Linear Equations in one Variable — Practice Quiz
ICSE · Class 8 · Mathematics
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Quick Quiz: Linear Equations in one Variable
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A person is paid ₹150 for each day worked and fined ₹30 for each day absent. In 40 days, the total earning is ₹3,300. For how many days did the person work?
A man is 24 years older than his son. In 2 years, the man will be twice as old as the son. What is the present age of the man?
Two consecutive even numbers have a difference of squares equal to 92. If the smaller even number is x, what is the larger number?
A boy walks to school at 4 km/h and is 10 minutes late. The next day he runs at 8 km/h and is 5 minutes early. What is the distance between his house and school?
Sample Questions
Solve the equation and then find y from 1/x + 1/y = 3, where x is the solution of (2x + 1)/10 - (3 - 2x)/15 = (x - 2)/6. What is the value of y?
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7/26
First solve (2x + 1)/10 - (3 - 2x)/15 = (x - 2)/6. LCM of 10, 15, and 6 is 30. Multiply each term by 30: 3(2x + 1) - 2(3 - 2x) = 5(x - 2). 6x + 3 - 6 + 4x = 5x - 10. 10x - 3 = 5x - 10. 5x = -7. x = -7/5. Now use 1/x + 1/y = 3. 1/x = -5/7. So, -5/7 + 1/y = 3. 1/y = 3 + 5/7 = 26/7. y = 7/26.
A rectangle is 8 cm long and 5 cm wide. Its perimeter becomes double when each side is increased by x cm. What is the new length of the rectangle?
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14.5 cm
Original perimeter = 2(length + width) = 2(8 + 5) = 26 cm. After increasing each side by x cm, new length = 8 + x and new width = 5 + x. New perimeter = 2(8 + x + 5 + x) = 26 + 4x. Given: new perimeter is double the original perimeter. So, 26 + 4x = 2 × 26 = 52. 4x = 26. x = 6.5 cm. New length = 8 + 6.5 = 14.5 cm.
Solve 21 - 3(a - 7) = a + 20. What is the value of a?
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11/2
Expand the bracket: 21 - 3a + 21 = a + 20. So, 42 - 3a = a + 20. 42 - 20 = a + 3a. 22 = 4a. a = 22/4 = 11/2.
Solve (y + 2)/4 - (y - 3)/3 = 1/2. What is the value of y?
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12
LCM of 4, 3, and 2 is 12. Multiply each term by 12: 3(y + 2) - 4(y - 3) = 6. 3y + 6 - 4y + 12 = 6. -y + 18 = 6. -y = -12. y = 12.
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