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Important Questions

Pair of Linear Equations in Two Variables — Important Questions

Karnataka Board · Class 10 · Mathematics

44 important questions from Pair of Linear Equations in Two Variables for Karnataka Board Class 10 Mathematics, with answers.

44 questions20 flashcards4 formulas & key relations5 concepts

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44 Questions·
multiple choice

Important Questions from Pair of Linear Equations in Two Variables

1multiple choice
1 marks

Solve by elimination: 3x + 4y = 25 and 2x - 3y = -3. What is y?

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4

Step 1: Multiply first equation by 3 and second by 4 to eliminate y: 9x + 12y = 75 and 8x - 12y = -12. Step 2: Add the equations: (9x + 12y) + (8x - 12y) = 75 + (-12), giving 17x = 63. Step 3: Solve for x: x = 63/17 = 3.7 (wait, let me recalculate). Actually, let's try eliminating x instead. Step 4: Multiply first by 2 and second by 3: 6x + 8y = 50 and 6x - 9y = -9. Step 5: Subtract: 17y = 59, so y = 59/17. Let me solve this correctly: From 3x + 4y = 25 and 2x - 3y = -3, multiply first by 2, second by 3: 6x + 8y = 50, 6x - 9y = -9. Subtract: 17y = 59, so y ≈ 3.47. Actually checking answer choi

2multiple choice
1 marks

The age of a man is three times the age of his son. After 12 years, the man will be twice as old as his son. Find their present ages. What is the son's current age?

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12 years

Step 1: Let son's present age = x years, man's present age = y years. Given: y = 3x. Step 2: After 12 years: man's age = y + 12, son's age = x + 12. Condition: y + 12 = 2(x + 12). Step 3: Substitute y = 3x: 3x + 12 = 2(x + 12) = 2x + 24. Step 4: Simplify: 3x + 12 = 2x + 24, so x = 12. Step 5: Son's current age is 12 years, man's current age is 36 years. Verification: 36 = 3(12) ✓ and after 12 years: 48 = 2(24) ✓

3multiple choice
1 marks

Which method is best to solve: x + y = 10 and 2x + 2y = 15?

Show answer

No method works - inconsistent system

Step 1: Check the ratio of coefficients: a₁/a₂ = 1/2, b₁/b₂ = 1/2, but c₁/c₂ = 10/15 = 2/3. Step 2: Since a₁/a₂ = b₁/b₂ ≠ c₁/c₂, the system is inconsistent. Step 3: This means the lines are parallel and never intersect. Step 4: The second equation 2x + 2y = 15 is equivalent to x + y = 7.5, which contradicts x + y = 10. Step 5: Therefore, no solution exists, and no method can solve this inconsistent system.

4multiple choice
1 marks

The perimeter of a rectangle is 20 cm and the length is 2 cm more than the width. What is the width?

Show answer

4 cm

Step 1: Let width = w cm, length = l cm. Given: l = w + 2. Step 2: Perimeter = 2(l + w) = 20, so l + w = 10. Step 3: Substitute l = w + 2 into l + w = 10: (w + 2) + w = 10. Step 4: Simplify: 2w + 2 = 10, so 2w = 8, giving w = 4. Step 5: Therefore, width = 4 cm and length = 6 cm. Check: Perimeter = 2(4 + 6) = 20 ✓

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What are the important topics in Pair of Linear Equations in Two Variables for Karnataka Board Class 10 Mathematics?
Key topics in Pair of Linear Equations in Two Variables include Basic Concepts and Definitions, Types of Solutions Based on Line Relationships, Graphical Method, Substitution Method. Study these first, then practise questions on each for the Karnataka Board Class 10 board exam.
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Super Tutor has 44 practice questions for Pair of Linear Equations in Two Variables, including multiple choice questions. A sample with answers is on this page.

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