How Many? (Addition and Subtraction of Single Digit Numbers)

Given: 4 children and 2 more children join them.
Concept: Addition means putting two groups together to find the total.
$$4 + 2 = 6$$
Answer: 4 children and 2 children altogether make 6 children.

Given: 3 tops and 1 more top.
Concept: Addition — combining two groups.
$$3 + 1 = 4$$
Answer: 3 tops and 1 top altogether make 4 tops.

Given: 3 ants and 2 more ants.
Concept: Addition — combining two groups.
$$3 + 2 = 5$$
Answer: 3 ants and 2 ants altogether make 5 ants.

Given: 4 pencils and 3 more pencils.
Concept: Addition — combining two groups.
$$4 + 3 = 7$$
Answer: 4 pencils and 3 pencils altogether make 7 pencils.

Given: 6 balls and 2 more balls.
Concept: Addition — combining two groups.
$$6 + 2 = 8$$
Answer: 6 balls and 2 balls altogether make 8 balls.
(Draw 8 balls in total in the space provided.)

Given: 7 and 1.
Concept: Addition.
$$7 + 1 = 8$$
Answer: 8
(Draw 8 objects in the space provided.)

This is an activity-based question. Count the number of brothers and sisters your mother has, then count the number of brothers and sisters your father has, and add both numbers together.
For example, if your mother has 2 siblings and your father has 3 siblings:
$$2 + 3 = 5$$
Answer will vary for each child.

This is an activity-based question. Count the total members in your family, then count the total members in your friend's family, and add both numbers.
For example, if you have 4 family members and your friend has 5:
$$4 + 5 = 9$$
Answer will vary for each child.

Given: Each hand has 5 fingers and each foot has 5 toes.
Both hands: $5 + 5 = 10$ fingers.
Both feet: $5 + 5 = 10$ toes.
Total: $10 + 10 = 20$
Answer: You have 20 fingers and toes altogether.

Given: We have 10 fingers in total (5 on each hand).
We can count from 1 to 10 using our fingers.
Answer: We can count 10 numbers on our fingers.

Each hand has 5 fingers.
Two hands together: $5 + 5 = 10$
Answer: The total number of fingers on two hands is 10.
(Note: The exact images are not visible, but the standard activity involves counting fingers on one or two hands and writing the total. Children should count the fingers shown and write the sum.)

Round A: Kishore's score is already marked with ✓, meaning Kishore rolled a higher total than Nitya in Round A.
(Since the dice images are not visible, the answer is based on the given information that Kishore won Round A.)
Answer: Kishore ✓ in Round A.

Note: The dice images for Round B are not visible in the text. Children should add the dots on each player's two dice, compare the totals, and place ✓ under the player with the higher total.
Method: Add dots on Kishore's two dice → total K. Add dots on Nitya's two dice → total N. If K > N, tick Kishore; if N > K, tick Nitya.

Note: The dice images for Round C are not visible in the text. Children should add the dots on each player's two dice, compare the totals, and place ✓ under the player with the higher total.

Note: The dice images for Round D are not visible in the text. Children should add the dots on each player's two dice, compare the totals, and place ✓ under the player with the higher total.

Note: The dice images for Round E are not visible in the text. Children should add the dots on each player's two dice, compare the totals, and place ✓ under the player with the higher total.

Given: 3 beads of one colour and 4 beads of another colour.
Concept: Addition.
$$3 + 4 = 7$$
Answer: 7 coloured beads in total.
(Colour 3 beads in one colour and 4 beads in another colour on the string.)

Given: 4 beads of one colour and 2 beads of another colour.
$$4 + 2 = 6$$
Answer: 6 coloured beads in total.

Given: 5 beads of one colour and 4 beads of another colour.
$$5 + 4 = 9$$
Answer: 9 coloured beads in total.

Given: 2 beads of one colour and 7 beads of another colour.
$$2 + 7 = 9$$
Answer: 9 coloured beads in total.

Given: 7 beads of one colour and 3 beads of another colour.
$$7 + 3 = 10$$
Answer: 10 coloured beads in total.

