Skip to main content
Chapter 5 of 13
NCERT Solutions

How Many? (Addition and Subtraction of Single Digit Numbers) — NCERT Solutions

CBSE · Class 1 · Mathematics

NCERT Solutions for How Many? (Addition and Subtraction of Single Digit Numbers), CBSE Class 1 Mathematics: 57 textbook questions solved step by step.

45 questions60 flashcards5 concepts

Interactive on Super Tutor

Studying How Many? (Addition and Subtraction of Single Digit Numbers)? Get the full interactive chapter.

Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for NCERT solutions and more.

Free trial, no card needed.

57 Questions Solved · 19 Sections

The first 29 solutions are open to read. The other 28 are free with a Super Tutor account.

Tell How Many Altogether? Fill in the Blanks

14 children and 2 children altogether make ___ children. 4+2=4 + 2 = Show solution

Given: 4 children and 2 more children join them.
Concept: Addition means putting two groups together to find the total.
4+2=64 + 2 = 6
Answer: 4 children and 2 children altogether make 6 children.

23 tops and 1 top altogether make ___ tops. 3+1=3 + 1 = Show solution

Given: 3 tops and 1 more top.
Concept: Addition — combining two groups.
3+1=43 + 1 = 4
Answer: 3 tops and 1 top altogether make 4 tops.

33 ants and 2 ants altogether make ___ ants. 3+2=3 + 2 = Show solution

Given: 3 ants and 2 more ants.
Concept: Addition — combining two groups.
3+2=53 + 2 = 5
Answer: 3 ants and 2 ants altogether make 5 ants.

44 pencils and 3 pencils altogether make ___ pencils. 4+3=4 + 3 = Show solution

Given: 4 pencils and 3 more pencils.
Concept: Addition — combining two groups.
4+3=74 + 3 = 7
Answer: 4 pencils and 3 pencils altogether make 7 pencils.

Add and Draw

16 balls and 2 balls altogether make ___ balls. 6+2=6 + 2 = Show solution

Given: 6 balls and 2 more balls.
Concept: Addition — combining two groups.
6+2=86 + 2 = 8
Answer: 6 balls and 2 balls altogether make 8 balls.
(Draw 8 balls in total in the space provided.)

27+1=7 + 1 = Show solution

Given: 7 and 1.
Concept: Addition.
7+1=87 + 1 = 8
Answer: 8
(Draw 8 objects in the space provided.)

Let us Count

AHow many brothers and sisters do your parents have altogether?Show solution

This is an activity-based question. Count the number of brothers and sisters your mother has, then count the number of brothers and sisters your father has, and add both numbers together.
For example, if your mother has 2 siblings and your father has 3 siblings:
2+3=52 + 3 = 5
Answer will vary for each child.

BHow many family members do you and your friend have altogether?Show solution

This is an activity-based question. Count the total members in your family, then count the total members in your friend's family, and add both numbers.
For example, if you have 4 family members and your friend has 5:
4+5=94 + 5 = 9
Answer will vary for each child.

CHow many fingers do you have in both your hands and feet?Show solution

Given: Each hand has 5 fingers and each foot has 5 toes.
Both hands: 5+5=105 + 5 = 10 fingers.
Both feet: 5+5=105 + 5 = 10 toes.
Total: 10+10=2010 + 10 = 20
Answer: You have 20 fingers and toes altogether.

DHow many numbers can you count on your fingers?Show solution

Given: We have 10 fingers in total (5 on each hand).
We can count from 1 to 10 using our fingers.
Answer: We can count 10 numbers on our fingers.

Count and Write the Total Number of Fingers

1Count and write the total number of fingers shown in the pictures of hands.Show solution

Each hand has 5 fingers.
Two hands together: 5+5=105 + 5 = 10
Answer: The total number of fingers on two hands is 10.
(Note: The exact images are not visible, but the standard activity involves counting fingers on one or two hands and writing the total. Children should count the fingers shown and write the sum.)

Let us Play — Addition with Dice (Kishore and Nitya Score Board)

ARound A: Kishore and Nitya each roll two dice. Find who scores more and put a tick (✓) on their score. (Round A is already shown with Kishore winning.)Show solution

Round A: Kishore's score is already marked with ✓, meaning Kishore rolled a higher total than Nitya in Round A.
(Since the dice images are not visible, the answer is based on the given information that Kishore won Round A.)
Answer: Kishore ✓ in Round A.

BRound B: Find who scores more between Kishore and Nitya and put a tick (✓).Show solution

Note: The dice images for Round B are not visible in the text. Children should add the dots on each player's two dice, compare the totals, and place ✓ under the player with the higher total.
Method: Add dots on Kishore's two dice → total K. Add dots on Nitya's two dice → total N. If K > N, tick Kishore; if N > K, tick Nitya.

CRound C: Find who scores more between Kishore and Nitya and put a tick (✓).Show solution

Note: The dice images for Round C are not visible in the text. Children should add the dots on each player's two dice, compare the totals, and place ✓ under the player with the higher total.

