.
A: Step 1: Reflexivity - Does 2 divide (a-a) = 0? YES, 0 is divisible by 2. ✓ Step 2: Symmetry - If (a,b) ∈ R, then 2|(a-b). Does 2|(b-a)? Since (b-a) = -(a-b) and 2 divides (a-b), it divides -(a-b). So
Q: Verify if relation R = {(L₁, L₂) : L₁ is perpendicular to L₂} in set L of all lines is reflexive, symmetric, or transitive.
A: Step 1: Reflexivity - Can a line be perpendicular to itself? NO. (L₁, L₁) ∉ R. NOT reflexive. Step 2: Symmetry - If L₁ ⊥ L₂, is L₂ ⊥ L₁? YES, perpendicularity is mutual. (L₁, L₂) ∈ R ⟹ (L₂, L₁) ∈ R.
Q: Find the principal value of sin⁻¹(1/√2)
A: Step 1: Let y = sin⁻¹(1/√2). Then sin(y) = 1/√2 Step 2: The principal value branch of sin⁻¹ has range [-π/2, π/2] Step 3: Find angle in [-π/2, π/2] where sin equals 1/√2 Step 4: sin(π/4) = 1/√2 Step 5
Q: Find the principal value of cos⁻¹(-1/2)
A: Step 1: Let y = cos⁻¹(-1/2). Then cos(y) = -1/2 Step 2: Principal value branch of cos⁻¹ has range [0, π] Step 3: Find angle in [0, π] where cosine equals -1/2 Step 4: cos(2π/3) = -1/2 (since cos(π/3)
Q: Find the principal value of tan⁻¹(-√3)
A: Step 1: Let y = tan⁻¹(-√3). Then tan(y) = -√3 Step 2: Principal value branch of tan⁻¹ has range (-π/2, π/2) Step 3: tan(π/3) = √3, so tan(-π/3) = -√3 Step 4: -π/3 lies in (-π/2, π/2) ✓ Step 5: Therefo
Q: Find the order of matrix A = [[2, 5, 19, -7], [35, -2, 5/2, 12], [√3, 1, -5, 17]]
A: Step 1: Count the number of rows = 3 Step 2: Count the number of columns = 4 Step 3: Order of matrix = m × n = 3 × 4 Answer: The matrix A is of order 3 × 4 (read as 3 by 4)
Q: If a matrix has 24 elements, what are all possible orders it can have?
A: Step 1: If matrix has order m × n, then total elements = m × n = 24 Step 2: Find all factor pairs of 24: - 1 × 24 - 24 × 1 - 2 × 12 - 12 × 2 - 3 × 8 - 8 × 3 - 4 × 6 - 6 × 4 Answer: Po
Q: Construct a 2 × 2 matrix A = [aᵢⱼ] where aᵢⱼ = (i + j)²/2
A: Step 1: Set up general form: A = [[a₁₁, a₁₂], [a₂₁, a₂₂]] Step 2: Calculate each element: - a₁₁ = (1 + 1)²/2 = 4/2 = 2 - a₁₂ = (1 + 2)²/2 = 9/2 - a₂₁ = (2 + 1)²/2 = 9/2 - a₂₂ = (2 + 2)²/2 = 1
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Where can I find Punjab Board Class 12 Mathematics Flashcards?
This page has flashcards for 5 chapters of Punjab Board Class 12 Mathematics for the board exams 2027. Each chapter links to its own page with the full set.
How should I prepare for Punjab Board Class 12 Mathematics board exams?
Go through the syllabus first, then work chapter by chapter: learn the ideas, practise questions, and revise with notes and flashcards. Leave time at the end to revise every chapter once more under timed conditions.
How do I use flashcards for Punjab Board Class 12 Mathematics?
Read the question side, answer it in your head, then check. Put the cards you got wrong back into the pile and review them again the next day. Short daily sessions work better than long ones.
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Punjab Board Class 12
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