Given: 2 and 3.
Method 1 (Counting on): Start from 2, count 3 more → 3, 4, 5.
Method 2 (Fingers): Hold up 2 fingers, then 3 more fingers, count all = 5.
$$2 + 3 = 5$$
Answer: 5

Given: 5 and 1.
Start from 5, count 1 more → 6.
$$5 + 1 = 6$$
Answer: 6

Given: 3 and 3.
Start from 3, count 3 more → 4, 5, 6.
$$3 + 3 = 6$$
Answer: 6

Given: 9 and 1.
Start from 9, count 1 more → 10.
$$9 + 1 = 10$$
Answer: 10

This is an activity based on a number wheel (like the Konark Sun Chariot wheel). Children fill in pairs of numbers that add up to the number in the centre.
For example, if the centre number is 5, the pairs are:
$0+5=5,\ 1+4=5,\ 2+3=5,\ 3+2=5,\ 4+1=5,\ 5+0=5$
(The exact centre number is not visible; children should fill pairs accordingly.)

Step 1: Solve the left column.
$$1+4=5$$
$$6+3=9$$
$$5+2=7$$
$$0+6=6$$

Step 2: Solve the right column.
$$4+2=6$$
$$3+4=7$$
$$3+2=5$$
$$5+4=9$$

Step 3: Match both sides through the middle number.
- $1+4=5$ matches with $3+2=5$ (through 5)
- $6+3=9$ matches with $5+4=9$ (through 9)
- $5+2=7$ matches with $3+4=7$ (through 7)
- $0+6=6$ matches with $4+2=6$ (through 6)

Answer:
$1+4 \longleftrightarrow 5 \longleftrightarrow 3+2$
$6+3 \longleftrightarrow 9 \longleftrightarrow 5+4$
$5+2 \longleftrightarrow 7 \longleftrightarrow 3+4$
$0+6 \longleftrightarrow 6 \longleftrightarrow 4+2$

Given: Cards numbered 0 to 9. Find pairs that add up to 9.
Concept: Addition pairs.
$$0 + 9 = 9$$
$$1 + 8 = 9$$
$$2 + 7 = 9$$
$$3 + 6 = 9$$
$$4 + 5 = 9$$
$$5 + 4 = 9$$
$$6 + 3 = 9$$
$$7 + 2 = 9$$
$$8 + 1 = 9$$
$$9 + 0 = 9$$
Answer: There are 10 ways to make 9 using two cards from 0–9 (including reversed pairs). If we count only unique pairs (where order does not matter), there are 5 ways: $(0,9),\ (1,8),\ (2,7),\ (3,6),\ (4,5)$.

Given: Raghav has 4 shells. Sarita has 5 shells.
Concept: Addition — combining two groups.
$$4 + 5 = 9$$
Answer: They have 9 shells altogether.

Given: Ranjeet has 3 marbles. Meenakshi has 6 marbles.
Concept: Addition.
$$3 + 6 = 9$$
Answer: They have 9 marbles in total.

Given: First bag has 3 coconuts. Second bag has 4 coconuts.
Concept: Addition.
$$3 + 4 = 7$$
Answer: There are 7 coconuts in all.

This is an activity-based question. Count the books in your bag and your friend's bag, then add.
For example: I have 3 books, my friend has 4 books.
$$3 + 4 = 7$$
We both have 7 books in all.
(Answer will vary for each child.)

This is an activity-based question.
For example: I have 2 pencils, my friend has 5 pencils.
$$2 + 5 = 7$$
We have 7 pencils altogether.
(Answer will vary for each child.)

This is an activity-based question.
For example: I have 1 notebook, my friend has 3 notebooks.
$$1 + 3 = 4$$
We have 4 notebooks in total.
(Answer will vary for each child.)

Given: Numbers 1, 2, and 3 are to be placed so that each row/column/diagonal adds up to 6.
Concept: Each path must use 1, 2, and 3 (each used twice in a path of three cells) to sum to 6.
Since $1 + 2 + 3 = 6$, any arrangement of 1, 2, 3 in a row, column, or diagonal will add up to 6.
One possible arrangement in a 3-cell strip:
$$1 + 2 + 3 = 6$$
$$2 + 1 + 3 = 6$$
$$3 + 2 + 1 = 6$$
Answer: Place 1, 2, 3 in any order in the three cells — the sum will always be 6.

Given: The poem starts with 'Five little children'.
Answer: There are 5 children in the bus at the beginning.

From the poem: 'One steps out, with a roar — Now, we are four!'
Answer: 1 child gets down at the first stand.

Given: Started with 5 children, 1 got down.
$$5 - 1 = 4$$
Answer: 4 children are left after the first stop.

Start: 5 children.
After 1st stand: $5 - 1 = 4$ children left.
After 2nd stand: $4 - 1 = 3$ children left.
After 3rd stand: $3 - 1 = 2$ children left.
After 4th stand: $2 - 1 = 1$ child left.
After 5th stand: $1 - 1 = 0$ children left.
Answer: After 2nd stand → 3, after 3rd stand → 2, after 4th stand → 1, after 5th stand → 0.

