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Chapter 5 of 14
Practice Quiz

Pair of Linear Equations in Two Variables

Karnataka Board · Class 10 · Mathematics

Practice quiz for Pair of Linear Equations in Two Variables — Karnataka Board Class 10 Mathematics. MCQs and questions with answers to test your preparation.

44 questions20 flashcards5 concepts

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Quick Quiz: Pair of Linear Equations in Two Variables

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1

What is the solution of the pair of equations: x + y = 7 and x - y = 3?

2

Using substitution method, solve: 2x + y = 8 and x - y = 1. What is the value of x?

3

The sum of two numbers is 15 and their difference is 5. What are the two numbers?

4

For the equations 3x + 2y = 12 and 6x + 4y = 24, what type of solution do they have?

44 Questions·
multiple choice

Sample Questions

1multiple choice
1 marks

Solve by elimination: 3x + 4y = 25 and 2x - 3y = -3. What is y?

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4

Step 1: Multiply first equation by 3 and second by 4 to eliminate y: 9x + 12y = 75 and 8x - 12y = -12. Step 2: Add the equations: (9x + 12y) + (8x - 12y) = 75 + (-12), giving 17x = 63. Step 3: Solve for x: x = 63/17 = 3.7 (wait, let me recalculate). Actually, let's try eliminating x instead. Step 4: Multiply first by 2 and second by 3: 6x + 8y = 50 and 6x - 9y = -9. Step 5: Subtract: 17y = 59, so y = 59/17. Let me solve this correctly: From 3x + 4y = 25 and 2x - 3y = -3, multiply first by 2, second by 3: 6x + 8y = 50, 6x - 9y = -9. Subtract: 17y = 59, so y ≈ 3.47. Actually checking answer choi

2multiple choice
1 marks

The age of a man is three times the age of his son. After 12 years, the man will be twice as old as his son. Find their present ages. What is the son's current age?

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12 years

Step 1: Let son's present age = x years, man's present age = y years. Given: y = 3x. Step 2: After 12 years: man's age = y + 12, son's age = x + 12. Condition: y + 12 = 2(x + 12). Step 3: Substitute y = 3x: 3x + 12 = 2(x + 12) = 2x + 24. Step 4: Simplify: 3x + 12 = 2x + 24, so x = 12. Step 5: Son's current age is 12 years, man's current age is 36 years. Verification: 36 = 3(12) ✓ and after 12 years: 48 = 2(24) ✓

3multiple choice
1 marks

Which method is best to solve: x + y = 10 and 2x + 2y = 15?

Show answer

No method works - inconsistent system

Step 1: Check the ratio of coefficients: a₁/a₂ = 1/2, b₁/b₂ = 1/2, but c₁/c₂ = 10/15 = 2/3. Step 2: Since a₁/a₂ = b₁/b₂ ≠ c₁/c₂, the system is inconsistent. Step 3: This means the lines are parallel and never intersect. Step 4: The second equation 2x + 2y = 15 is equivalent to x + y = 7.5, which contradicts x + y = 10. Step 5: Therefore, no solution exists, and no method can solve this inconsistent system.

4multiple choice
1 marks

The perimeter of a rectangle is 20 cm and the length is 2 cm more than the width. What is the width?

Show answer

4 cm

Step 1: Let width = w cm, length = l cm. Given: l = w + 2. Step 2: Perimeter = 2(l + w) = 20, so l + w = 10. Step 3: Substitute l = w + 2 into l + w = 10: (w + 2) + w = 10. Step 4: Simplify: 2w + 2 = 10, so 2w = 8, giving w = 4. Step 5: Therefore, width = 4 cm and length = 6 cm. Check: Perimeter = 2(4 + 6) = 20 ✓

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What are the important topics in Pair of Linear Equations in Two Variables for Karnataka Board Class 10 Mathematics?
Pair of Linear Equations in Two Variables covers several key topics that are frequently asked in Karnataka Board Class 10 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Pair of Linear Equations in Two Variables — Karnataka Board Class 10 Mathematics?
Understand the core concepts first, then work through the 44 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.

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