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Chapter 2 of 13
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Similarity

Maharashtra Board · Class 10 · Mathematics

Flashcards for Similarity — Maharashtra Board Class 10 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions30 flashcards5 concepts

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Card 1Basic Proportionality Theorem

Solve: In triangle ABC, line PQ is parallel to BC, P lies on AB and Q lies on AC. Find the relationship between AP, PB, AQ, and QC.

Answer

Step 1: Since PQ is parallel to BC, use the basic proportionality theorem. Step 2: Write the ratio of the divided sides. AP/PB = AQ/QC Answer: The line divides the two sides in the same proportion.

Card 2Basic Proportionality Theorem

When do you use the basic proportionality theorem?

Answer

Use it when a line is parallel to one side of a triangle and cuts the other two sides at distinct points. Example: If PQ ∥ BC in triangle ABC, then AP/PB = AQ/QC. This helps compare the two divided si

Card 3Basic Proportionality Theorem

Solve: In triangle ABC, line PQ is parallel to BC. If AP = 3 cm, PB = 6 cm, and AQ = 4 cm, find QC.

Answer

Step 1: Use the basic proportionality theorem. AP/PB = AQ/QC Step 2: Substitute the values. 3/6 = 4/QC Step 3: Simplify 3/6 = 1/2. So, 1/2 = 4/QC Step 4: Cross-multiply. QC = 8 cm Answer: QC = 8 cm

Card 4Basic Proportionality Theorem

Why does the basic proportionality theorem work?

Answer

Count the triangles formed by drawing the two extra segments. Triangles APQ, PQB, and PQC are used in the proof. Because the line is parallel to BC, the smaller triangles have equal heights where need

Card 5Converse of Basic Proportionality Theorem

Solve: In triangle PQR, if PS/SQ = PT/TR, what can you conclude about ST and QR?

Answer

Step 1: Recognise the converse of the basic proportionality theorem. Step 2: If a line divides two sides of a triangle in the same ratio, it is parallel to the third side. Step 3: Here, the line throu

Card 6Converse of Basic Proportionality Theorem

What is the key idea behind the converse of the basic proportionality theorem?

Answer

If the two sides of a triangle are divided in the same ratio, then the joining line must be parallel to the third side. A common way to prove this is by the indirect method. This result is useful when

Card 7Angle Bisector Theorem

Solve: In triangle ABC, if the bisector of angle C meets AB at E, write the ratio formed on AB.

Answer

Step 1: Apply the angle bisector theorem. Step 2: The bisector of an angle divides the opposite side in the ratio of the remaining two sides. AE/EB = CA/CB Answer: AE/EB = CA/CB

Card 8Angle Bisector Theorem

Solve: In triangle ABC, angle C is bisected at E on AB. If CA = 10 cm and CB = 15 cm, and AE = 8 cm, find EB.

Answer

Step 1: Use the angle bisector theorem. AE/EB = CA/CB Step 2: Substitute the values. 8/EB = 10/15 Step 3: Simplify 10/15 = 2/3. So, 8/EB = 2/3 Step 4: Cross-multiply. 2 × EB = 3 × 8 2EB = 24 EB = 12 c

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Frequently Asked Questions

What are the important topics in Similarity for Maharashtra Board Class 10 Mathematics?
Similarity covers several key topics that are frequently asked in Maharashtra Board Class 10 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Similarity — Maharashtra Board Class 10 Mathematics?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Similarity?
There are 30 flashcards for Similarity covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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