Electromagnetic Induction — Practice Quiz
Maharashtra Board · Class 12 · Physics
Try a 4-question quiz on Electromagnetic Induction for Maharashtra Board Class 12 Physics: tap an answer to check it and see why.
Interactive on Super Tutor
Studying Electromagnetic Induction? Get the full interactive chapter.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for practice quiz and more.
Free trial, no card needed.
Quick Quiz: Electromagnetic Induction
0/4Tap an answer to check it instantly. No sign-up needed for these 4.
According to Faraday's first law of electromagnetic induction, what condition is necessary for an EMF to be induced in a circuit?
A coil of 100 turns has an area of 0.01 m². If a uniform magnetic field of 0.5 T perpendicular to the coil is reduced to zero in 0.1 s, calculate the induced EMF.
According to Lenz's law, the direction of induced current is such that it:
A conducting rod of length 0.2 m moves with velocity 5 m/s perpendicular to a magnetic field of 0.8 T. Calculate the motional EMF induced.
Sample Questions
Which of the following factors affect the self-inductance of a solenoid?
Show answer
Number of turns, Cross-sectional area, Length of solenoid, Permeability of core material
Self-inductance L = μ₀n²Al = μ₀N²A/l, where N is number of turns, A is area, l is length, and μ₀ is permeability. Current does not affect inductance as it's a property of the geometry and material.
The unit of inductance is:
Show answer
Henry
The unit of inductance is Henry (H), named after Joseph Henry. 1 H = 1 V·s/A = 1 Ω·s. Weber is the unit of magnetic flux, Tesla is for magnetic field, and Farad is for capacitance.
A solenoid has 500 turns, length 0.5 m, and cross-sectional area 0.01 m². Calculate its self-inductance in air.
Show answer
6.28 mH
For a solenoid: L = μ₀N²A/l. Given: N = 500, A = 0.01 m², l = 0.5 m, μ₀ = 4π × 10⁻⁷ H/m. L = (4π × 10⁻⁷ × 500² × 0.01)/0.5 = 6.28 × 10⁻³ H = 6.28 mH
The energy stored in an inductor of 2 H carrying current of 3 A is:
Show answer
9 J
Energy stored in an inductor: U = ½LI². Given: L = 2 H, I = 3 A. Therefore, U = ½ × 2 × 3² = ½ × 2 × 9 = 9 J
+41 more questions on Electromagnetic Induction (Maharashtra Board Class 12 Physics)
Practise AllFrequently Asked Questions
What are the important topics in Electromagnetic Induction for Maharashtra Board Class 12 Physics?
How many practice questions are there for Electromagnetic Induction?
Sources & Official References
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
More resources for Electromagnetic Induction
For serious students
Get the full Electromagnetic Induction chapter — start free.
Quizzes, flashcards, an AI doubt solver and a study plan for Maharashtra Board Class 12 Physics. Free to start, no card needed.