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Kinetic Theory — Flashcards

CBSE · Class 11 · Physics

60 flashcards for Kinetic Theory (CBSE Class 11 Physics) to test yourself on key terms and facts. Sample: "State Boyle's law for a fixed mass of gas"

144 questions60 flashcards15 formulas & key relations5 concepts

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60 Flashcards·
Gas lawsIdeal gas equation
Card 1Gas laws

State Boyle's law for a fixed mass of gas at constant temperature.

Answer

For a fixed mass of gas at constant temperature, pressure varies inversely with volume. Formula: PV = constant. If volume decreases, pressure increases so that PV stays constant. Units: P in pascal, V…

Card 2Gas laws

स्थिर तापमान पर गैस के नियत द्रव्यमान के लिए बॉयल का नियम बताइए।

Answer

स्थिर तापमान पर गैस के नियत द्रव्यमान के लिए, दाब आयतन के व्युत्क्रमानुपाती होता है। सूत्र: PV = constant. यदि आयतन घटता है, तो दाब बढ़ता है ताकि PV स्थिर रहे। इकाइयाँ: P पास्कल में, V घन मीटर में।…

Card 3Gas laws

चार्ल्स का नियम बताइए।

Answer

नियत दाब पर, किसी गैस का आयतन उसके परम ताप T के समानुपाती होता है। सूत्र: V ∝ T. यदि T दोगुना हो जाता है, तो V भी दोगुना हो जाता है। तापमान केल्विन में होना चाहिए।…

Card 4Gas laws

State Charles' law.

Answer

For a fixed pressure, the volume of a gas is proportional to its absolute temperature T. Formula: V ∝ T. If T doubles, V also doubles. Temperature must be in kelvin.

Card 5Gas laws

State Avogadro's law.

Answer

Equal volumes of all gases at equal temperature and pressure have the same number of molecules. This is why one mole of any ideal gas occupies the same volume at STP.

Card 6Gas laws

अवोगाद्रो का नियम बताइए।

Answer

समान तापमान और दाब पर सभी गैसों के समान आयतन में अणुओं की संख्या समान होती है। यही कारण है कि किसी भी आदर्श गैस का 1 मोल STP पर समान आयतन घेरता है।…

Card 7Ideal gas equation

एक गैस नमूने का दाब 1.0 × 10^5 Pa, आयतन 2.0 × 10^-3 m^3, और तापमान 300 K है। यदि गैस की मात्रा 0.08 mol है, तो आदर्श गैस समीकरण में प्रयुक्त गैस स्थिरांक का मान ज्ञात कीजिए।

Answer

दिया है: P = 1.0 × 10^5 Pa, V = 2.0 × 10^-3 m^3, T = 300 K, μ = 0.08 mol सूत्र: PV = μRT चरण 1: PV = (1.0 × 10^5)(2.0 × 10^-3) = 200 J चरण 2: μT = 0.08 × 300 = 24 mol K चरण 3: R = PV / (μT) = 200 / 24…

Card 8Ideal gas equation

A gas sample has pressure 1.0 × 10^5 Pa, volume 2.0 × 10^-3 m^3, and temperature 300 K. If the amount of gas is 0.08 mol, find the gas constant value used by the ideal gas equation.

Answer

Given: P = 1.0 × 10^5 Pa, V = 2.0 × 10^-3 m^3, T = 300 K, μ = 0.08 mol Formula: PV = μRT Step 1: PV = (1.0 × 10^5)(2.0 × 10^-3) = 200 J Step 2: μT = 0.08 × 300 = 24 mol K Step 3: R = PV / (μT) = 200 /…

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Frequently Asked Questions

What are the important topics in Kinetic Theory for CBSE Class 11 Physics?
Key topics in Kinetic Theory include Matter is made of atoms, An ideal gas satisfies PV =, Pressure arises from elastic collisions, The average kinetic energy per molecule. Study these first, then practise questions on each for Class 11 exams.
How many flashcards are available for Kinetic Theory?
There are 60 flashcards for Kinetic Theory covering key definitions, facts and ideas. A few sample cards are shown on this page.
How should I revise Kinetic Theory for Class 11 exams?
Learn the core ideas first, then work through the 144 practice questions on Kinetic Theory. Revise definitions regularly and use flashcards for quick recall before the exam.

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