Mensuration
Telangana Board · Class 10 · Mathematics
Flashcards for Mensuration — Telangana Board Class 10 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.
Interactive on Super Tutor
Studying Mensuration? Get the full interactive chapter.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for flashcards and more.
1,000+ Class 10 students started this chapter today
Solve: Find the slant height of a conical tent with radius 7 m and height 10 m.
Answer
Step 1: Use the formula l = √(r^2 + h^2). Step 2: Substitute r = 7 m and h = 10 m. l = √(7^2 + 10^2) = √(49 + 100) = √149. Step 3: √149 ≈ 12.2 m. Answer: The slant height is 12.2 m.
A conical tent has radius 7 m, height 10 m, and canvas width 2 m. Find the length of canvas needed.
Answer
Step 1: Find slant height. l = √(7^2 + 10^2) = √149 ≈ 12.2 m. Step 2: Find curved surface area of the cone. CSA = πrl = (22/7) × 7 × 12.2 = 268.4 m². Step 3: Length of canvas = area ÷ width = 268.4 ÷ …
Find the total surface area of a cylinder with radius 14 cm and height 21 cm.
Answer
Step 1: Use TSA of cylinder = 2πr(r + h). Step 2: Substitute r = 14 cm and h = 21 cm. TSA = 2 × (22/7) × 14 × (14 + 21) = 2 × (22/7) × 14 × 35 = 3080 cm². Answer: Total surface area = 3080 cm².
A cylinder has radius 14 cm and height 21 cm. Find its base area, curved surface area, total surface area, and volume.
Answer
Step 1: Base area = πr² = (22/7) × 14² = 616 cm². Step 2: CSA = 2πrh = 2 × (22/7) × 14 × 21 = 1848 cm². Step 3: TSA = 2 × base area + CSA = 2 × 616 + 1848 = 3080 cm². Step 4: Volume = πr²h = 616 × 21 …
Find the surface area and volume of a sphere of radius 2.1 cm.
Answer
Step 1: Surface area of sphere = 4πr². = 4 × (22/7) × (2.1)² = 55.44 cm². Step 2: Volume of sphere = (4/3)πr³. = (4/3) × (22/7) × (2.1)³ = 38.808 cm³. Answer: Surface area = 55.44 cm² and volume = 38.
Find the volume and total surface area of a hemisphere of radius 3.5 cm.
Answer
Step 1: Volume of hemisphere = (2/3)πr³. = (2/3) × (22/7) × (3.5)³ = 89.83 cm³. Step 2: TSA of hemisphere = 3πr². = 3 × (22/7) × (3.5)² = 115.5 cm². Answer: Volume = 89.83 cm³ and TSA = 115.5 cm².
When do you use CSA = 2πrh for a cylinder? Give a quick example.
Answer
Use CSA = 2πrh when only the curved side of the cylinder is needed, not the two circular bases. Example: For radius 1 m and height 7 m, CSA = 2 × π × 1 × 7 = 14π m² = 44 m² if π = 22/7. Answer: This f…
Why is the total surface area of a cone on a cylinder not equal to the sum of the two total surface areas?
Answer
When two solids are joined, the touching surfaces disappear from outside view. So, the hidden circular face is not counted again. For a combined solid, only the exposed surfaces are added. Example ide…
+14 more flashcards available
Practice AllFrequently Asked Questions
What are the important topics in Mensuration for Telangana Board Class 10 Mathematics?
How to score full marks in Mensuration — Telangana Board Class 10 Mathematics?
How many flashcards are available for Mensuration?
Sources & Official References
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
More resources for Mensuration
Practice Quiz
Test yourself with a quick quiz
Important Questions
Practice with board exam-style questions
Revision Notes
Key points for last-minute revision
Formula Sheet
All formulas in one place
Chapter Summary
Understand the chapter at a glance
Concept Maps
See how topics connect visually
Study Plan
Step-by-step plan to ace this chapter
Syllabus
What topics to cover
NCERT Solutions
Every textbook question solved step by step
For serious students
Get the full Mensuration chapter — for free.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan for Telangana Board Class 10 Mathematics.