Mechanical Properties of Fluids — Flashcards
CBSE · Class 11 · Physics
64 flashcards for Mechanical Properties of Fluids (CBSE Class 11 Physics) to test yourself on key terms and facts.
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द्रवों को ठोसों से अलग करने वाला मूल गुण बताइए।
Answer
एक द्रव बह सकता है। द्रव और गैसों को द्रव कहा जाता है क्योंकि उनका अपना निश्चित आकार नहीं होता और वे पात्र का आकार ले लेते हैं।…
State the basic property that distinguishes fluids from solids.
Answer
A fluid can flow. Liquids and gases are called fluids because they do not have a fixed shape of their own and take the shape of the container.
Why do gases fill the entire container while liquids do not?
Answer
Gases are highly compressible and expand to occupy all available space. Liquids are largely incompressible, so they keep a nearly fixed volume and form a free surface.
गैसें पूरे पात्र को क्यों भर देती हैं जबकि द्रव नहीं भरते?
Answer
गैसें बहुत अधिक संपीड्य होती हैं और उपलब्ध सभी स्थान को भरने के लिए फैलती हैं। द्रव लगभग असंपीड्य होते हैं, इसलिए वे लगभग निश्चित आयतन बनाए रखते हैं और एक मुक्त पृष्ठ बनाते हैं।…
औसत दाब का सूत्र बताइए और संकेतों को समझाइए।
Answer
सूत्र: P_av = F/A यहाँ F अभिलंब बल है और A क्षेत्रफल है। इकाई: N m^-2 या Pa. अर्थ: जब वही बल छोटे क्षेत्रफल पर कार्य करता है, तो दाब बढ़ जाता है।…
State the formula for average pressure and explain the symbols.
Answer
Formula: P_av = F/A Here F is the normal force and A is the area. Unit: N m^-2 or Pa. Meaning: pressure increases when the same force acts on a smaller area.
A force of 400 N acts normally on an area of 20 cm². Find the average pressure.
Answer
Given: F = 400 N, A = 20 cm² = 20 x 10^-4 m² = 2.0 x 10^-3 m² Formula: P_av = F/A Step 1: P_av = 400 N / (2.0 x 10^-3 m²) Step 2: P_av = 2.0 x 10^5 N m^-2 Answer: 2.0 x 10^5 Pa…
400 N का बल 20 cm² के क्षेत्रफल पर अभिलंब रूप से कार्य करता है। औसत दाब ज्ञात कीजिए।
Answer
दिया है: F = 400 N, A = 20 cm² = 20 x 10^-4 m² = 2.0 x 10^-3 m² सूत्र: P_av = F/A चरण 1: P_av = 400 N / (2.0 x 10^-3 m²) चरण 2: P_av = 2.0 x 10^5 N m^-2 उत्तर: 2.0 x 10^5 Pa…
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