DRound D: Find who scores more between Kishore and Nitya and put a tick (✓).Show solution

Note: The dice images for Round D are not visible in the text. Children should add the dots on each player's two dice, compare the totals, and place ✓ under the player with the higher total.

ERound E: Find who scores more between Kishore and Nitya and put a tick (✓).Show solution

Note: The dice images for Round E are not visible in the text. Children should add the dots on each player's two dice, compare the totals, and place ✓ under the player with the higher total.

Beads and String

AColour the beads as per the numbers and find the total. 3+4=3 + 4 = Show solution

Given: 3 beads of one colour and 4 beads of another colour.
Concept: Addition.
3+4=73 + 4 = 7
Answer: 7 coloured beads in total.
(Colour 3 beads in one colour and 4 beads in another colour on the string.)

B4+2=4 + 2 = Show solution

Given: 4 beads of one colour and 2 beads of another colour.
4+2=64 + 2 = 6
Answer: 6 coloured beads in total.

C5+4=5 + 4 = Show solution

Given: 5 beads of one colour and 4 beads of another colour.
5+4=95 + 4 = 9
Answer: 9 coloured beads in total.

D2+7=2 + 7 = Show solution

Given: 2 beads of one colour and 7 beads of another colour.
2+7=92 + 7 = 9
Answer: 9 coloured beads in total.

E7+3=7 + 3 = Show solution

Given: 7 beads of one colour and 3 beads of another colour.
7+3=107 + 3 = 10
Answer: 10 coloured beads in total.

Add in Your Own Way

1Find the sum: 2+3=2 + 3 = Show solution

Given: 2 and 3.
Method 1 (Counting on): Start from 2, count 3 more → 3, 4, 5.
Method 2 (Fingers): Hold up 2 fingers, then 3 more fingers, count all = 5.
2+3=52 + 3 = 5
Answer: 5

2Find the sum: 5+1=5 + 1 = Show solution

Given: 5 and 1.
Start from 5, count 1 more → 6.
5+1=65 + 1 = 6
Answer: 6

3Find the sum: 3+3=3 + 3 = Show solution

Given: 3 and 3.
Start from 3, count 3 more → 4, 5, 6.
3+3=63 + 3 = 6
Answer: 6

4Find the sum: 9+1=9 + 1 = Show solution

Given: 9 and 1.
Start from 9, count 1 more → 10.
9+1=109 + 1 = 10
Answer: 10

Let us Do — Fill up Number Pairs and Add and Match

AFill up the number pairs (pairs of numbers that add up to make a given number, as shown in the wheel diagram).Show solution

This is an activity based on a number wheel (like the Konark Sun Chariot wheel). Children fill in pairs of numbers that add up to the number in the centre.
For example, if the centre number is 5, the pairs are:
0+5=5, 1+4=5, 2+3=5, 3+2=5, 4+1=5, 5+0=50+5=5,\ 1+4=5,\ 2+3=5,\ 3+2=5,\ 4+1=5,\ 5+0=5
(The exact centre number is not visible; children should fill pairs accordingly.)

BAdd and match the following:
1+41+4 — 55 — 4+24+2
6+36+3 — 66 — 3+43+4
5+25+2 — 77 — 3+23+2
0+60+6 — 99 — 5+45+4
Show solution

Step 1: Solve the left column.
1+4=51+4=5
6+3=96+3=9
5+2=75+2=7
0+6=60+6=6

Step 2: Solve the right column.
4+2=64+2=6
3+4=73+4=7
3+2=53+2=5
5+4=95+4=9

Step 3: Match both sides through the middle number.

  • 1+4=51+4=5 matches with 3+2=53+2=5 (through 5)
  • 6+3=96+3=9 matches with 5+4=95+4=9 (through 9)
  • 5+2=75+2=7 matches with 3+4=73+4=7 (through 7)
  • 0+6=60+6=6 matches with 4+2=64+2=6 (through 6)

Answer:
1+4⟷5⟷3+21+4 \longleftrightarrow 5 \longleftrightarrow 3+2
6+3⟷9⟷5+46+3 \longleftrightarrow 9 \longleftrightarrow 5+4
5+2⟷7⟷3+45+2 \longleftrightarrow 7 \longleftrightarrow 3+4
0+6⟷6⟷4+20+6 \longleftrightarrow 6 \longleftrightarrow 4+2

Project Work — Cards 0 to 9 with Sum 9

1Take ten cards 0 to 9. Arrange the cards in such a manner that their sum must be 9. In how many ways can you do it?Show solution

Given: Cards numbered 0 to 9. Find pairs that add up to 9.
Concept: Addition pairs.
0+9=90 + 9 = 9
1+8=91 + 8 = 9
2+7=92 + 7 = 9
3+6=93 + 6 = 9
4+5=94 + 5 = 9
5+4=95 + 4 = 9
6+3=96 + 3 = 9
7+2=97 + 2 = 9
8+1=98 + 1 = 9
9+0=99 + 0 = 9
Answer: There are 10 ways to make 9 using two cards from 0–9 (including reversed pairs). If we count only unique pairs (where order does not matter), there are 5 ways: (0,9), (1,8), (2,7), (3,6), (4,5)(0,9),\ (1,8),\ (2,7),\ (3,6),\ (4,5).

