Electrostatic Potential and Capacitance
Telangana Board · Class 12 · Physics
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Quick Quiz: Electrostatic Potential and Capacitance
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The SI unit of electric potential is:
Calculate the electric potential at a distance of 0.1 m from a point charge of 5 × 10⁻⁹ C in air. (Take k = 9 × 10⁹ N⋅m²/C²)
A parallel plate capacitor has plates of area 0.02 m² separated by 2 mm in air. Calculate its capacitance. (ε₀ = 8.85 × 10⁻¹² F/m)
Two capacitors of 4 μF and 6 μF are connected in series. What is their equivalent capacitance?
Sample Questions
Which of the following statements about electric potential are correct?
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Electric potential is a scalar quantity, Potential is measured in volts, Potential decreases with distance from a positive charge, Potential is zero at infinity
Electric potential is a scalar quantity measured in volts. It decreases with distance from a positive charge and is taken as zero at infinity. Work done in electrostatic field is path independent, not path dependent.
The capacitance of a parallel plate capacitor depends on:
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Area of the plates, Distance between plates, Dielectric constant of medium
For a parallel plate capacitor, C = ε₀A/d or Kε₀A/d with dielectric. Capacitance depends on area (A), separation (d), and dielectric constant (K), but not on charge or potential difference.
The energy stored in a capacitor is given by:
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½CV², ½Q²/C, ½QV
The energy stored in a capacitor can be expressed in three equivalent forms: U = ½CV² = ½Q²/C = ½QV. All three expressions are correct and equivalent.
What happens to the capacitance when a dielectric material is inserted between the plates of a capacitor?
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Increases
When a dielectric material with dielectric constant K is inserted, the capacitance increases by a factor K. The new capacitance becomes C = KC₀ where C₀ is the original capacitance.
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