Vegetable Farm (Addition and Subtraction up to 20) — NCERT Solutions

Given: Aman has 8 laddoos. Charanjeet has 6 laddoos.

Concept: Addition – finding the total.

Method 1 (Counting on): Start at 8, count 6 more: 9, 10, 11, 12, 13, 14.

Method 2 (Breaking numbers):
$$8 + 6 = 8 + 2 + 4 = 10 + 4 = 14$$

$$8 + 6 = \boxed{14}$$

Answer: There are 14 laddoos in all.

Given: Sheena has 12 bangles. She got 6 more.

Concept: Addition – finding the new total.

Method 1 (Counting on): Start at 12, count 6 more: 13, 14, 15, 16, 17, 18.

Method 2 (Breaking numbers):
$$12 + 6 = 10 + 2 + 6 = 10 + 8 = 18$$

$$12 + 6 = \boxed{18}$$

Answer: Sheena has 18 bangles now.

Given: $15 - 9$

Working: Start at 15 on the number line, hop 9 steps back: 14, 13, 12, 11, 10, 9, 8, 7, 6.

$$15 - 9 = \boxed{6}$$

Note: The figures for problems A–H are not visible in the OCR. These are subtraction problems up to 20 based on pictures.

General method for any subtraction $a - b$:

Step 1: Start at $a$ on the number line.
Step 2: Hop $b$ steps backward.
Step 3: The number you land on is the answer.

Example: $14 - 6$: Start at 14, hop 6 back → land on 8.
$$14 - 6 = \boxed{8}$$

Students should apply the same hopping-back strategy to the picture-based problems A through H in their textbook.

Given: Start at 6, jump 2 steps forward.

Working: $6 + 2 = 8$

Answer: Anjali reaches 8.

Given: Start at 15, jump 7 steps backward.

Working: $15 - 7 = 8$

Answer: Renu also reaches 8.

Conclusion: Both Anjali and Renu reach the same place — 8. This shows that $6 + 2 = 15 - 7 = 8$.

Given:

• Diyas the potter had = 9
• Diyas sold = 5
• Diyas made again = 7

Step 1: Diyas left after selling:
$$9 - 5 = 4$$

Step 2: Diyas after making 7 more:
$$4 + 7 = 11$$

Answer: The potter has $\boxed{11}$ diyas now.

Given:

• Children at first stop = 6
• Children who board at second stop = 8
• Children who get down at third stop = 7

Step 1: Children in bus after second stop:
$$6 + 8 = 14$$

Step 2: Children in bus after third stop:
$$14 - 7 = 7$$

Answer: There are $\boxed{7}$ children in the bus at the third stop.

Given:

• Total seats in bus = 18
• Children already sitting = 9

Concept: Subtraction – finding how many more can fit.

Working:
$$18 - 9 = 9$$

Answer: $\boxed{9}$ more children can sit inside the bus.

Given:

• Toffees Kuljeet had = 14
• Toffees left = 6

Concept: Subtraction – finding how many were given away.

Working:
$$14 - 6 = 8$$

Answer: Kuljeet shared $\boxed{8}$ toffees with her friends.

Given:

• Bananas Raman had = 12
• Bananas left = 5

Concept: Subtraction – finding how many were eaten.

Working:
$$12 - 5 = 7$$

Answer: Raman ate $\boxed{7}$ bananas.