Coordinate Geometry — Flashcards
CBSE · Class 11 · Applied Mathematics
25 flashcards for Coordinate Geometry (CBSE Class 11 Applied Mathematics) to test yourself on key terms and facts.
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What is the slope of a line and how is it calculated for a line passing through two points?
Answer
The slope (m) of a line is tan θ, where θ is the inclination angle with the positive x-axis. For a line passing through points (x₁, y₁) and (x₂, y₂): m = (y₂ - y₁)/(x₂ - x₁). The slope represents the …
State the condition for two lines to be parallel and perpendicular in terms of their slopes.
Answer
Parallel lines: m₁ = m₂ (slopes are equal). Perpendicular lines: m₁ × m₂ = -1 (product of slopes equals -1). Note: This applies only to non-vertical lines.
Write the point-slope form of a line equation and when to use it.
Answer
Point-slope form: y - y₁ = m(x - x₁), where m is the slope and (x₁, y₁) is a known point on the line. Use this form when you know the slope and one point on the line.
What is the slope-intercept form of a line equation?
Answer
Slope-intercept form: y = mx + c, where m is the slope and c is the y-intercept (the point where the line crosses the y-axis). This is useful when you know the slope and y-intercept.
Write the intercept form of a line equation and its application.
Answer
Intercept form: x/a + y/b = 1, where 'a' is the x-intercept and 'b' is the y-intercept. Use this when you know both intercepts. The line passes through points (a, 0) and (0, b).
What is the normal form of a line equation?
Answer
Normal form: x cos α + y sin α = p, where p is the perpendicular distance from origin to the line and α is the angle the perpendicular makes with the positive x-axis (0° ≤ α < 360°).
What is the general form of a line equation and what conditions must it satisfy?
Answer
General form: Ax + By + C = 0, where A² + B² ≠ 0 (A and B cannot both be zero simultaneously). This represents a straight line for any values of A, B, C satisfying this condition.
Derive the formula for the distance of a point from a line.
Answer
Distance from point (x₁, y₁) to line Ax + By + C = 0 is: d = |Ax₁ + By₁ + C|/√(A² + B²). The absolute value ensures distance is always positive.
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Sources & Official References
- NCERT Official — ncert.nic.in
- CBSE Academic — cbseacademic.nic.in
- CBSE Official — cbse.gov.in
- National Education Policy 2020 — education.gov.in
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