Work, Energy and Power
CBSE · Class 11 · Physics
Flashcards for Work, Energy and Power — CBSE Class 11 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.
Interactive on Super Tutor
Studying Work, Energy and Power? Get the full interactive chapter.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for flashcards and more.
1,000+ Class 11 students started this chapter today
State the scalar (dot) product of two vectors.
Answer
Formula: A · B = AB cos θ. It gives a scalar, not a vector. Here A and B are the magnitudes of the vectors and θ is the angle between them. If θ = 0°, the product is maximum; if θ = 90°, the product i…
दो सदिशों का अदिश (डॉट) गुणनफल बताइए।
Answer
सूत्र: A · B = AB cos θ. यह एक अदिश देता है, सदिश नहीं। यहाँ A और B सदिशों के परिमाण हैं और θ उनके बीच का कोण है। यदि θ = 0° हो, तो गुणनफल अधिकतम होता है; यदि θ = 90° हो, तो गुणनफल शून्य होता है।…
10 N का एक बल किसी पिंड पर कार्य करता है और विस्थापन उसी दिशा में 2 m है। किया गया कार्य ज्ञात कीजिए।
Answer
दिया है: F = 10 N, d = 2 m, θ = 0°. सूत्र: W = Fd cos θ. चरण 1: W = 10 × 2 × cos 0°. चरण 2: W = 20 × 1 = 20 J. उत्तर: 20 J.
A force of 10 N acts on a body and the displacement is 2 m in the same direction. Find the work done.
Answer
Given: F = 10 N, d = 2 m, θ = 0°. Formula: W = Fd cos θ. Step 1: W = 10 × 2 × cos 0°. Step 2: W = 20 × 1 = 20 J. Answer: 20 J.
Why is no work done when a person pushes a rigid wall?
Answer
Work needs force and displacement. A rigid wall does not move, so displacement is zero. Therefore work done on the wall is zero, even if the force is large. Muscles may still use internal energy, so t…
जब कोई व्यक्ति एक कठोर दीवार को धक्का देता है, तो कोई कार्य क्यों नहीं होता?
Answer
कार्य के लिए बल और विस्थापन दोनों चाहिए। एक कठोर दीवार नहीं हिलती, इसलिए विस्थापन शून्य है। इसलिए दीवार पर किया गया कार्य शून्य है, चाहे बल कितना भी बड़ा हो। मांसपेशियाँ फिर भी आंतरिक ऊर्जा का उपयोग क…
एक भारोत्तोलक 150 kg द्रव्यमान को 30 s तक कंधे पर स्थिर रखता है। भार पर कितना कार्य होता है?
Answer
भार का विस्थापन = 0 m. सूत्र: W = Fd cos θ. चरण 1: d = 0 m. चरण 2: W = कोई भी बल × 0 = 0 J. उत्तर: 0 J.
A weightlifter holds a 150 kg mass steadily on the shoulder for 30 s. How much work is done on the load?
Answer
Displacement of the load = 0 m. Formula: W = Fd cos θ. Step 1: d = 0 m. Step 2: W = any force × 0 = 0 J. Answer: 0 J.
+62 more flashcards available
Practice AllFrequently Asked Questions
What are the important topics in Work, Energy and Power for CBSE Class 11 Physics?
How to score full marks in Work, Energy and Power — CBSE Class 11 Physics?
How many flashcards are available for Work, Energy and Power?
Sources & Official References
- NCERT Official — ncert.nic.in
- CBSE Academic — cbseacademic.nic.in
- CBSE Official — cbse.gov.in
- National Education Policy 2020 — education.gov.in
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
More resources for Work, Energy and Power
Practice Quiz
Test yourself with a quick quiz
Important Questions
Practice with board exam-style questions
Revision Notes
Key points for last-minute revision
Formula Sheet
All formulas in one place
Chapter Summary
Understand the chapter at a glance
Concept Maps
See how topics connect visually
Study Plan
Step-by-step plan to ace this chapter
Syllabus
What topics to cover
NCERT Solutions
Every textbook question solved step by step
For serious students
Get the full Work, Energy and Power chapter — for free.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan for CBSE Class 11 Physics.