Trigonometry
Telangana Board · Class 10 · Mathematics
Flashcards for Trigonometry — Telangana Board Class 10 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.
Interactive on Super Tutor
Studying Trigonometry? Get the full interactive chapter.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for flashcards and more.
1,000+ Class 10 students started this chapter today
Solve: In a right-angled triangle, if tan A = 3/4, find sin A, cos A, cosec A, sec A, and cot A.
Answer
Step 1: tan A = opposite/adjacent = 3/4, so take opposite = 3k and adjacent = 4k. Step 2: Use Pythagoras theorem. AC^2 = (3k)^2 + (4k)^2 = 9k^2 + 16k^2 = 25k^2 AC = 5k Step 3: Find the ratios. sin A =…
Solve: In a right-angled triangle PQR, right angle is at Q, PQ = 3 cm and PR = 6 cm. Find angle PRQ and angle QPR.
Answer
Step 1: For angle R, opposite side = PQ = 3 cm and hypotenuse = PR = 6 cm. Step 2: Find sine of angle R. sin R = PQ/PR = 3/6 = 1/2 Step 3: sin 30° = 1/2, so angle PRQ = 30°. Step 4: The two acute angl…
Solve: In triangle ABC, right angle is at B, AB = 5 cm and angle ACB = 30°. Find BC and AC.
Answer
Step 1: At angle C, AB is opposite and BC is adjacent. Step 2: Use tan C. tan 30° = AB/BC = 5/BC Step 3: tan 30° = 1/√3. So, 5/BC = 1/√3 BC = 5√3 cm Step 4: Use sin 30°. sin 30° = AB/AC = 5/AC = 1/2 A…
Solve: In a right-angled triangle, if sin A = 15/17, find cos A and tan A.
Answer
Step 1: Use the identity sin^2 A + cos^2 A = 1. Step 2: Substitute sin A = 15/17. (15/17)^2 + cos^2 A = 1 225/289 + cos^2 A = 1 cos^2 A = 64/289 Step 3: Since A is acute, cos A = 8/17. Step 4: Use tan…
When do you use the identity cos^2 A + sin^2 A = 1?
Answer
Use it when one trigonometric ratio is known and another ratio is needed. Example: If sin A = 3/5, then sin^2 A + cos^2 A = 1 9/25 + cos^2 A = 1 cos^2 A = 16/25 cos A = 4/5 for an acute angle. This id…
Solve: If cos A = 12/13 and A is acute, find sin A and tan A.
Answer
Step 1: Use sin^2 A + cos^2 A = 1. Step 2: Substitute cos A = 12/13. sin^2 A + (12/13)^2 = 1 sin^2 A + 144/169 = 1 sin^2 A = 25/169 Step 3: Since A is acute, sin A = 5/13. Step 4: Find tan A. tan A = …
Solve: If 3 tan A = 4, find sin A and cos A.
Answer
Step 1: 3 tan A = 4 means tan A = 4/3. Step 2: Take opposite = 4k and adjacent = 3k. Step 3: Hypotenuse = sqrt((4k)^2 + (3k)^2) = sqrt(16k^2 + 9k^2) = 5k. Step 4: Find ratios. sin A = 4k/5k = 4/5 cos …
Solve: In triangle PQR, right angle is at R, PQ = 29 units and QR = 21 units. Find PR, sin θ, cos θ, and verify sin^2 θ + cos^2 θ = 1, where θ = angle PQR.
Answer
Step 1: Use Pythagoras theorem. PR^2 = PQ^2 - QR^2 = 29^2 - 21^2 = 841 - 441 = 400 PR = 20 units Step 2: For angle θ at Q, opposite side = PR and adjacent side = QR. sin θ = PR/PQ = 20/29 cos θ = QR/P…
+20 more flashcards available
Practice AllFrequently Asked Questions
What are the important topics in Trigonometry for Telangana Board Class 10 Mathematics?
How to score full marks in Trigonometry — Telangana Board Class 10 Mathematics?
How many flashcards are available for Trigonometry?
Sources & Official References
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
More resources for Trigonometry
Practice Quiz
Test yourself with a quick quiz
Important Questions
Practice with board exam-style questions
Revision Notes
Key points for last-minute revision
Formula Sheet
All formulas in one place
Chapter Summary
Understand the chapter at a glance
Concept Maps
See how topics connect visually
Study Plan
Step-by-step plan to ace this chapter
Syllabus
What topics to cover
NCERT Solutions
Every textbook question solved step by step
For serious students
Get the full Trigonometry chapter — for free.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan for Telangana Board Class 10 Mathematics.