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Polynomials

Punjab Board · Class 9 · Mathematics

Flashcards for Polynomials — Punjab Board Class 9 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions32 flashcards5 concepts

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A labeled diagram illustrating the general form of a polynomial, distinguishing between real and complex polynomials by highlighting the nature of coefficients and variables. Also includes the definit
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32 Flashcards
Card 1Evaluating Polynomials

Evaluate p(x) = 2x² + 5x - 3 at x = 2

Answer

Step 1: Substitute x = 2 into p(x) Step 2: p(2) = 2(2)² + 5(2) - 3 Step 3: p(2) = 2(4) + 10 - 3 Step 4: p(2) = 8 + 10 - 3 Step 5: p(2) = 15 Answer: The value of the polynomial at x = 2 is 15

Card 2Evaluating Polynomials

Find the value of p(x) = x³ - 3x² + 2x - 5 at x = -1

Answer

Step 1: Substitute x = -1 into p(x) Step 2: p(-1) = (-1)³ - 3(-1)² + 2(-1) - 5 Step 3: p(-1) = -1 - 3(1) - 2 - 5 Step 4: p(-1) = -1 - 3 - 2 - 5 Step 5: p(-1) = -11 Answer: The polynomial equals -11 w

Card 3Finding Zeros of Polynomials

Check if x = 3 is a zero of p(x) = x² - 5x + 6

Answer

Step 1: Substitute x = 3 into p(x) Step 2: p(3) = (3)² - 5(3) + 6 Step 3: p(3) = 9 - 15 + 6 Step 4: p(3) = 0 Conclusion: Since p(3) = 0, x = 3 IS a zero of the polynomial. Note: This means (x - 3) i

Card 4Finding Zeros of Polynomials

Verify that x = -2 is a zero of p(x) = x³ + 5x² + 8x + 4

Answer

Step 1: Substitute x = -2 into p(x) Step 2: p(-2) = (-2)³ + 5(-2)² + 8(-2) + 4 Step 3: p(-2) = -8 + 5(4) - 16 + 4 Step 4: p(-2) = -8 + 20 - 16 + 4 Step 5: p(-2) = 0 Conclusion: Since p(-2) = 0, x = -

Card 5Finding Zeros of Polynomials

Find the zero of the linear polynomial p(x) = 3x + 7

Answer

Step 1: Set p(x) = 0 Step 2: 3x + 7 = 0 Step 3: 3x = -7 Step 4: x = -7/3 Answer: The zero of p(x) is x = -7/3 Verification: p(-7/3) = 3(-7/3) + 7 = -7 + 7 = 0 ✓ Note: Every linear polynomial ax + b

Card 6Degree of Polynomials

What is the degree of the polynomial p(x) = 4x⁵ - 3x³ + 2x - 7?

Answer

Step 1: Identify all terms and their exponents - 4x⁵ has exponent 5 - -3x³ has exponent 3 - 2x has exponent 1 - -7 has exponent 0 Step 2: Find the highest exponent Highest exponent = 5 Answer: The d

Card 7Factor Theorem

Determine if (x - 1) is a factor of p(x) = x³ + 2x² - 5x + 2 using the Factor Theorem

Answer

Factor Theorem: (x - a) is a factor of p(x) if and only if p(a) = 0 Step 1: For (x - 1), we have a = 1 Step 2: Calculate p(1) Step 3: p(1) = (1)³ + 2(1)² - 5(1) + 2 Step 4: p(1) = 1 + 2 - 5 + 2 Step

Card 8Factor Theorem Applications

Use Factor Theorem: Find the value of k if (x + 2) is a factor of p(x) = x² + kx - 6

Answer

Factor Theorem: If (x + 2) is a factor, then p(-2) = 0 Step 1: Set up the equation p(-2) = 0 Step 2: (-2)² + k(-2) - 6 = 0 Step 3: 4 - 2k - 6 = 0 Step 4: -2k - 2 = 0 Step 5: -2k = 2 Step 6: k = -1 A

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Frequently Asked Questions

What are the important topics in Polynomials for Punjab Board Class 9 Mathematics?
Key topics in Polynomials include Polynomials - Complete Concept Overview, Polynomials Concepts Overview, Decision flowchart to determine if an expression is a polynomial based on whether all exponents are whole numbers. These are the concepts Punjab Board Class 9 examiners draw on most — study them first, then practise related questions.
How to score full marks in Polynomials — Punjab Board Class 9 Mathematics?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Polynomials?
There are 32 flashcards for Polynomials covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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