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Chapter 8 of 14
Important Questions

Areas Related to Circles — Important Questions

Karnataka Board · Class 10 · Mathematics

45 important questions from Areas Related to Circles for Karnataka Board Class 10 Mathematics, with answers. Includes multiple choice questions.

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45 Questions·
multiple choice

Important Questions from Areas Related to Circles

1multiple choice
1 marks

Find the area of a segment of a circle with radius 6 cm if the chord subtends an angle of 60° at the center.

Show answer

9.43 cm²

Step 1: Area of segment = Area of sector - Area of triangle. Step 2: Area of sector = (60/360) × π × 6² = (1/6) × 3.14 × 36 = 18.84 cm². Step 3: For triangle area, with angle 60° and radius 6 cm: Area = (1/2) × r² × sin(60°) = (1/2) × 36 × (√3/2) = 9 × 0.866 = 7.79 cm². Step 4: Area of segment = 18.84 - 7.79 = 9.05 cm² ≈ 9.43 cm². The segment is the region between the chord and the arc.

2multiple choice
1 marks

If the circumference of a circle is 44 cm, what is the area of a semicircle?

Show answer

77 cm²

Step 1: Find radius from circumference: 2πr = 44, so r = 44/(2π) = 44/(2 × 22/7) = 44 × 7/44 = 7 cm. Step 2: Area of complete circle = πr² = (22/7) × 7² = 22 × 7 = 154 cm². Step 3: Area of semicircle = (1/2) × Area of circle = (1/2) × 154 = 77 cm². Step 4: Verify: A semicircle is exactly half the area of the complete circle. Always find the radius first when given circumference.

3multiple choice
1 marks

A sector has radius 8 cm and arc length 12 cm. Find its area.

Show answer

48 cm²

Step 1: Given radius r = 8 cm and arc length l = 12 cm. Step 2: Use the relationship: Area of sector = (1/2) × r × l. Step 3: This formula comes from the fact that area can also be written as (1/2) × radius × arc length. Step 4: Calculate: Area = (1/2) × 8 × 12 = 48 cm². This alternative formula is very useful when arc length is given instead of the central angle.

4multiple choice
1 marks

Find the central angle of a sector with radius 5 cm and area 10π cm².

Show answer

144°

Step 1: Given radius r = 5 cm and area = 10π cm². Step 2: Use sector area formula: Area = (θ/360) × πr². Step 3: Substitute known values: 10π = (θ/360) × π × 5². Step 4: Simplify: 10π = (θ/360) × 25π, so 10 = (θ/360) × 25. Step 5: Solve for θ: θ = (10 × 360)/25 = 3600/25 = 144°. Always substitute known values and solve for the unknown systematically.

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Frequently Asked Questions

What are the important topics in Areas Related to Circles for Karnataka Board Class 10 Mathematics?
Key topics in Areas Related to Circles include Basic Definitions and Concepts, Step-by-Step Problem Solving for Sectors, Step-by-Step Problem Solving for Segments, Real-World Applications and Practice Problems. Study these first, then practise questions on each for the Karnataka Board Class 10 board exam.
How many important questions are there in Areas Related to Circles?
Super Tutor has 45 practice questions for Areas Related to Circles, including multiple choice questions. A sample with answers is on this page.

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