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Conic Sections — Flashcards

Madhya Pradesh Board · Class 11 · Mathematics

56 flashcards for Conic Sections (Madhya Pradesh Board Class 11 Mathematics) to test yourself on key terms and facts.

193 questions56 flashcards14 formulas & key relations5 concepts

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56 Flashcards·
Circle equationवृत्त का समीकरणCircle from general formसामान्य रूप से वृत्तCircle through pointsबिंदुओं से होकर जाने वाला वृत्त
Card 1Circle equation

Find the equation of a circle with centre (0, 0) and radius 7.

Answer

Step 1: Use the circle equation (x - h)^2 + (y - k)^2 = r^2. Step 2: Here, h = 0, k = 0, and r = 7. Step 3: Substitute: x^2 + y^2 = 7^2. Answer: x^2 + y^2 = 49.

Card 2वृत्त का समीकरण

केंद्र (0, 0) और त्रिज्या 7 वाले एक वृत्त का समीकरण ज्ञात कीजिए।

Answer

चरण 1: वृत्त का समीकरण (x - h)^2 + (y - k)^2 = r^2 का उपयोग कीजिए। चरण 2: यहाँ, h = 0, k = 0, और r = 7 है। चरण 3: रखने पर: x^2 + y^2 = 7^2. उत्तर: x^2 + y^2 = 49.

Card 3Circle equation

Find the equation of a circle with centre (-3, 2) and radius 4.

Answer

Step 1: Use (x - h)^2 + (y - k)^2 = r^2. Step 2: Substitute h = -3, k = 2, r = 4. Step 3: (x + 3)^2 + (y - 2)^2 = 16. Answer: (x + 3)^2 + (y - 2)^2 = 16.

Card 4वृत्त का समीकरण

केंद्र (-3, 2) और त्रिज्या 4 वाले एक वृत्त का समीकरण ज्ञात कीजिए।

Answer

चरण 1: (x - h)^2 + (y - k)^2 = r^2 का उपयोग कीजिए। चरण 2: h = -3, k = 2, r = 4 रखें। चरण 3: (x + 3)^2 + (y - 2)^2 = 16. उत्तर: (x + 3)^2 + (y - 2)^2 = 16.

Card 5Circle from general form

Find the centre and radius of the circle x^2 + y^2 + 8x + 10y - 8 = 0.

Answer

Step 1: Group x terms and y terms: (x^2 + 8x) + (y^2 + 10y) = 8. Step 2: Complete squares: (x^2 + 8x + 16) + (y^2 + 10y + 25) = 8 + 16 + 25. Step 3: Write as (x + 4)^2 + (y + 5)^2 = 49. Step 4: Compar…

Card 6सामान्य रूप से वृत्त

वृत्त x^2 + y^2 + 8x + 10y - 8 = 0 का केंद्र और त्रिज्या ज्ञात कीजिए।

Answer

चरण 1: x पदों और y पदों को समूहित कीजिए: (x^2 + 8x) + (y^2 + 10y) = 8. चरण 2: वर्ग पूर्ण कीजिए: (x^2 + 8x + 16) + (y^2 + 10y + 25) = 8 + 16 + 25. चरण 3: इसे (x + 4)^2 + (y + 5)^2 = 49 के रूप में लिखिए…

Card 7Circle through points

A circle passes through (2, -2) and (3, 4), and its centre lies on x + y = 2. Find its equation.

Answer

Step 1: Let the centre be (h, k) and radius be r. Step 2: Since the circle passes through the points: (2 - h)^2 + (-2 - k)^2 = r^2 (3 - h)^2 + (4 - k)^2 = r^2 Step 3: Also, h + k = 2. Step 4: Solving …

Card 8बिंदुओं से होकर जाने वाला वृत्त

एक वृत्त (2, -2) और (3, 4) से होकर जाता है, और उसका केंद्र x + y = 2 पर स्थित है। उसका समीकरण ज्ञात कीजिए।

Answer

चरण 1: केंद्र को (h, k) तथा त्रिज्या को r मानिए। चरण 2: क्योंकि वृत्त दिए गए बिंदुओं से होकर जाता है: (2 - h)^2 + (-2 - k)^2 = r^2 (3 - h)^2 + (4 - k)^2 = r^2 चरण 3: साथ ही, h + k = 2. चरण 4: इन्हें ह…

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Frequently Asked Questions

What are the important topics in Conic Sections for Madhya Pradesh Board Class 11 Mathematics?
Key topics in Conic Sections include Conic Sections and Their Classification, Circle, Parabola, Ellipse. Study these first, then practise questions on each for Class 11 exams.
How many flashcards are available for Conic Sections?
There are 56 flashcards for Conic Sections covering key definitions, facts and ideas. A few sample cards are shown on this page.
How should I revise Conic Sections for Class 11 exams?
Learn the core ideas first, then work through the 193 practice questions on Conic Sections. Revise definitions regularly and use flashcards for quick recall before the exam.

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