Fractions in Disguise
CBSE · Class 8 · Mathematics
Practice quiz for Fractions in Disguise — CBSE Class 8 Mathematics. MCQs and questions with answers to test your preparation.
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Quick Quiz: Fractions in Disguise
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A sweater has a cost price of ₹300 and is sold for ₹430. What is the profit percentage on cost price?
A damaged vase costs ₹2650 and is sold at an 18% loss. What is the selling price?
A storekeeper adds a 50% profit margin on goods and then gives a 50% discount. If the cost price is ₹12,000, what selling price is obtained?
A bakery sells a cake for ₹200 after a 30% discount followed by a 20% discount. What is the final price?
Sample Questions
A retailer buys a car for ₹4,40,000 after a 15% discount. What was the original price of the car?
Show answer
₹5,17,647 approximately
A 15% discount means the car was bought at 85% of the original price. So original price = 440000 ÷ 0.85 = ₹5,17,647 approximately.
A fixed deposit of ₹6000 earns 10% p.a. for 3 years without compounding. What is the total amount?
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₹7800
Without compounding, amount = p(1 + rt). Here p = 6000, r = 0.10, t = 3. So amount = 6000(1 + 0.10×3) = 6000×1.3 = ₹7800.
A fixed deposit of ₹6000 earns 10% p.a. for 3 years with compounding annually. What is the total amount?
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₹7986
With compounding, amount = p × (1 + r)^t. So amount = 6000 × (1.1)^3 = 6000 × 1.331 = ₹7986.
A village population is 1250 and reduces by 10% each decade. What is the expected population after 3 decades, using the compounding method?
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About 911
Each decade the population becomes 90% of the previous one. So after 3 decades: 1250 × 0.9 × 0.9 × 0.9 = 1250 × 0.729 = 911.25, which is about 911.
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Sources & Official References
- NCERT Official — ncert.nic.in
- CBSE Academic — cbseacademic.nic.in
- CBSE Official — cbse.gov.in
- National Education Policy 2020 — education.gov.in
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