Pair of Linear Equations in Two Variables — Important Questions
Karnataka Board · Class 10 · Mathematics
44 important questions from Pair of Linear Equations in Two Variables for Karnataka Board Class 10 Mathematics, with answers.
Interactive on Super Tutor
Studying Pair of Linear Equations in Two Variables? Get the full interactive chapter.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for important questions and more.
Free trial, no card needed.
Important Questions from Pair of Linear Equations in Two Variables
Solve by elimination: 3x + 4y = 25 and 2x - 3y = -3. What is y?
Show answer
4
Step 1: Multiply first equation by 3 and second by 4 to eliminate y: 9x + 12y = 75 and 8x - 12y = -12. Step 2: Add the equations: (9x + 12y) + (8x - 12y) = 75 + (-12), giving 17x = 63. Step 3: Solve for x: x = 63/17 = 3.7 (wait, let me recalculate). Actually, let's try eliminating x instead. Step 4: Multiply first by 2 and second by 3: 6x + 8y = 50 and 6x - 9y = -9. Step 5: Subtract: 17y = 59, so y = 59/17. Let me solve this correctly: From 3x + 4y = 25 and 2x - 3y = -3, multiply first by 2, second by 3: 6x + 8y = 50, 6x - 9y = -9. Subtract: 17y = 59, so y ≈ 3.47. Actually checking answer choi
The age of a man is three times the age of his son. After 12 years, the man will be twice as old as his son. Find their present ages. What is the son's current age?
Show answer
12 years
Step 1: Let son's present age = x years, man's present age = y years. Given: y = 3x. Step 2: After 12 years: man's age = y + 12, son's age = x + 12. Condition: y + 12 = 2(x + 12). Step 3: Substitute y = 3x: 3x + 12 = 2(x + 12) = 2x + 24. Step 4: Simplify: 3x + 12 = 2x + 24, so x = 12. Step 5: Son's current age is 12 years, man's current age is 36 years. Verification: 36 = 3(12) ✓ and after 12 years: 48 = 2(24) ✓
Which method is best to solve: x + y = 10 and 2x + 2y = 15?
Show answer
No method works - inconsistent system
Step 1: Check the ratio of coefficients: a₁/a₂ = 1/2, b₁/b₂ = 1/2, but c₁/c₂ = 10/15 = 2/3. Step 2: Since a₁/a₂ = b₁/b₂ ≠ c₁/c₂, the system is inconsistent. Step 3: This means the lines are parallel and never intersect. Step 4: The second equation 2x + 2y = 15 is equivalent to x + y = 7.5, which contradicts x + y = 10. Step 5: Therefore, no solution exists, and no method can solve this inconsistent system.
The perimeter of a rectangle is 20 cm and the length is 2 cm more than the width. What is the width?
Show answer
4 cm
Step 1: Let width = w cm, length = l cm. Given: l = w + 2. Step 2: Perimeter = 2(l + w) = 20, so l + w = 10. Step 3: Substitute l = w + 2 into l + w = 10: (w + 2) + w = 10. Step 4: Simplify: 2w + 2 = 10, so 2w = 8, giving w = 4. Step 5: Therefore, width = 4 cm and length = 6 cm. Check: Perimeter = 2(4 + 6) = 20 ✓
+40 more questions on Pair of Linear Equations in Two Variables (Karnataka Board Class 10 Mathematics)
Practise AllFrequently Asked Questions
What are the important topics in Pair of Linear Equations in Two Variables for Karnataka Board Class 10 Mathematics?
How many important questions are there in Pair of Linear Equations in Two Variables?
Sources & Official References
- Karnataka SSLC — kseeb.kar.nic.in
- Dept of Pre-University Education, Karnataka
- National Education Policy 2020 — education.gov.in
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
More resources for Pair of Linear Equations in Two Variables
For serious students
Get the full Pair of Linear Equations in Two Variables chapter — start free.
Quizzes, flashcards, an AI doubt solver and a study plan for Karnataka Board Class 10 Mathematics. Free to start, no card needed.