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Pair of Linear Equations in Two Variables — Flashcards

Karnataka Board · Class 10 · Mathematics

20 flashcards for Pair of Linear Equations in Two Variables (Karnataka Board Class 10 Mathematics) to test yourself on key terms and facts.

44 questions20 flashcards4 formulas & key relations5 concepts

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20 Flashcards·
Substitution MethodElimination MethodGraphical AnalysisWord ProblemsSystem AnalysisSpecial CasesMethod Selection
Card 1Substitution Method

Solve by substitution method: x + y = 10 and 2x - y = 5

Answer

Step 1: From first equation: y = 10 - x Step 2: Substitute in second equation: 2x - (10 - x) = 5 Step 3: Simplify: 2x - 10 + x = 5 → 3x = 15 → x = 5 Step 4: Find y: y = 10 - 5 = 5 Answer: x = 5, y = 5…

Card 2Elimination Method

Solve by elimination method: 3x + 2y = 12 and 2x + 3y = 13

Answer

Step 1: Make coefficients equal. Multiply first by 3, second by 2: 9x + 6y = 36 ... (1) 4x + 6y = 26 ... (2) Step 2: Subtract (2) from (1): 5x = 10 → x = 2 Step 3: Substitute x = 2 in original: 3(2) +…

Card 3Graphical Analysis

Find the values of a₁/a₂, b₁/b₂, c₁/c₂ for: 2x + 3y - 6 = 0 and 4x + 6y - 12 = 0. What type of lines are these?

Answer

Given: 2x + 3y - 6 = 0 and 4x + 6y - 12 = 0 a₁ = 2, b₁ = 3, c₁ = -6 a₂ = 4, b₂ = 6, c₂ = -12 Step 1: Calculate ratios: a₁/a₂ = 2/4 = 1/2 b₁/b₂ = 3/6 = 1/2 c₁/c₂ = -6/-12 = 1/2 Step 2: Compare: a₁/a₂…

Card 4Word Problems

A shopkeeper has ₹50 and ₹100 notes totaling ₹4000. If he has 50 notes in total, find the number of each type of note.

Answer

Let x = number of ₹50 notes, y = number of ₹100 notes Step 1: Form equations: Total notes: x + y = 50 ... (1) Total value: 50x + 100y = 4000 ... (2) Step 2: From (1): x = 50 - y Step 3: Substitute i…

Card 5System Analysis

Check if the system has unique solution, no solution, or infinitely many solutions: x + 2y = 5 and 2x + 4y = 8

Answer

Given: x + 2y - 5 = 0 and 2x + 4y - 8 = 0 a₁ = 1, b₁ = 2, c₁ = -5 a₂ = 2, b₂ = 4, c₂ = -8 Step 1: Calculate ratios: a₁/a₂ = 1/2 b₁/b₂ = 2/4 = 1/2 c₁/c₂ = -5/-8 = 5/8 Step 2: Compare: a₁/a₂ = b₁/b₂ ≠…

Card 6Special Cases

Solve: 2/x + 3/y = 13 and 5/x - 4/y = -2 (where x ≠ 0, y ≠ 0)

Answer

Let u = 1/x and v = 1/y Transformed equations: 2u + 3v = 13 ... (1) 5u - 4v = -2 ... (2) Step 1: Multiply (1) by 4 and (2) by 3: 8u + 12v = 52 ... (3) 15u - 12v = -6 ... (4) Step 2: Add (3) and (4):…

Card 7Word Problems

The sum of two numbers is 25. The larger number is 3 more than twice the smaller number. Find both numbers.

Answer

Let x = smaller number, y = larger number Step 1: Form equations: x + y = 25 ... (1) y = 2x + 3 ... (2) Step 2: Substitute (2) into (1): x + (2x + 3) = 25 Step 3: Solve: 3x + 3 = 25 → 3x = 22 → x = …

Card 8Method Selection

When do you use elimination method instead of substitution method?

Answer

Use elimination method when: 1. Both equations have simple integer coefficients 2. Making coefficients equal is straightforward 3. Substitution leads to complex fractions Example: 2x + 3y = 7 and 3x …

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Frequently Asked Questions

What are the important topics in Pair of Linear Equations in Two Variables for Karnataka Board Class 10 Mathematics?
Key topics in Pair of Linear Equations in Two Variables include Basic Concepts and Definitions, Types of Solutions Based on Line Relationships, Graphical Method, Substitution Method. Study these first, then practise questions on each for the Karnataka Board Class 10 board exam.
How many flashcards are available for Pair of Linear Equations in Two Variables?
There are 20 flashcards for Pair of Linear Equations in Two Variables covering key definitions, facts and ideas. A few sample cards are shown on this page.
How should I revise Pair of Linear Equations in Two Variables for the Karnataka Board Class 10 board exam?
Learn the core ideas first, then work through the 44 practice questions on Pair of Linear Equations in Two Variables. Revise definitions regularly and use flashcards for quick recall before the exam.

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