Skip to main content
Chapter 10 of 14
Important Questions

Surface Areas and Volumes — Important Questions

Karnataka Board · Class 10 · Mathematics

45 important questions from Surface Areas and Volumes for Karnataka Board Class 10 Mathematics, with answers. Includes multiple choice questions.

45 questions20 flashcards4 concepts

Interactive on Super Tutor

Studying Surface Areas and Volumes? Get the full interactive chapter.

Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for important questions and more.

Free trial, no card needed.

45 Questions·
multiple choice

Important Questions from Surface Areas and Volumes

1multiple choice
1 marks

A sphere has radius 9 cm. What is its volume?

Show answer

3053.6 cm³

Step 1: Given radius r = 9 cm. Step 2: For a sphere, volume = (4/3)πr³. Step 3: Substitute values: Volume = (4/3) × (22/7) × 9³ = (4/3) × (22/7) × 729. Step 4: Calculate: Volume = (4 × 22 × 729)/(3 × 7) = 64152/21 = 3053.6 cm³. Remember to cube the radius first.

2multiple choice
1 marks

A cylinder has radius 4 cm and height 15 cm. What is its volume?

Show answer

754.3 cm³

Step 1: Given radius r = 4 cm and height h = 15 cm. Step 2: For a cylinder, volume = πr²h. Step 3: Substitute values: Volume = (22/7) × 4² × 15 = (22/7) × 16 × 15. Step 4: Calculate: Volume = (22 × 240)/7 = 5280/7 = 754.3 cm³. The volume is the area of the circular base times the height.

3multiple choice
1 marks

A cone has base radius 6 cm and height 8 cm. What is its volume?

Show answer

301.7 cm³

Step 1: Given radius r = 6 cm and height h = 8 cm. Step 2: For a cone, volume = (1/3)πr²h. Step 3: Substitute values: Volume = (1/3) × (22/7) × 6² × 8 = (1/3) × (22/7) × 36 × 8. Step 4: Calculate: Volume = (22 × 288)/(3 × 7) = 6336/21 = 301.7 cm³. Cone volume is one-third of cylinder volume with same base and height.

4multiple choice
1 marks

A toy consists of a cylinder with a hemisphere on top. Both have radius 3 cm, and the cylinder has height 10 cm. What is the total surface area?

Show answer

244.3 cm²

Step 1: Both shapes have radius r = 3 cm, cylinder height h = 10 cm. Step 2: Total surface area = CSA of hemisphere + CSA of cylinder + base area of cylinder. Step 3: Calculate each part: CSA of hemisphere = 2πr² = 2 × (22/7) × 9 = 56.6 cm²; CSA of cylinder = 2πrh = 2 × (22/7) × 3 × 10 = 188.6 cm²; Base area = πr² = (22/7) × 9 = 28.3 cm². Step 4: Add them: 56.6 + 188.6 + 28.3 = 244.3 cm². Note: The hemisphere covers one base of the cylinder.

+41 more questions on Surface Areas and Volumes (Karnataka Board Class 10 Mathematics)

Practise All

Frequently Asked Questions

What are the important topics in Surface Areas and Volumes for Karnataka Board Class 10 Mathematics?
Key topics in Surface Areas and Volumes include Basic Formulas for 3D Shapes, Surface Area of Combination Solids, Volume of Combination Solids, Step-by-Step Problem Solving. Study these first, then practise questions on each for the Karnataka Board Class 10 board exam.
How many important questions are there in Surface Areas and Volumes?
Super Tutor has 45 practice questions for Surface Areas and Volumes, including multiple choice questions. A sample with answers is on this page.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.

For serious students

Get the full Surface Areas and Volumes chapter — start free.

Quizzes, flashcards, an AI doubt solver and a study plan for Karnataka Board Class 10 Mathematics. Free to start, no card needed.