Co-ordinate Geometry — Flashcards
Maharashtra Board · Class 10 · Mathematics
30 flashcards for Co-ordinate Geometry (Maharashtra Board Class 10 Mathematics) to test yourself on key terms and facts.
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Solve: Find the distance between P(-1) and Q(-5) on a number line.
Answer
Step 1: Use distance on a number line = larger coordinate - smaller coordinate. Step 2: |-1 - (-5)| = |-1 + 5| = |4|. Answer: 4…
Solve: Find the distance between Q(-5) and R(4) on a number line.
Answer
Step 1: Find the difference: 4 - (-5). Step 2: 4 + 5 = 9. Answer: 9…
Solve: Find the distance between A(2,3) and C(-2,2) using the distance formula.
Answer
Step 1: Use AB = sqrt((x2 - x1)^2 + (y2 - y1)^2). Step 2: AC = sqrt((-2 - 2)^2 + (2 - 3)^2). Step 3: AC = sqrt((-4)^2 + (-1)^2). Step 4: AC = sqrt(16 + 1) = sqrt(17). Answer: sqrt(17)…
Why does the distance formula give the same answer even if the order of points is reversed?
Answer
Notice that squaring removes the sign. If the points are P(x1,y1) and Q(x2,y2), then: PQ^2 = (x2 - x1)^2 + (y2 - y1)^2 and also PQ^2 = (x1 - x2)^2 + (y1 - y2)^2. Both are equal because (a)^2 = (-a)^2.
Formula for distance between two points in the plane.
Answer
AB = sqrt((x2 - x1)^2 + (y2 - y1)^2) Here A(x1,y1) and B(x2,y2) are two points. Quick use: For A(2,3) and B(-2,2), the distance is sqrt(17).
Apply the distance-from-origin formula to a point P(x,y).
Answer
Use d(O,P) = sqrt(x^2 + y^2). Example: If P(3,4), then d(O,P) = sqrt(3^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5. Answer: 5 units…
Solve: A point P divides AB in the ratio 3:5. If AP = 6 and PB = 10, what is AP/PB?
Answer
Step 1: Write the ratio as AP/PB. Step 2: AP/PB = 6/10. Step 3: Simplify = 3/5. Answer: 3/5…
When do you use the section formula?
Answer
Use the section formula when a point divides a line segment in a given ratio. Formula: ( (mx2 + nx1)/(m + n), (my2 + ny1)/(m + n) ) Example: If A(x1,y1) and B(x2,y2) are divided in ratio 3:2, substitu…
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