Addition Story

ARaghav has 4 shells and Sarita has 5 shells. How many shells do they have altogether?Show solution

Given: Raghav has 4 shells. Sarita has 5 shells.
Concept: Addition — combining two groups.
4+5=94 + 5 = 9
Answer: They have 9 shells altogether.

BRanjeet has 3 marbles and Meenakshi has 6 marbles. How many marbles do they have in total?

Free with a Super Tutor account

CThere are 3 coconuts in one bag. There are 4 coconuts in another bag. How many coconuts are there in all?

Free with a Super Tutor account

Let us See What We Have in Our Bags

AI have ___ books in my bag and my friend has ___ books. We both have ___ books in all.

Free with a Super Tutor account

BI have ___ pencils and my friend has ___ pencils. We have ___ pencils altogether.

Free with a Super Tutor account

CI have ___ notebooks and my friend has ___ notebooks. We have ___ notebooks in total.

Free with a Super Tutor account

Think and Do

1Write the numbers 1, 2 and 3 in the given table in a way as shown by the dotted lines so that each way adds up to 6.

Free with a Super Tutor account

Let us Talk — Five Little Children (Poem)

AHow many children are there in the bus at the beginning?

Free with a Super Tutor account

BHow many children get down from the bus on the first stand?

Free with a Super Tutor account

CHow many children are left in the bus after the first stop?

Free with a Super Tutor account

DHow many children are left after the second stand? Answer the same for third, fourth and fifth stand.

Free with a Super Tutor account

EHow many children are left in the bus at the end?

Free with a Super Tutor account

Fill in the Blanks (Section A)

i6 frogs, 2 jumped away. 6−2=6 - 2 = ___ left.

Free with a Super Tutor account

ii7 balloons, ___ flew away. 7−2=7 - 2 = 5 left. How many flew away?

Free with a Super Tutor account

iii9 bananas, 6 took away. 9−6=9 - 6 = ___ left.

Free with a Super Tutor account

Draw and Fill in the Blanks (Section B)

iSome pots, 1 pot broke. 3−3 - ___ == ___ left. (Draw the pots that are left.)

Free with a Super Tutor account

ii7 ladoos, 4 eaten. 7−4=7 - 4 = ___ left. (Draw the ladoos that are left.)

Free with a Super Tutor account

iii7 balls, some took away, some left. 7−7 - ___ == ___ left. (Draw the balls that are left.)

Free with a Super Tutor account

Word Problems (Section C)

iManisha has 9 bananas. She ate 3 bananas. How many bananas are left?

Free with a Super Tutor account

iiThere are 8 butterflies on the flowers. 5 butterflies flew away. How many butterflies are left?

Free with a Super Tutor account

How Many Dots Are Hidden and How Many Are Visible?

1Make your own ten dots card and hide a few dots. Fill in the table: Total Dots = 10, find Hidden Dots and Visible Dots.

Free with a Super Tutor account

Hop Backwards on the Number Strip

AJump 3 steps back from 9. 9−3=69 - 3 = 6

Free with a Super Tutor account

BJump 4 steps back from 7. 7−4=7 - 4 =

Free with a Super Tutor account

Do the Subtraction in Your Own Way

A8−2=8 - 2 =

Free with a Super Tutor account

B7−3=7 - 3 =

Free with a Super Tutor account

C9−5=9 - 5 =

Free with a Super Tutor account

D6−3=6 - 3 =

Free with a Super Tutor account

E5−1=5 - 1 =

Free with a Super Tutor account

F4−2=4 - 2 =

Free with a Super Tutor account

28 more solved questions in How Many? (Addition and Subtraction of Single Digit Numbers)

They are free with a Super Tutor account, along with practice quizzes and flashcards for this chapter. Free to start, no card needed.

Frequently Asked Questions

What are the important topics in How Many? (Addition and Subtraction of Single Digit Numbers) for CBSE Class 1 Mathematics?
Key topics in How Many? (Addition and Subtraction of Single Digit Numbers) include Addition: Join Two Groups, Addition Games and Number Pairs, Addition Story Problems, Subtraction: Take Away and Find What Is Left. Study these first, then practise questions on each for Class 1 exams.
Are these NCERT Solutions for How Many? (Addition and Subtraction of Single Digit Numbers) free?
The first 29 of the 57 solutions on this page are open to read. The other 28 are free with a Super Tutor account — signing up is free and needs no card.
How should I revise How Many? (Addition and Subtraction of Single Digit Numbers) for Class 1 exams?
Learn the core ideas first, then work through the 45 practice questions on How Many? (Addition and Subtraction of Single Digit Numbers). Revise definitions regularly and use flashcards for quick recall before the exam.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.

For serious students

Get the full How Many? (Addition and Subtraction of Single Digit Numbers) chapter — start free.

Quizzes, flashcards, an AI doubt solver and a study plan for CBSE Class 1 Mathematics. Free to start, no card needed.