Work, Energy and Power — Flashcards
CBSE · Class 11 · Physics
70 flashcards for Work, Energy and Power (CBSE Class 11 Physics) to test yourself on key terms and facts. Sample: "State the scalar (dot) product of two"
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State the scalar (dot) product of two vectors.
Answer
Formula: A · B = AB cos θ. It gives a scalar, not a vector. Here A and B are the magnitudes of the vectors and θ is the angle between them. If θ = 0°, the product is maximum; if θ = 90°, the product i…
दो सदिशों का अदिश (डॉट) गुणनफल बताइए।
Answer
सूत्र: A · B = AB cos θ. यह एक अदिश देता है, सदिश नहीं। यहाँ A और B सदिशों के परिमाण हैं और θ उनके बीच का कोण है। यदि θ = 0° हो, तो गुणनफल अधिकतम होता है; यदि θ = 90° हो, तो गुणनफल शून्य होता है।…
10 N का एक बल किसी पिंड पर कार्य करता है और विस्थापन उसी दिशा में 2 m है। किया गया कार्य ज्ञात कीजिए।
Answer
दिया है: F = 10 N, d = 2 m, θ = 0°. सूत्र: W = Fd cos θ. चरण 1: W = 10 × 2 × cos 0°. चरण 2: W = 20 × 1 = 20 J. उत्तर: 20 J.
A force of 10 N acts on a body and the displacement is 2 m in the same direction. Find the work done.
Answer
Given: F = 10 N, d = 2 m, θ = 0°. Formula: W = Fd cos θ. Step 1: W = 10 × 2 × cos 0°. Step 2: W = 20 × 1 = 20 J. Answer: 20 J.
Why is no work done when a person pushes a rigid wall?
Answer
Work needs force and displacement. A rigid wall does not move, so displacement is zero. Therefore work done on the wall is zero, even if the force is large. Muscles may still use internal energy, so t…
जब कोई व्यक्ति एक कठोर दीवार को धक्का देता है, तो कोई कार्य क्यों नहीं होता?
Answer
कार्य के लिए बल और विस्थापन दोनों चाहिए। एक कठोर दीवार नहीं हिलती, इसलिए विस्थापन शून्य है। इसलिए दीवार पर किया गया कार्य शून्य है, चाहे बल कितना भी बड़ा हो। मांसपेशियाँ फिर भी आंतरिक ऊर्जा का उपयोग क…
एक भारोत्तोलक 150 kg द्रव्यमान को 30 s तक कंधे पर स्थिर रखता है। भार पर कितना कार्य होता है?
Answer
भार का विस्थापन = 0 m. सूत्र: W = Fd cos θ. चरण 1: d = 0 m. चरण 2: W = कोई भी बल × 0 = 0 J. उत्तर: 0 J.
A weightlifter holds a 150 kg mass steadily on the shoulder for 30 s. How much work is done on the load?
Answer
Displacement of the load = 0 m. Formula: W = Fd cos θ. Step 1: d = 0 m. Step 2: W = any force × 0 = 0 J. Answer: 0 J.
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- CBSE Academic — cbseacademic.nic.in
- CBSE Official — cbse.gov.in
- National Education Policy 2020 — education.gov.in
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