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Dual Nature of Radiation and Matter — Flashcards

CBSE · Class 12 · Physics

60 flashcards for Dual Nature of Radiation and Matter (CBSE Class 12 Physics) to test yourself on key terms and facts.

109 questions60 flashcards6 formulas & key relations5 concepts

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An infographic comparing the three main types of electron emission: Thermionic emission, Field emission, and Photoelectric emission, highlighting the energy source for each.
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60 Flashcards·
फोटॉन ऊर्जाPhoton energyPhoton rateफोटॉन दरफोटॉन संवेगPhoton momentum
Card 1फोटॉन ऊर्जा

आवृत्ति 6.0 × 10^14 Hz वाला एक प्रकाश स्रोत विकिरण उत्सर्जित करता है। एक फोटॉन की ऊर्जा क्या है?

Answer

दिया गया: आवृत्ति ν = 6.0 × 10^14 Hz, प्लांक नियतांक h = 6.626 × 10^-34 J s सूत्र: E = hν चरण 1: E = (6.626 × 10^-34 J s)(6.0 × 10^14 s^-1) चरण 2: E = 3.976 × 10^-19 J उत्तर: प्रति फोटॉन 3.98 × 10^-19…

Card 2Photon energy

A light source of frequency 6.0 × 10^14 Hz emits radiation. What is the energy of one photon?

Answer

Given: frequency ν = 6.0 × 10^14 Hz, Planck's constant h = 6.626 × 10^-34 J s Formula: E = hν Step 1: E = (6.626 × 10^-34 J s)(6.0 × 10^14 s^-1) Step 2: E = 3.976 × 10^-19 J Answer: 3.98 × 10^-19 J pe…

Card 3Photon rate

A laser emits light of power 2.0 × 10^-3 W at frequency 6.0 × 10^14 Hz. How many photons are emitted per second on average?

Answer

Given: Power P = 2.0 × 10^-3 W, frequency ν = 6.0 × 10^14 Hz, h = 6.626 × 10^-34 J s Step 1: Energy of one photon, E = hν = (6.626 × 10^-34)(6.0 × 10^14) = 3.976 × 10^-19 J Step 2: Number of photons p…

Card 4फोटॉन दर

2.0 × 10^-3 W शक्ति वाला एक लेज़र 6.0 × 10^14 Hz आवृत्ति पर प्रकाश उत्सर्जित करता है। औसतन प्रति सेकंड कितने फोटॉन उत्सर्जित होते हैं?

Answer

दिया गया: शक्ति P = 2.0 × 10^-3 W, आवृत्ति ν = 6.0 × 10^14 Hz, h = 6.626 × 10^-34 J s चरण 1: एक फोटॉन की ऊर्जा, E = hν = (6.626 × 10^-34)(6.0 × 10^14) = 3.976 × 10^-19 J चरण 2: प्रति सेकंड फोटॉनों की …

Card 5फोटॉन संवेग

एक फोटॉन की आवृत्ति 5.0 × 10^14 Hz है। इसका संवेग ज्ञात कीजिए।

Answer

दिया गया: ν = 5.0 × 10^14 Hz, h = 6.626 × 10^-34 J s, c = 3.0 × 10^8 m/s सूत्र: p = hν/c चरण 1: p = (6.626 × 10^-34 × 5.0 × 10^14) / (3.0 × 10^8) चरण 2: p = 3.313 × 10^-19 / 3.0 × 10^8 चरण 3: p = 1.10…

Card 6Photon momentum

A photon has frequency 5.0 × 10^14 Hz. Find its momentum.

Answer

Given: ν = 5.0 × 10^14 Hz, h = 6.626 × 10^-34 J s, c = 3.0 × 10^8 m/s Formula: p = hν/c Step 1: p = (6.626 × 10^-34 × 5.0 × 10^14) / (3.0 × 10^8) Step 2: p = 3.313 × 10^-19 / 3.0 × 10^8 Step 3: p = 1.

Card 7Photon energy

A photon has wavelength 500 nm. Find its energy.

Answer

Given: λ = 500 nm = 500 × 10^-9 m, h = 6.626 × 10^-34 J s, c = 3.0 × 10^8 m/s Formula: E = hc/λ Step 1: E = (6.626 × 10^-34 × 3.0 × 10^8) / (500 × 10^-9) Step 2: E = 1.9878 × 10^-25 / 5.00 × 10^-7 Ste…

Card 8फोटॉन ऊर्जा

एक फोटॉन की तरंगदैर्घ्य 500 nm है। इसकी ऊर्जा ज्ञात कीजिए।

Answer

दिया गया: λ = 500 nm = 500 × 10^-9 m, h = 6.626 × 10^-34 J s, c = 3.0 × 10^8 m/s सूत्र: E = hc/λ चरण 1: E = (6.626 × 10^-34 × 3.0 × 10^8) / (500 × 10^-9) चरण 2: E = 1.9878 × 10^-25 / 5.00 × 10^-7 चरण …

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Frequently Asked Questions

What are the important topics in Dual Nature of Radiation and Matter for CBSE Class 12 Physics?
Key topics in Dual Nature of Radiation and Matter include Electron emission and work function, Photoelectric effect and experimental observations, Failure of wave theory and Einstein’s explanation, Photon nature of light. Study these first, then practise questions on each for the CBSE Class 12 board exam.
How many flashcards are available for Dual Nature of Radiation and Matter?
There are 60 flashcards for Dual Nature of Radiation and Matter covering key definitions, facts and ideas. A few sample cards are shown on this page.
How should I revise Dual Nature of Radiation and Matter for the CBSE Class 12 board exam?
Learn the core ideas first, then work through the 109 practice questions on Dual Nature of Radiation and Matter. Revise definitions regularly and use flashcards for quick recall before the exam.

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