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Chapter 8 of 14
Important Questions

Areas Related to Circles

Karnataka Board · Class 10 · Mathematics

Most important questions from Areas Related to Circles for Karnataka Board Class 10 Mathematics board exam 2026. MCQs, short answer, and long answer questions with marks.

45 questions20 flashcards5 concepts

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45 Questions·
multiple choice

Sample Questions

1multiple choice
1 marks

Find the area of a segment of a circle with radius 6 cm if the chord subtends an angle of 60° at the center.

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9.43 cm²

Step 1: Area of segment = Area of sector - Area of triangle. Step 2: Area of sector = (60/360) × π × 6² = (1/6) × 3.14 × 36 = 18.84 cm². Step 3: For triangle area, with angle 60° and radius 6 cm: Area = (1/2) × r² × sin(60°) = (1/2) × 36 × (√3/2) = 9 × 0.866 = 7.79 cm². Step 4: Area of segment = 18.84 - 7.79 = 9.05 cm² ≈ 9.43 cm². The segment is the region between the chord and the arc.

2multiple choice
1 marks

If the circumference of a circle is 44 cm, what is the area of a semicircle?

Show answer

77 cm²

Step 1: Find radius from circumference: 2πr = 44, so r = 44/(2π) = 44/(2 × 22/7) = 44 × 7/44 = 7 cm. Step 2: Area of complete circle = πr² = (22/7) × 7² = 22 × 7 = 154 cm². Step 3: Area of semicircle = (1/2) × Area of circle = (1/2) × 154 = 77 cm². Step 4: Verify: A semicircle is exactly half the area of the complete circle. Always find the radius first when given circumference.

3multiple choice
1 marks

A sector has radius 8 cm and arc length 12 cm. Find its area.

Show answer

48 cm²

Step 1: Given radius r = 8 cm and arc length l = 12 cm. Step 2: Use the relationship: Area of sector = (1/2) × r × l. Step 3: This formula comes from the fact that area can also be written as (1/2) × radius × arc length. Step 4: Calculate: Area = (1/2) × 8 × 12 = 48 cm². This alternative formula is very useful when arc length is given instead of the central angle.

4multiple choice
1 marks

Find the central angle of a sector with radius 5 cm and area 10π cm².

Show answer

144°

Step 1: Given radius r = 5 cm and area = 10π cm². Step 2: Use sector area formula: Area = (θ/360) × πr². Step 3: Substitute known values: 10π = (θ/360) × π × 5². Step 4: Simplify: 10π = (θ/360) × 25π, so 10 = (θ/360) × 25. Step 5: Solve for θ: θ = (10 × 360)/25 = 3600/25 = 144°. Always substitute known values and solve for the unknown systematically.

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Frequently Asked Questions

What are the important topics in Areas Related to Circles for Karnataka Board Class 10 Mathematics?
Areas Related to Circles covers several key topics that are frequently asked in Karnataka Board Class 10 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Areas Related to Circles — Karnataka Board Class 10 Mathematics?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many important questions are there in Areas Related to Circles?
There are 45 practice questions available for Areas Related to Circles. These cover multiple question types including MCQs, short answer, and long answer questions.

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