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Differential Equation and Applications

Maharashtra Board · Class 12 · Mathematics & Statistics -Commerce

Flashcards for Differential Equation and Applications — Maharashtra Board Class 12 Mathematics & Statistics -Commerce. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions20 flashcards5 concepts

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Card 1Basic Definitions

What is a differential equation? Provide the definition and give two examples.

Answer

A differential equation is an equation involving dependent variable(s), independent variable(s), and derivatives of the dependent variable(s) with respect to the independent variable. Examples: 1) dy

Card 2Order and Degree

How do you determine the ORDER of a differential equation? Give examples with different orders.

Answer

The ORDER is the highest order derivative present in the equation. Examples: • dy/dx = y + x → Order = 1 (highest derivative is first order) • d²y/dx² + 3(dy/dx) - 2y = 0 → Order = 2 (highest derivat

Card 3Order and Degree

How do you find the DEGREE of a differential equation? Solve this step-by-step: Find the degree of (d²y/dx²)³ = 2 + (dy/dx)²

Answer

Step-by-step method: 1) Make all derivatives free from fractional/negative indices 2) Identify the highest order derivative 3) Find its power For (d²y/dx²)³ = 2 + (dy/dx)²: • Already free from fracti

Card 4Solutions

What is the difference between General Solution and Particular Solution of a differential equation?

Answer

GENERAL SOLUTION: • Contains arbitrary constants • Number of constants = order of equation • Example: y = Ae^x + Be^(-x) (2 constants for 2nd order) PARTICULAR SOLUTION: • Obtained by giving specific

Card 5Variable Separable Method

Solve this step-by-step using variable separation: dy/dx = (1+y)/(1+x)

Answer

Step 1: Separate variables dy/(1+y) = dx/(1+x) Step 2: Integrate both sides ∫dy/(1+y) = ∫dx/(1+x) Step 3: Apply integration log(1+y) = log(1+x) + log c log(1+y) = log[c(1+x)] Step 4: Remove logarit

Card 6Variable Separable Method

When do we use substitution in differential equations? Solve: (2x - 2y + 3)dx - (x - y + 1)dy = 0

Answer

Use substitution when variables cannot be separated directly. Step 1: Rearrange dy/dx = (2x - 2y + 3)/(x - y + 1) = (2(x-y) + 3)/(x-y+1) Step 2: Substitute x - y = t dt/dx = 1 - dy/dx, so dy/dx = 1

Card 7Homogeneous Equations

What is a Homogeneous Differential Equation? How do you identify one?

Answer

DEFINITION: A differential equation f(x,y)dx + g(x,y)dy = 0 is homogeneous if f(x,y) and g(x,y) are homogeneous functions of the same degree. IDENTIFICATION TEST: Replace x with λx and y with λy in b

Card 8Homogeneous Equations

Solve this homogeneous equation step-by-step: (x² + y²)dx - 2xy dy = 0

Answer

Step 1: Verify it's homogeneous Both x² + y² and 2xy have degree 2 ✓ Step 2: Rearrange dy/dx = (x² + y²)/(2xy) Step 3: Substitute y = tx, dy/dx = t + x(dt/dx) t + x(dt/dx) = (x² + t²x²)/(2x·tx) = (1

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What are the important topics in Differential Equation and Applications for Maharashtra Board Class 12 Mathematics & Statistics -Commerce?
Differential Equation and Applications covers several key topics that are frequently asked in Maharashtra Board Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Differential Equation and Applications — Maharashtra Board Class 12 Mathematics & Statistics -Commerce?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
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There are 20 flashcards for Differential Equation and Applications covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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