From the poem: 'Last steps out, having much fun — Now, there are none!'
$$1 - 1 = 0$$
Answer: 0 (no) children are left in the bus at the end.

Given: 6 frogs. 2 frogs jumped away.
Concept: Subtraction — taking away from a group.
$$6 - 2 = 4$$
Answer: 4 frogs are left.

Given: 7 balloons. 5 are left.
Concept: Subtraction.
$$7 - 2 = 5$$
So 2 balloons flew away.
Answer: 2 balloons flew away.

Given: 9 bananas. 6 were taken away.
Concept: Subtraction.
$$9 - 6 = 3$$
Answer: 3 bananas are left.

Given: 3 pots total. 1 pot broke.
Concept: Subtraction.
$$3 - 1 = 2$$
Answer: 2 pots are left.
(Draw 2 unbroken pots in the space provided.)

Given: 7 ladoos. 4 were eaten.
Concept: Subtraction.
$$7 - 4 = 3$$
Answer: 3 ladoos are left.
(Draw 3 ladoos in the space provided.)

Given: 7 balls total. (The number taken away is shown in the image which is not visible.)
Concept: Subtraction.
For example, if 3 balls were taken away:
$$7 - 3 = 4$$
Answer: The number left depends on how many were taken away. Children should count the balls taken away from the picture and subtract from 7 to find the remaining balls.

Given: Manisha has 9 bananas. She ate 3 bananas.
Concept: Subtraction — taking away.
$$9 - 3 = 6$$
Answer: 6 bananas are left.

Given: 8 butterflies. 5 flew away.
Concept: Subtraction.
$$8 - 5 = 3$$
Answer: 3 butterflies are left.

Given: Total dots = 10.
Concept: A number and its complement always add up to 10.
All possible combinations:
$$0 + 10 = 10 \Rightarrow \text{Hidden: 0, Visible: 10}$$
$$1 + 9 = 10 \Rightarrow \text{Hidden: 1, Visible: 9}$$
$$2 + 8 = 10 \Rightarrow \text{Hidden: 2, Visible: 8}$$
$$3 + 7 = 10 \Rightarrow \text{Hidden: 3, Visible: 7}$$
$$4 + 6 = 10 \Rightarrow \text{Hidden: 4, Visible: 6}$$
$$5 + 5 = 10 \Rightarrow \text{Hidden: 5, Visible: 5}$$
$$6 + 4 = 10 \Rightarrow \text{Hidden: 6, Visible: 4}$$
$$7 + 3 = 10 \Rightarrow \text{Hidden: 7, Visible: 3}$$
$$8 + 2 = 10 \Rightarrow \text{Hidden: 8, Visible: 2}$$
$$9 + 1 = 10 \Rightarrow \text{Hidden: 9, Visible: 1}$$
$$10 + 0 = 10 \Rightarrow \text{Hidden: 10, Visible: 0}$$
Answer: Fill the table with the pairs above. The pattern is: Hidden Dots + Visible Dots = 10 always.

Given: Start at 9, jump 3 steps back.
Concept: Subtraction on a number line — move left.
Start at 9 → jump to 8 (1 step) → 7 (2 steps) → 6 (3 steps).
$$9 - 3 = 6$$
Answer: 6

Given: Start at 7, jump 4 steps back.
Concept: Subtraction on a number line — move left.
Start at 7 → 6 (1 step) → 5 (2 steps) → 4 (3 steps) → 3 (4 steps).
$$7 - 4 = 3$$
Answer: 3

Given: 8 take away 2.
Count back 2 from 8: 8 → 7 → 6.
$$8 - 2 = 6$$
Answer: 6

Given: 7 take away 3.
Count back 3 from 7: 7 → 6 → 5 → 4.
$$7 - 3 = 4$$
Answer: 4

Given: 9 take away 5.
Count back 5 from 9: 9 → 8 → 7 → 6 → 5 → 4.
$$9 - 5 = 4$$
Answer: 4

Given: 6 take away 3.
Count back 3 from 6: 6 → 5 → 4 → 3.
$$6 - 3 = 3$$
Answer: 3

Given: 5 take away 1.
Count back 1 from 5: 5 → 4.
$$5 - 1 = 4$$
Answer: 4

Given: 4 take away 2.
Count back 2 from 4: 4 → 3 → 2.
$$4 - 2 = 2$$
Answer: 2