Mechanical Properties of Solids
CBSE · Class 11 · Physics
Flashcards for Mechanical Properties of Solids — CBSE Class 11 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.
Interactive on Super Tutor
Studying Mechanical Properties of Solids? Get the full interactive chapter.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for flashcards and more.
1,000+ Class 11 students started this chapter today
तनाव की परिभाषा और इसकी SI इकाई बताइए।
Answer
तनाव वह प्रति इकाई क्षेत्रफल पुनर्स्थापी बल है जो किसी पिंड में बाहरी बल से विकृत होने पर उत्पन्न होता है। सूत्र: stress = F/A. SI इकाई: N/m^2 या pascal (Pa). विमीय सूत्र: [ML^-1T^-2].
State the definition of stress and its SI unit.
Answer
Stress is the restoring force per unit area developed in a body when it is deformed by an external force. Formula: stress = F/A. SI unit: N/m^2 or pascal (Pa). Dimensional formula: [ML^-1T^-2].
State the definition of strain and why it has no unit.
Answer
Strain is the fractional change in dimension of a body under stress. For length change, longitudinal strain = ΔL/L. Since it is a ratio of two lengths, it has no units and no dimensional formula.
विकृति की परिभाषा बताइए और इसका कोई इकाई क्यों नहीं होती।
Answer
विकृति तनाव के अधीन किसी पिंड के आयाम में होने वाला भिन्नात्मक परिवर्तन है। लंबाई परिवर्तन के लिए, अनुदैर्ध्य विकृति = ΔL/L. क्योंकि यह दो लंबाइयों का अनुपात है, इसकी कोई इकाई और कोई विमीय सूत्र नहीं …
500 N का बल 0.25 m^2 के क्षेत्रफल पर लम्बवत्作用 करता है। तनाव ज्ञात कीजिए।
Answer
दिया है: F = 500 N, A = 0.25 m^2. सूत्र: stress = F/A. चरण 1: stress = 500 N / 0.25 m^2. चरण 2: stress = 2000 N m^-2. उत्तर: 2.0 × 10^3 Pa.
A force of 500 N acts normally on an area of 0.25 m^2. Find the stress.
Answer
Given: F = 500 N, A = 0.25 m^2. Formula: stress = F/A. Step 1: stress = 500 N / 0.25 m^2. Step 2: stress = 2000 N m^-2. Answer: 2.0 × 10^3 Pa.
A wire of original length 2.0 m extends by 1.0 mm. Find the longitudinal strain.
Answer
Given: L = 2.0 m, ΔL = 1.0 mm = 1.0 × 10^-3 m. Formula: longitudinal strain = ΔL/L. Step 1: strain = (1.0 × 10^-3 m)/(2.0 m). Step 2: strain = 5.0 × 10^-4. Answer: 5.0 × 10^-4, no unit.
2.0 m लंबाई वाली एक तार 1.0 mm बढ़ती है। अनुदैर्ध्य विकृति ज्ञात कीजिए।
Answer
दिया है: L = 2.0 m, ΔL = 1.0 mm = 1.0 × 10^-3 m. सूत्र: longitudinal strain = ΔL/L. चरण 1: strain = (1.0 × 10^-3 m)/(2.0 m). चरण 2: strain = 5.0 × 10^-4. उत्तर: 5.0 × 10^-4, कोई इकाई नहीं।…
+56 more flashcards available
Practice AllFrequently Asked Questions
What are the important topics in Mechanical Properties of Solids for CBSE Class 11 Physics?
How to score full marks in Mechanical Properties of Solids — CBSE Class 11 Physics?
How many flashcards are available for Mechanical Properties of Solids?
Sources & Official References
- NCERT Official — ncert.nic.in
- CBSE Academic — cbseacademic.nic.in
- CBSE Official — cbse.gov.in
- National Education Policy 2020 — education.gov.in
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
More resources for Mechanical Properties of Solids
Practice Quiz
Test yourself with a quick quiz
Important Questions
Practice with board exam-style questions
Revision Notes
Key points for last-minute revision
Formula Sheet
All formulas in one place
Chapter Summary
Understand the chapter at a glance
Concept Maps
See how topics connect visually
Study Plan
Step-by-step plan to ace this chapter
Syllabus
What topics to cover
NCERT Solutions
Every textbook question solved step by step
For serious students
Get the full Mechanical Properties of Solids chapter — for free.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan for CBSE Class 11 Physics.