Linear Equations in Two variables — Practice Quiz
Telangana Board · Class 9 · Mathematics
4 MCQs on Linear Equations in Two variables for Telangana Board Class 9 Mathematics: tap an answer to check it and see why.
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Quick Quiz: Linear Equations in Two variables
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If the cost of 3 notebooks is ₹x and the cost of 2 pens is ₹y, and the total cost is ₹45, which linear equation represents this situation?
Which of the following is a solution to the equation 2x + 3y = 12?
If x = 2 and y = -1 is a solution to the equation 3x + ky = 5, find the value of k.
The equation x - 3y = 6 can be written in the form ax + by + c = 0. What are the values of a, b, and c?
Sample Questions
How many solutions does the linear equation 2x + 5y = 10 have?
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Infinitely many solutions
Step 1: A linear equation in two variables has the form ax + by + c = 0. Step 2: For any linear equation in two variables (where both coefficients are non-zero), there are infinitely many solutions. Step 3: We can choose any value for x and find the corresponding y, or vice versa. Step 4: For example, if x = 0, then y = 2; if x = 5, then y = 0; if x = 2.5, then y = 1, etc. Step 5: Therefore, 2x + 5y = 10 has infinitely many solutions.
Find the value of x when y = 0 for the equation 4x - 3y = 12.
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x = 3
Step 1: Given equation is 4x - 3y = 12 and y = 0. Step 2: Substitute y = 0 into the equation: 4x - 3(0) = 12. Step 3: Simplify: 4x - 0 = 12, so 4x = 12. Step 4: Solve for x: x = 12/4 = 3. Step 5: Verify: 4(3) - 3(0) = 12 - 0 = 12 ✓. Therefore, x = 3.
The graph of which equation passes through the origin (0, 0)?
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2x - 3y = 0
Step 1: For a line to pass through origin (0, 0), the point (0, 0) must satisfy the equation. Step 2: Test each option by substituting x = 0 and y = 0. Step 3: For 2x - 3y = 0: 2(0) - 3(0) = 0 - 0 = 0 ✓. Step 4: For x + y = 5: 0 + 0 = 0 ≠ 5. Step 5: The other options also don't equal their right-hand side when substituting (0, 0). Therefore, 2x - 3y = 0 passes through the origin.
The equation of a line parallel to the x-axis and passing through the point (3, -2) is:
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y = -2
Step 1: A line parallel to x-axis has the form y = k, where k is a constant. Step 2: All points on such a line have the same y-coordinate. Step 3: Since the line passes through (3, -2), all points have y-coordinate = -2. Step 4: Therefore, the equation is y = -2. Step 5: Verify: The point (3, -2) satisfies y = -2 since the y-coordinate is -2.
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