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Chapter 10 of 16
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Index Numbers

Maharashtra Board · Class 12 · Mathematics & Statistics -Commerce

Flashcards for Index Numbers — Maharashtra Board Class 12 Mathematics & Statistics -Commerce. Quick Q&A cards covering key concepts, definitions, and formulas.

44 questions20 flashcards5 concepts

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Card 1Area under curve

What is the formula for finding the area under a curve y = f(x) between x = a and x = b, where f(x) ≥ 0?

Answer

Area = ∫ᵇₐ f(x) dx This formula gives the area bounded by: • The curve y = f(x) • The X-axis • The vertical lines x = a and x = b Note: The function must be continuous in [a, b] and f(x) ≥ 0 for thi

Card 2Area under curve

How do you find the area bounded by a curve x = g(y), Y-axis, and horizontal lines y = c and y = d?

Answer

Area = ∫ᵈᶜ x dy = ∫ᵈᶜ g(y) dy This formula is used when: • The curve is expressed as x in terms of y • The region is bounded by horizontal lines • Integration is performed with respect to y Example:

Card 3Area under curve

Find the area bounded by y = x², X-axis, and lines x = 1 and x = 3.

Answer

Step 1: Set up the integral Area = ∫³₁ y dx = ∫³₁ x² dx Step 2: Integrate = [x³/3]³₁ Step 3: Apply limits = 3³/3 - 1³/3 = 27/3 - 1/3 = 9 - 1/3 = 26/3 sq. units Answer: 26/3 square units

Card 4Area under curve

What happens when f(x) < 0 in the interval [a, b]? How do you calculate the area?

Answer

When f(x) < 0, the definite integral gives a negative value, but area is always positive. Solution: Take the absolute value Area = |∫ᵇₐ f(x) dx| Example: y = -x², x = 1 to x = 2 ∫²₁ (-x²) dx = [-x³/

Card 5Area between curves

How do you find the area between two curves y = f(x) and y = g(x) from x = a to x = b?

Answer

Area = |∫ᵇₐ [f(x) - g(x)] dx| Step-by-step approach: 1. Find intersection points by solving f(x) = g(x) 2. Determine which curve is above the other 3. Set up integral as (upper curve - lower curve) 4

Card 6Area between curves

Find the area bounded by curves y² = 9x and x² = 9y.

Answer

Step 1: Find intersection points From y² = 9x and x² = 9y Substitute y = x²/9 into first equation: (x²/9)² = 9x → x⁴/81 = 9x → x⁴ = 729x x(x³ - 729) = 0 → x = 0 or x = 9 Points: (0,0) and (9,9) Step

Card 7Area under curve

What is the area of the region bounded by y = sin x and X-axis from x = 0 to x = 2π?

Answer

Since sin x changes sign, we split the integral: Step 1: Identify regions • From 0 to π: sin x ≥ 0 (above X-axis) • From π to 2π: sin x ≤ 0 (below X-axis) Step 2: Calculate each area A₁ = ∫ᵖ₀ sin x

Card 8Area of standard curves

Find the area of the ellipse x²/a² + y²/b² = 1.

Answer

Step 1: Use symmetry Total area = 4 × (area in first quadrant) Step 2: Express y in terms of x From ellipse equation: y = (b/a)√(a² - x²) Limits: x = 0 to x = a Step 3: Set up integral Area = 4∫ᵃ₀ (

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Frequently Asked Questions

What are the important topics in Index Numbers for Maharashtra Board Class 12 Mathematics & Statistics -Commerce?
Index Numbers covers several key topics that are frequently asked in Maharashtra Board Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Index Numbers — Maharashtra Board Class 12 Mathematics & Statistics -Commerce?
Understand the core concepts first, then work through the 44 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
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There are 20 flashcards for Index Numbers covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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